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Hoo Sze Yen                       www.physicsrox.com                         Physics SPM 2011



CHAPTER 2:
FORCES AND MOTION

2.1     Linear Motion
Linear Motion is the study of motion of an object in a straight line (with constant
acceleration).

Classification                 Scalar                        Vector
Physical quantity with…        Magnitude only                Magnitude and direction
Example                        Distance                      Displacement
                               Speed                         Velocity
                                                             Acceleration

2.1.1 Equations of Linear Motion

If s = displacement (succession) [m]
   u = initial velocity [m s-1]
   v = final velocity [m s-1]        Velocity is the rate of change of displacement.
   t = time [s]                      Acceleration is the rate of change of velocity.
   a = acceleration [m s-2]


                                  s = ½ (u + v) t                        —

                                        v−u
                                  a=                                     —
                                         t

From :                            v = u + at
Insert into    :                  s = ½ (u + u + at) t
                                  s = ut + ½ at 2                        —

                                        v−u
From     :                        t=
                                         a
                                                 (v − u )
Insert into    :                  s = ½(u + v)
                                                    t
                                     v2 − u2
                                    =
                                       2a
                                   2   2
                                  v = u + 2as                            —




Chapter 2: Forces and Motion                                                      Page 1 of 14
Hoo Sze Yen                           www.physicsrox.com                          Physics SPM 2011



2.2     Linear Motion Graphs

2.2.1 Ticker timer

Ticker timers are used to study motion in a short period of time.
Ticker timers usually have a frequency of 50 Hz; hence the period of one tick is 0.02 s.

Movement                                         Explanation
                                                 Consistent distance
                                                 = uniform velocity

                                                 Short distance
                                                 = low velocity

                                                 Long distance
                                                 = high velocity

                                                 Increasing distance
                                                 = increasing velocity / acceleration

                                                 Decreasing distance
                                                 = decreasing velocity / deceleration


To calculate the average velocity from a ticker tape strip or graph:

                                                       Total distance
                                 Average velocity =
                                                        Total time

To calculate the acceleration from a ticker
tape strip or graph:
                                                            s1                   s2
                                               s1
Step 1: Calculate the initial velocity, u =       .
                                               t
                                        s2
Step 2: Calculate the final velocity, v =    .
                                         t
                                        v−u
Step 3: Calculate the acceleration, a =        .                                               s2
                                           t

                                                                        s1
                               Remember! Time for acceleration
                               must be ONE LESS tick/strip




Chapter 2: Forces and Motion                                                            Page 2 of 14
Hoo Sze Yen                                 www.physicsrox.com                                       Physics SPM 2011



2.2.2 Linear Motion Graphs
                  Displacement-time                 Velocity-time graphs                Acceleration-time
                  graphs                                                                graphs
                  Velocity = slope of the graph     Acceleration = slope of the graph   Velocity = area under the graph
                                                    Displacement = area under the
                                                    graph
v=0                 s/m                               v/m s-                              a/m s-
                                                      1                                   2
(a = 0)



                                          t/s                              t/s                                 t/s

v = constant        s/m                               v/m s-                              a/m s-
                                                      1                                   2
(a = 0)



                                          t/s                              t/s                                 t/s

v↑                  s/m                               v/m s-                              a/m s-2
                                                      1
a = constant



                                          t/s                              t/s                                 t/s

v↓                  s/m                               v/m s-                              a/m s-2
                                                      1
a = constant
                                                                                                               t/s


                                          t/s                              t/s

v↑                                                    v/m s-                            a/m s-2
                                                      1
a↑



                                                                           t/s                                 t/s
                                                                                                -2
v↑                                                    v/m s   -                         a/m s
                                                      1
a↓



                                                                           t/s                                 t/s

a ↑ increasing                                                                          a/m s-2
rate



                                                                                                               t/s
                                                                                                -2
a ↑ decreasing                                                                          a/m s
rate



                                                                                                               t/s




Chapter 2: Forces and Motion                                                                              Page 3 of 14
Hoo Sze Yen                          www.physicsrox.com                              Physics SPM 2011


REMEMBER!

                               gradient                         gradient



       DISPLACEMENT                         VELOCITY                       ACCELERATION
        Displacement-time                 Velocity-time graph               Acceleration-time
              graph                                                              graph


                        area under the graph               area under the graph



2.3     Inertia
Inertia – natural characteristics of an object to oppose any attempted change on its
          original state, whether at rest or in motion
        – tendency of an object to remain at rest, or to keep moving at constant speed
          in a straight line

Newton’s First Law of Motion (Law of Inertia)
Every object in a state of uniform motion tends to remain in that state of motion unless
an external force is applied to it.

