1. f(x) = ax2 + bx + c, where a 0

2. f(x) = ax2 + bx + c
vertex
Line of symmetry

3. f(x) = ax2 + bx + c How do you find:
y-intercept (0, c)
line of symmetry:
vertex:
y-intercept vertex
( , f( ) )
Line of symmetry

4. Find the y-intercept, the equation of the axis of
symmetry, and the coordinates of the vertex for
y-intercept: Line of symmetry:
(0, 2)
Vertex: f(2) = 1(2)2 - 4(2) + 2
(2, -2 ) =4–8+2
= -2

5. Line of symmetry: x = 2
Vertex: (2, -2)
y- int: (0, 2)
x f(x)
0 2
1 –1 (0, 2)
2 –2
3 –1
4 2
(2, –2)

6. Find the y-intercept, the equation of the axis of
symmetry, and the coordinates of the vertex for
6 3
y-intercept: Line of symmetry:
6
(0, 3) 3
Vertex: f(3) = 1(3)2 – 6(3) + 3
(3, -6 ) = 9 – 18 + 3
= -6

7. Line of symmetry: x = 3
Vertex: (3, -6)
y- int: (0, 3)
x x2 – 6x + 3 f(x)
(0, 3)
0 3
1 12 – 6(1) + 3 –2
2 22 – 6(2) + 3 –5
3 –6
6 3
(3, –6)

8. Find the maximum or a minimum value of
a = -1
= =1
=
Maximum value is 4 when x is 1