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INTRODUCTION TO
GEOMETRY
The Elements
• Knowing that you can’t define everything and
that you can’t prove everything, Euclid began by
stating three undefined terms:
 Point
 (Straight) Line
 Plane (Surface)
Actually, Euclid did attempt to define these basic
terms . . .
is that which has no part
is a line that lies evenly with the points
on itself
is a plane that lies evenly with the
straight lines on itself
Basic Terms & Definitions
• A ray starts at a point (called the endpoint)
and extends indefinitely in one direction.
• A line segment is part of a line and has
two endpoints.
A B AB
BA AB
• An angle is formed by two rays with the
same endpoint.
• An angle is measured in degrees. The
angle formed by a circle has a measure of
360 degrees.
vertex
side
side
• A right angle has a measure of 90
degrees.
• A straight angle has a measure of 180
degrees.
• A simple closed curve is a curve that we
can trace without going over any point
more than once while beginning and
ending at the same point.
• A polygon is a simple closed curve
composed of at least three line segments,
called sides. The point at which two sides
meet is called a vertex.
• A regular polygon is a polygon with sides
of equal length.
Polygons
# of sides name of Polygon
3 triangle
4 quadrilateral
5 pentagon
6 hexagon
7 heptagon
8 octagon
9 nonagon
10 decagon
Quadrilaterals
• Recall: a quadrilateral is a 4-sided polygon. We can
further classify quadrilaterals:
 A trapezoid is a quadrilateral with at least one pair of
parallel sides.
 A parallelogram is a quadrilateral in which both pairs of
opposite sides are parallel.
 A kite is a quadrilateral in which two pairs of adjacent
sides are congruent.
 A rhombus is a quadrilateral in which all sides are
congruent.
 A rectangle is a quadrilateral in which all angles are
congruent (90 degrees)
 A square is a quadrilateral in which all four sides are
congruent and all four angles are congruent.
From General to Specific
Quadrilateral
trapezoid
kite
parallelogram
rhombus
rectangle
square
Morespecific
Perimeter and Area
• The perimeter of a plane geometric figure
is a measure of the distance around the
figure.
• The area of a plane geometric figure is the
amount of surface in a region.
perimeter
area
Triangle
h
b
a c
Perimeter = a + b + c
Area = bh
2
1
The height of a triangle is
measured perpendicular to the
base.
Rectangle and Square
w
l
s
Perimeter = 2w + 2l Perimeter = 4s
Area = lw Area = s2
Parallelogram
b
a h
Perimeter = 2a + 2b
Area = hb  Area of a parallelogram
= area of rectangle with
width = h and length = b
Trapezoid
c d
a
b
Perimeter = a + b + c + d
Area =
b
a
 Parallelogram with base (a + b) and height = h
with area = h(a + b)
 But the trapezoid is half the parallelgram 
h(a + b)2
1
h
Ex: Name the polygon
3
21
4
5
6
 hexagon
1
2
3
4
5
 pentagon
Ex: What is the perimeter of a
triangle with sides of lengths 1.5 cm,
3.4 cm, and 2.7 cm?
1.5 2.7
3.4
Perimeter = a + b + c
= 1.5 + 2.7 + 3.4
= 7.6
Ex: The perimeter of a regular
pentagon is 35 inches. What is the
length of each side?
Perimeter = 5s
35 = 5s
s = 7 inches
s
Recall: a regular polygon is
one with congruent sides.
Ex: A parallelogram has a based of
length 3.4 cm. The height
measures 5.2 cm. What is the area
of the parallelogram?
3.4
5.2
Area = (base)(height)
Area = (3.4)(5.2)
= 17.86 cm2
Ex: The width of a rectangle is
12 ft. If the area is 312 ft2
, what
is the length of the rectangle?
12 312 Area = (Length)(width)
L = 26 ft
Let L = Length
L
312 = (L)(12)
Check: Area = (Length)(width) = (12)(26)
= 312
Circle
• A circle is a plane figure in which all points are
equidistance from the center.
• The radius, r, is a line segment from the center of
the circle to any point on the circle.
• The diameter, d, is the line segment across the
circle through the center. d = 2r
• The circumference, C, of a circle is the distance
around the circle. C = 2πr
• The area of a circle is A = πr2
.
r
d
Find the Circumference
• The circumference, C,
of a circle is the distance
around the circle. C = 2πr
• C = 2πr
• C = 2π(1.5)
• C = 3π cm
1.5 cm
Find the Area of the Circle
• The area of a circle is A = πr2
• d=2r
• 8 = 2r
• 4 = r
• A = πr2
• A = π(4)2
• A = 16π sq. in.
8 in
Composite Geometric Figures
• Composite Geometric Figures are made
from two or more geometric figures.
• Ex:
+
• Ex: Composite Figure
-
Ex: Find the perimeter of the
following composite figure
+=
8
15
Rectangle with width = 8
and length = 15
Half a circle with diameter = 8
 radius = 4
Perimeter of composite figure = 38 + 4π.