2.4     Momentum
                           Momentum = mass × velocity
                                   p = mv
                           -1
where p = momentum [kg m s ]
      m = mass [kg]
      v = velocity [m s-1]

Principle of conservation of momentum
In any collision or interaction between two or more objects in an isolated system, the
total momentum before collision is equal to the total momentum after collision.

                                   m1u1 + m2u2 = m1v1 + m2v2




Chapter 2: Forces and Motion                                                              Page 4 of 14
Hoo Sze Yen                          www.physicsrox.com                             Physics SPM 2011


Three types of collisions:
1) Elastic collision
   Both objects move separately after collision.
    Note: In an elastic collision, the kinetic energy is conserved.


                                   m1u1 + m2u2 = m1v1 + m2v2

    E.g.: a cue ball hitting a snooker ball, bowling ball striking a pin, bumper cars colliding into
    each other

2) Inelastic collision
   Both objects move together after collision.


                                   m1u1 + m2u2 = (m1 + m2)v

    E.g.: a boy running and jumping onto a skateboard and both move together after collision

3) Explosion
   Both objects are initially stationary, and move in opposite directions after the
   explosion.


                                         0 = m1v1 + m2v2
                                          m1v1 = - m2v2

    E.g. : a bullet fired from a stationary gun, a man jumping out of a stationary boat, a boy
    jumping off a stationary skateboard


2.5     Force
Force changes the size, shape, state of rest, velocity and/or direction of an object.
Force is a vector quantity.

Newton’s Second Law of Motion
The acceleration of a body, a, is directly proportional to the net force acting upon it, F,
and inversely proportional to its mass, m.

                                              F = ma

where F = force [N]
      m = mass [kg]
      a = acceleration caused by F [m s-2]



Chapter 2: Forces and Motion                                                             Page 5 of 14
Hoo Sze Yen                          www.physicsrox.com                      Physics SPM 2011



2.5.1 Balanced Forces

Balanced forces is a state where net force is zero
An object that is stationary, or moving with uniform velocity in a straight line, is said to
be in a state of balanced forces.
Example:
An airplane moving with uniform velocity at constant height is in a state of balanced
forces.

                                                          Weight = Lift
                                                          Thrust = Drag




2.5.2 Unbalanced Forces

Unbalanced forces may cause an object to start moving, to speed it up, to slow it
down, or to bring it to a stop. The greater the unbalanced force, the greater the
acceleration or deceleration produced.


2.6     Impulse and Impulsive Force
                               Impulse = change of momentum
                                        Ft = mv – mu

              Impulsive force = change of momentum in a very short period of time
                                             mv − mu
                                          F=
                                                t

where Ft = impulse [kg m s-1]
      F = impulsive force [N]
      m = mass [kg]
      u = initial velocity [m s-1]
      v = final velocity [m s-1]




Chapter 2: Forces and Motion                                                        Page 6 of 14
Hoo Sze Yen                         www.physicsrox.com                        Physics SPM 2011



2.7     Safety Features in Vehicles
1.   Padded dashboards                              8. Antilock brake systems (ABS)
2.   Shatterproof windscreen glass                  9. Variable-ratio response steering
3.   Inflatable airbags                                 systems
4.   Collapsible steering wheels                    10. Intelligent speed adaptation systems
5.   Headrest                                       11. Reverse collision warning systems
6.   Padded seats                                   12. Bumper bars
7.   Seatbelt

2.8     Gravity
All objects are pulled towards the centre of the earth by a force
known as the earth’s gravitational force. Any object dropped
towards earth which falls under the influence of the earth’s
gravitational force (without any influence of other external forces,
such as air friction) is said to be going through a free fall. In reality,
free falls only happen within a vacuum space.

The diagram on the right shows the non-uniform gravitational field of the Earth, g which
is represented by radial lines directed towards the centre of the Earth. The field is
strongest where the lines are closest.

2.8.1 Free fall

An object undergoing free fall will fall at the rate of gravitational acceleration which is
at a constant of 9.81 m s-2 at sea level. The gravitational acceleration is not influenced
by the size or mass of the object.
Baseball Bowling ball
                        Objects dropped from the same height will fall at the same rate and
                        will hit the ground at the same time, regardless of the mass.




                    However, for objects with very small mass
                    and very large surface area like feathers,
                    pieces of paper and cloth, they will fall at a
                    lower rate. This is because the larger the
                    surface area, the greater the air resistance.

