cash flows in the diagrams Parts 1 and 2Book for class is engineer.pdf

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Carmen, a computer sales representative, feels that the odds are 13 to 8 that she will clinch the sale of a mini-computer to a certain company. What is the (subjective) probability that Carmen will make the sale? (Round your answer to three decimal places.) P(Sale) = 1 Solution 13 (will happen) + 8(won\'t happen) = 21 now, 13/21 = (probability she will make the sale).

Bildung

cash flows in the diagrams Parts 1 and 2
Book for class is engineering economic analysis by Newman The cash flows in the diagrams
below are considered to be equivalent in terms of economic desirability at an interest rate of 6%
compounded annually. Determine the unknown value A. $4000 0 1 2 3 4 5 6 789 10 $200 If the
cash flow diagram below has a present worth (at year 0) of $0 at an interest rate of 8%, calculate
the value of C S520 $440 $360 S280 4 $200 A
Solution
If the cah flows in both the diagram are equivalent in terms of economic desirabilty, it means
there would be equal total present worth of both the alternatives' cash flows.
Total PW of cash flows of Alternative 1 = Total PW of cash flows of Alternative
Lets calculate Total PW of cash flows of Alternative 1 :
Now, Consider Alternative 2:
Total PW = $2968.4 = A(P/F,6%,1) + A(P/F,6%,2) + A(P/F,6%,3) + A(P/F,6%,4) +
A(P/F,6%,5) + A(P/F,6%,6) + A(P/F,6%,7) + A(P/F,6%,8)
= A(0.9434) + A( 0.8900) + A(0.8396) + A( 0.7921) + A(0.7473) + A( 0.7050) + A(0.6651) +
A( 0.6274)
= A (0.9434+0.8900+0.8396+0.7921+ 0.7473 + 0.7050 +0.6651 +0.6274)
=A*6.2099
A = $2968.4 / 6.2099 = $478.0109.YearCash flowsInterest at 6%PW0-2001-
200100.94340200.890300.83960440000.79213168.4Total PW2968.4

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Can someone explain this whole problem to me in detailed steps? I understand everything up until line 5 to 6... I don\'t understand how the i is taken out of the numerator and how an i randomly appears in the denominator. Clarification/more detailed steps from lines 4 and on would be greatly appreciated. Solution i appears in denominator as for e^ix-e^-ix gives 2i*sinx so he divided by 2i for cancelling in 4th step he multiplied denominator with i and taken common - sign out in 5th step rationaliging has been done in 6th step he taken 5 common and multiplyed denominator with 2 and on considering 2i common in numerator he taken 2i and multiplied and divided with i for that whole term 2i in th 6th step so that in numerator 2i becomes -2 and denominator 2 becomes 2i in 7th step he used e^ix and e^-ix values as they are cosx+isinx and cosx-isinx respectively and bye substitution and calculation in 6th step we got 7th step simplified answer.

Can someone explain this whole problem to me in detailed steps I un.pdf

Amansupan

Can someone please explain the gauss theorem on the field of complex numbers? Solution Answer: Gauss gave the first clear exposition of complex numbers and of the investigation of functions of complex variables in the early 19th Century. Although imaginary numbers involving i(the imaginary unit, equal to the square root of -1) had been used since as early as the 16th Century to solve equations that could not be solved in any other way, and despite Euler.

Can someone please explain the gauss theorem on the field of complex.pdf

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Can someone please explain these to me Let T R 3 rightarrow R 4 be .pdf

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