Perimeter of partial rectangle
= 15 + 8 + 15 = 38
Circumference of half a circle
= (1/2)(2π4) = 4π.
Ex: Find the perimeter of the
following composite figure
28
60
42
12
? = a
? = b
60
a 42
60 = a + 42  a = 18
28
b
12
28 = b + 12  b = 16
Perimeter = 28 + 60 + 12 + 42 + b + a
= 28 + 60 + 12 + 42 + 16 + 18 = 176
Ex: Find the area of the figure
3
3
8
8
Area of rectangle = (8)(3) = 24
3
8
Area of triangle = ½ (8)(3) = 12
Area of figure
= area of the triangle + area of
the square = 12 + 24 = 36.
3
Ex: Find the area of the figure
4
3.5
4
3.5
Area of rectangle = (4)(3.5) = 14
4
Diameter = 4  radius = 2
Area of circle = π22
= 4π  Area of half the circle = ½ (4π) = 2π
The area of the figure
= area of rectangle – cut out area
= 14 – 2π square units.
Ex: A walkway 2 m wide surrounds
a rectangular plot of grass. The
plot is 30 m long and 20 m wide.
What is the area of the walkway?
20
30
2
What are the dimensions of the big
rectangle (grass and walkway)?
Width = 2 + 20 + 2 = 24
Length = 2 + 30 + 2 = 34
The small rectangle has area = (20)(30) = 600 m2
.
What are the dimensions of the small rectangle (grass)?
Therefore, the big rectangle has area
= (24)(34) = 816 m2
.
The area of the walkway is the difference between the big and small
rectangles:
20 by 30
Area = 816 – 600 = 216 m2
.
2
Find the area of the shaded region
10
10
10
r = 5
Area of each
circle = π52
= 25π
¼ of the circle cuts
into the square.
But we have four ¼
4(¼)(25π ) cuts into
the area of the square.
Area of square =
102
= 100
Therefore, the area of the shaded region
= area of square – area cut out by circles = 100 – 25π
square units
r = 5
32
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Intro to Geometry Concepts

  • 1. 1
  • 3. The Elements • Knowing that you can’t define everything and that you can’t prove everything, Euclid began by stating three undefined terms:  Point  (Straight) Line  Plane (Surface) Actually, Euclid did attempt to define these basic terms . . . is that which has no part is a line that lies evenly with the points on itself is a plane that lies evenly with the straight lines on itself
  • 4. Basic Terms & Definitions • A ray starts at a point (called the endpoint) and extends indefinitely in one direction. • A line segment is part of a line and has two endpoints. A B AB BA AB
  • 5. • An angle is formed by two rays with the same endpoint. • An angle is measured in degrees. The angle formed by a circle has a measure of 360 degrees. vertex side side
  • 6. • A right angle has a measure of 90 degrees. • A straight angle has a measure of 180 degrees.
  • 7. • A simple closed curve is a curve that we can trace without going over any point more than once while beginning and ending at the same point. • A polygon is a simple closed curve composed of at least three line segments, called sides. The point at which two sides meet is called a vertex. • A regular polygon is a polygon with sides of equal length.
  • 8. Polygons # of sides name of Polygon 3 triangle 4 quadrilateral 5 pentagon 6 hexagon 7 heptagon 8 octagon 9 nonagon 10 decagon
  • 9. Quadrilaterals • Recall: a quadrilateral is a 4-sided polygon. We can further classify quadrilaterals:  A trapezoid is a quadrilateral with at least one pair of parallel sides.  A parallelogram is a quadrilateral in which both pairs of opposite sides are parallel.  A kite is a quadrilateral in which two pairs of adjacent sides are congruent.  A rhombus is a quadrilateral in which all sides are congruent.  A rectangle is a quadrilateral in which all angles are congruent (90 degrees)  A square is a quadrilateral in which all four sides are congruent and all four angles are congruent.
  • 10. From General to Specific Quadrilateral trapezoid kite parallelogram rhombus rectangle square Morespecific
  • 11. Perimeter and Area • The perimeter of a plane geometric figure is a measure of the distance around the figure. • The area of a plane geometric figure is the amount of surface in a region. perimeter area
  • 12. Triangle h b a c Perimeter = a + b + c Area = bh 2 1 The height of a triangle is measured perpendicular to the base.
