2. B -field of a rotating charged conducting sphere Question: Calculate B -field in arbitrary points on the axis of rotation inside and outside the sphere Available: A charged conducting sphere (charge Q, radius R ), rotating with rad/sec
3. Analysis and Symmetry (1) Calculate B -field in point P inside or outside the sphere P P O Assume Z-axis through O and P. z P Z Y X Coordinate systems: - X,Y, Z r - r,
4. Analysis and Symmetry (2) Conducting sphere , all charges at surface: surface density: Q/( 4 R 2 ) [C/m 2 ] Rotating charges will establish a “surface current” P P z P Y X Z r O Surface current density j’ [A/m] will be a function of j’
5. Analysis and Symmetry (3) dB, dl and e r mutual. perpendic. P z P Y X Z r O T Cylinder- symmetry around Z-axis: dB z Z-components only !! Direction of contributions dB: P O dB T r e r dl Biot & Savart : r P dB
6. Approach (1): a long wire note: r and vector e r !! dB dl and e r dB AOP dB Biot & Savart : Z Y X P z I.dl in dz at z dl e r r P y P A O
7. Approach (2): a volume current dB dl and e r dB AOP j : current density [A/m 2 ] dB Biot & Savart : Z Y P j.dA.dl = j.dv dl e r y P dA j A O r P
8. Approach (3): a surface current dB dl and e r dB AOP dB Biot & Savart : Z Y P dl e r y P dl j’ A O r P Current strip at surface: j’ : current density[A/m] j’.db.dl = j’.dA dl db
9. Approach (4) Conducting sphere, surface density: Q/( 4 R 2 ) surface element: dA = ( R.d R. sin d Z d R d R sin R.d . R. sin d Surface element:
10.
11. Conducting sphere (2) Z R d d R sin R.d R. sin d Full rotation over 2 R sin in 2 s. Charge on ring with radius R. sin and width db is: . 2 R. sin db current: dI = . 2 R. sin db / ( 2 ) = R sin db current density: j’ = R sin [A/m] dA = db.dl dl = R. sin d db= Rd
12. Conducting sphere (3) R d d R sin R.d R. sin d P z P j’ e r r P dA = R.d . R. sin d j’ e r : => | j’ x e r | = j’.e r = j’ j’ = R sin
13. Conducting sphere (4) R d d R sin P z P j’ e r r P dA = Rd R. sin d j’ = R sin Z-components only !! dB z Cylinder- symmetry: P O dB R r P z P e r
14. Conducting sphere (5) R d d R sin P z P j’ e r r P dA = Rd .R. sin d P O dB dB z R r P z P r P 2 = ( R. sin ) 2 + ( z P - R. cos ) 2 j’ = R sin
15. Conducting sphere (6) R d d R sin P z P j’ e r r P with r P 2 = ( R. sin ) 2 + ( z P - R. cos ) 2 Integration: 0< <
16. Conducting sphere (7) this result holds for z P >R ; for -R< z P <R the result is: and for z P <-R : P P z P Y X Z R O
17. Conducting sphere (8) inside sphere: constant field !! P P z P Y X Z r O result for | z P |>R : result for | z P |<R : B directed along + e z for all points everywhere on Z-axis !!
18. Conducting sphere (9) With surface density: Q/ (4 R 2 ) : result for | z P | > R : result for | z P | < R :