Binomial Distribution and Probability Examples Explained
1.
2. • Introduction
• Easy examples
• Real life
examples
• Binomial
distribution
• GeoGebra
TOPICS THAT HAVE
BEEN COVERED
3. Introduction
• Many events can't be predicted with total certainty. The best
we can say is how likely they are to happen, using the idea of
probability.
• Probability does not tell us exactly what will happen, it is just
a guide
4. Binomial Distribution
• Each trial can result in just two possible outcomes. We call
one of these outcomes a success and the other, a failure.
The probability of success, denoted by P, is the same on
every trial. The trials are independent; that is, the outcome
on one trial does not affect the outcome on other trials.
8. Finding Out The Probability
Three stage rocket is about to be launched. In order for a successful launch to occur all
three stages of the rocket must successfully pass their pre- take off tests. By default, each
stage has a 50% chance of success.
Success rate{%} – 10.0000000
Successful Launches – 1
Failed Launches- 9
• 94% success is over a long history of rocket
development. More recently, launching agencies have
refined their designs and processes to achieve really
high reliabilities. Atlas II through Atlas V have had only
one partial failure in 120 launches since 1991
• 176 failures from 3024 launches = 5.8% failure. Various
assumptions made as to what constitutes failure.
• Let's take the one partial failure in 120 data and check whether this is statistically significantly lower
than the 94% success rate long term. One could apply the right same principles to the different
launch vehicle categories on the comparison of orbital failure and launch.
• Assuming the true probability of partial failure were p=6%, as in the figure quoted by Russell's
comment, the probability of observing one partial failure or fewer in 120 launches is:
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10. Finding The Probability
• Now lets calculate the total number of seats in Delhi metro. Total seats in one
coach are 50 ( 14+14+14+4+4). Average coach in each train are 6(Refer
assumption given below). Total seats in one train = 50x 6 this means 300 seats in
one metro. And total of 600000 (300x 2000) seats available in Delhi metro
everyday.
• Hence now we will talk about the probability of getting a seat in Delhi metro.
With total number of ridership of 2.4 million and 6,00,000 seats available we can
draw the conclusion that 1 out of 5 people get a seat in Delhi metro(2,400,000/
600,000).
• Hence number of people who travel sitting in metro are 600,000 and those who
travel standing are 1,800,000.
• This calculation gives a very general result of the possibility of getting a seat.
Result may vary according to the time of travel and the line travelled on.
ASSUMPTION: The average number of coaches in metro can be taken as 6, we
have 4 and 8 coach metro, hence in this case the excess number of coaches in 8
car metro will be compensating for the number of coaches in 4 car metro.
11. A digital way of thinking……..solving
& understanding