  • 13. Rectangle and Square w l s Perimeter = 2w + 2l Perimeter = 4s Area = lw Area = s2
  • 14. Parallelogram b a h Perimeter = 2a + 2b Area = hb  Area of a parallelogram = area of rectangle with width = h and length = b
  • 15. Trapezoid c d a b Perimeter = a + b + c + d Area = b a  Parallelogram with base (a + b) and height = h with area = h(a + b)  But the trapezoid is half the parallelgram  h(a + b)2 1 h
  • 16. Ex: Name the polygon 3 21 4 5 6  hexagon 1 2 3 4 5  pentagon
  • 17. Ex: What is the perimeter of a triangle with sides of lengths 1.5 cm, 3.4 cm, and 2.7 cm? 1.5 2.7 3.4 Perimeter = a + b + c = 1.5 + 2.7 + 3.4 = 7.6
  • 18. Ex: The perimeter of a regular pentagon is 35 inches. What is the length of each side? Perimeter = 5s 35 = 5s s = 7 inches s Recall: a regular polygon is one with congruent sides.
  • 19. Ex: A parallelogram has a based of length 3.4 cm. The height measures 5.2 cm. What is the area of the parallelogram? 3.4 5.2 Area = (base)(height) Area = (3.4)(5.2) = 17.86 cm2
  • 20. Ex: The width of a rectangle is 12 ft. If the area is 312 ft2 , what is the length of the rectangle? 12 312 Area = (Length)(width) L = 26 ft Let L = Length L 312 = (L)(12) Check: Area = (Length)(width) = (12)(26) = 312
  • 21. Circle • A circle is a plane figure in which all points are equidistance from the center. • The radius, r, is a line segment from the center of the circle to any point on the circle. • The diameter, d, is the line segment across the circle through the center. d = 2r • The circumference, C, of a circle is the distance around the circle. C = 2πr • The area of a circle is A = πr2 . r d
  • 22. Find the Circumference • The circumference, C, of a circle is the distance around the circle. C = 2πr • C = 2πr • C = 2π(1.5) • C = 3π cm 1.5 cm
  • 23. Find the Area of the Circle • The area of a circle is A = πr2 • d=2r • 8 = 2r • 4 = r • A = πr2 • A = π(4)2 • A = 16π sq. in. 8 in
  • 24. Composite Geometric Figures • Composite Geometric Figures are made from two or more geometric figures. • Ex: +
  • 25. • Ex: Composite Figure -
  • 26. Ex: Find the perimeter of the following composite figure += 8 15 Rectangle with width = 8 and length = 15 Half a circle with diameter = 8  radius = 4 Perimeter of composite figure = 38 + 4π. Perimeter of partial rectangle = 15 + 8 + 15 = 38 Circumference of half a circle = (1/2)(2π4) = 4π.
  • 27. Ex: Find the perimeter of the following composite figure 28 60 42 12 ? = a ? = b 60 a 42 60 = a + 42  a = 18 28 b 12 28 = b + 12  b = 16 Perimeter = 28 + 60 + 12 + 42 + b + a = 28 + 60 + 12 + 42 + 16 + 18 = 176
  • 28. Ex: Find the area of the figure 3 3 8 8 Area of rectangle = (8)(3) = 24 3 8 Area of triangle = ½ (8)(3) = 12 Area of figure = area of the triangle + area of the square = 12 + 24 = 36. 3
  • 29. Ex: Find the area of the figure 4 3.5 4 3.5 Area of rectangle = (4)(3.5) = 14 4 Diameter = 4  radius = 2 Area of circle = π22 = 4π  Area of half the circle = ½ (4π) = 2π The area of the figure = area of rectangle – cut out area = 14 – 2π square units.
  • 30. Ex: A walkway 2 m wide surrounds a rectangular plot of grass. The plot is 30 m long and 20 m wide. What is the area of the walkway? 20 30 2 What are the dimensions of the big rectangle (grass and walkway)? Width = 2 + 20 + 2 = 24 Length = 2 + 30 + 2 = 34 The small rectangle has area = (20)(30) = 600 m2 . What are the dimensions of the small rectangle (grass)? Therefore, the big rectangle has area = (24)(34) = 816 m2 . The area of the walkway is the difference between the big and small rectangles: 20 by 30 Area = 816 – 600 = 216 m2 . 2
  • 31. Find the area of the shaded region 10 10 10 r = 5 Area of each circle = π52 = 25π ¼ of the circle cuts into the square. But we have four ¼ 4(¼)(25π ) cuts into the area of the square. Area of square = 102 = 100 Therefore, the area of the shaded region = area of square – area cut out by circles = 100 – 25π square units r = 5
  • 32. 32 Do you find this slides were useful? One second of your life , can bring a smile in a girl life If Yes ,Join Dreams School “Campaign for Female Education” Help us in bringing a change in a girl life, because “When someone takes away your pens you realize quite how important education is”. Just Click on any advertisement on the page, your one click can make her smile. Eliminate Inequality “Not Women” One second of your life , can bring a smile in her life!! Do you find these slides were useful? If Yes ,Join Dreams School “Campaign for Female Education” Help us in bringing a change in a girl life, because “When someone takes away your pens you realize quite how important education is”. Just Click on any advertisement on the page, your one click can make her smile. We our doing our part & u ? Eliminate Inequality “Not Women”