1. A single acting cylinder with a 2000 mm^2 piston area supplied with 3 bar pressure generates an outward force of 600 N and a mass force of 61.22 kg. 2. A double acting cylinder with a 60mm diameter piston, 10mm diameter rod, and 3 bar pressure generates outward and inward forces of 847.8 N and 824.25 N respectively. 3. A single acting cylinder with an 80mm piston, 15mm rod diameter, and 6 bar pressure generates outward and inward forces of 3015.93 N and 2909.99 N respectively. This cylinder is capable of pushing a 300 kg object.

1. PROBLEMS
1. A single acting cylinder has a cm² area piston. I fit is connected to a
compressor that supplies a 3 bar pressure, work out the force exerted by its
rod in Newton and Kg.
P(MPa) · A (mm²)  Foutstroke
Foutstoke= 0’3MPa · 2000mm² = 600N
P (MPa) · (π r1² - π r2²)  Instroke
m=P/g = 600/9’8 = 61’22 Kg
1 bar = 0’1MPa
20cm² = 2000 mm² =A
3bar= 0’3MPa
P =m.g
2. A double acting cylinder has a 60mm diameter piston and a 10mm diameter
rod. I fit is connected to a compressor that supplies a 3 bar pressure, work
out the force exerted by its rod when the expanding and retracting strokes
are performed.
Øcilíndre 60mm
Foutstroke= P (MPa) · A (mm²)
Øbarra
10mm
P= 3bar = 0’3 MPa
P
3 bar
A= π r² = 3’14 · 30² = 2826mm²
Abarra= π · 5²= 78’5mm²
Foutstroke= 0’3MPa · 2826 mm²
Fi= 847’8N
Finstroke= 0’3MPa · (2826mm² -78’5mm²) = 824’25N

2. 3. A clamping vice uses a single acting cylinder to clamp the work-pieces.
Determine the extend force if the piston diameter of the cylinder is 80mm,
rod diameter 15 mm and the pressure used is 6 bar.
Øcilíndre
8mm
Foutstroke= P(MPa) · A (mm²) =0’6 · 5025’55=3015’93 N
Øbarra
15m
P= 6bar = 0’6 MPa
P
6ar
A= π r² = π · 40² = 5026’55 mm²
R= 80mm/2 = 40mm
Finstroke= P(MPa) · (π r1 - π r2²)
0’6MPa (5026’55 – 176’7)= 2909’ 99 N
Abarra= π 7’5² = 176’7 mm²
4. A double acting cylinder is used to transfer work-pieces in a production
machine. Determine the extend and retract forces if the piston diameter of
the cylinder is 80mm , rod diameter 15mm and the pressure used is 6bar.
Øcilíndre
80mm
Foutstroke = 0’6MPa · 5024 mm² = 3014’4 N
Øbarra
15mm
P= 6 bar = 0’6 MPa
P
6 bar
Acilindre = π r² = 3’14 · 40²= 5024 mm²
Abase= π r²= 3’14 · 7’5² = 176’63 mm²
Finstroke= P (MPa) · (π r1 - π r2²)= 0’6 MPa · (5024 mm²
- 176’63 mm²)= 2908’42N

3. 5. Determine if the single acting cylinder with the following features, is
capable of pushing a 300 Kg object.
- piston diameter: 80 mm
- rod diameter: 25 mm
- working pressure: 6 Kg/cm2
Øcilíndre
80mm
6Kg .
10cm .
Øbarra
25mm
1cm²
1kg
P
1cm² .
= 0’6 N/mm²
6 Kg/cm²
100mm²
60N
100mm²
Foutstroke= 0’6 MPa · 5024mm² = 3014’4N
A= π r²= 3’14 · 40²= 5024mm ²
-Sí.
6. Determine the minimum diameter of a single acting cylinder to be able to
push a minimal load of 8000 N if it’s fed with a 100 bar pressure.
Foutstroke 8000N
F= P · A
P
8000N =10 MPa · π ² 3’14
100 bar
8000/ 10·3’14 = r²
r²= √251’2 = 15’8 N