Weitere ähnliche Inhalte
Ähnlich wie Alg2 lesson 10-4 and 10-5 (20)
Mehr von Carol Defreese (20)
Kürzlich hochgeladen (20)
Alg2 lesson 10-4 and 10-5
- 1. A common logarithm has a base of 10.
log 5 means log10 5
The log key on your calculator will find
common logs.
- 3. Solve
log 3x = log 17
x log 3 = log 17
log 17
x = log 3
1.2304
=
0.4771
= 2.5789
- 5. Solve: 5x + 3 = 2x + 4
log 5x + 3 = log 2x + 4
(x + 3) log 5 = (x + 4) log 2
x log 5 + 3 log 5 = x log 2 + 4 log 2
x log 5 – x log 2 = 4 log 2 – 3 log 5
x(log 5 – log 2) = 4 log 2 – 3 log 5
x = 4 log 2 – 3 log 5 = 4(0.3010) – 3(0.6990)
log 5 – log 2 0.6990 – 0.3010
= -2.244
- 9. Quantities that grow or decay
continuously can be described by a
natural exponential function.
f(x) = ex
e is a constant
e is approximately 2.71828
- 10. Use a calculator to evaluate each expression to four
decimal places.
a.
Answer: 1.3499
b.
Answer: 0.1353
- 11. The inverse of the natural exponential
function is the natural log function.
y = ex loge y = x
loge is usually written as ln
- 12. Use a calculator to evaluate each expression to
four decimal places.
a. In 2 Answer: 0.6931
b. In Answer: –0.6931
- 13. Write as a natural logarithmic equation.
x = loge 23
x = ln 23
- 14. Write as an exponential equation.
loge x = 2.25
- 16. Solve
loge 2x = 0.7
2x = e0.7
x = ½ e0.7
Answer: about 1.0069