                    If the same objects are placed in a vacuum
                    tube, they will fall at the same rate.



Chapter 2: Forces and Motion                                                       Page 7 of 14
Hoo Sze Yen                          www.physicsrox.com                           Physics SPM 2011

2.8.2 Weight

Weight = gravitational force acting on the respective object

                                             W = mg

where W = weight [N]
      m = mass [m]
      g = gravitational acceleration [m s-2]

2.8.3 Lifts

               R                               Common formula:
                                                 R = mg + ma
 a
                        Where       R = reading of the scale [N]
                             m = mass of person [kg]
                             g = gravitational acceleration [m s-2]
       W = mg                a = upward acceleration of the lift [m s-2]

                       If the lift is stationary or moving with uniform velocity (a = 0):
                                                      R = mg

                       If the lift is moving upwards with acceleration:
                                                 R = mg + ma

                       If the lift is moving upwards with deceleration:
                                                R = mg + m(-a)
                                                 R = mg – ma

                       If the lift is moving downwards with acceleration:
                                                 R = mg - ma

                       If the lift is moving downwards with deceleration:
                                                R = mg – m(-a)
                                                 R = mg + ma




Chapter 2: Forces and Motion                                                           Page 8 of 14
Hoo Sze Yen                            www.physicsrox.com                               Physics SPM 2011

2.9     Forces in Equilibrium
Equilibrium:
- resultant force = 0
- acceleration = 0 (stationary or uniform velocity)

Newton’s Third Law
For every action there is an equal and opposite reaction.
                                                                                    Fx = F cos θ
                                                                                    Fy = F sin θ
2.9.1 Nett / Resultant Forces

Using the parallelogram method




You can solve resultant force by using scaled diagram or calculation.

1. Scaled diagram
   Draw the forces to scale using a ruler and a protractor.
   Magnitude of resultant force is obtained by measuring and converting back to value
   using the scale, and the angle is measured with a protractor.

2. Calculator
                               R                            Rx = F1 + F2 cos θ
                                       F2                   Ry = F2
                                             R
                                                                  Rx + R y
                                                                    2        2
                  α                θ                        R=
                                             y
                      F1
                                                                        Ry
                                                            Angle of R, α = tan-1
                R                                                       Rx
Note: If two equal forces are acting upon an object at an angle, the simplified solution is:
                      x
                      F
                           R = F cos θ + F cos θ
           θ               R = 2 F cos θ
              θ

                      F




Chapter 2: Forces and Motion                                                                 Page 9 of 14
Hoo Sze Yen                                   www.physicsrox.com                           Physics SPM 2011

2.9.2 Pulleys
                                                      Based on the force formula:
                          Assume motion                              F = ma
  T                       and acceleration            F = Net force acting on the system
              T
                          in this direction           m = Total mass of the system
      m2
                                                      a = Acceleration of the system
 F2        m1

              F1
                                                                 F1 – F2 = (m1 + m2) a

                                                      To find out the rope tension:
                                                                       F = ma
                                                                    F1 – T = m1a
                                                                    T = F2 – m2a


           Example:
           Calculate the acceleration and rope tension in the following system.

           To calculate acceleration:                  To calculate tension:

                                                       Isolate the left side of the pulley (5 kg
                             F = ma                    object is moving down):
                             50 – 30              =
            5 kg             (5+3)a                      T         F = ma
                   3 kg
                             a = 2.5 m s-2                         50 – T = 5(2.5)
                                                                   T = 37.5 N
                                                          5 kg




                                                          50 N
                                                       OR

                                                       Isolate the right side of the pulley (3 kg
                                                       object is moving up):

                                                         T         F = ma
                                                                   T – 30 = 3(2.5)
                                                                   T = 37.5 N
                                                          3 kg




                                                          30 N


                                                       You will get the same value of tension
                                                       whether you isolate the left or right side.




Chapter 2: Forces and Motion                                                                   Page 10 of 14
Hoo Sze Yen                            www.physicsrox.com                     Physics SPM 2011

2.9.3 Inclined Planes
                                       R              Fr


                                            θ




                               θ

                                           W=mg

                                            R = mg cos θ
                                            Fr = mg sin θ
where W = weight of object [N]
      m = mass of object [kg]
      g = gravitational acceleration [m s-2]
      R = reaction caused by weight of object perpendicular to plane [N]
      Fr = friction caused by weight of object parallel to plane [N]

When solving questions with inclined planes, use the following shortcut:

                          Weight of object parallel to the plane = mg sin θ




                     mg sin θ

                                   θ



2.10 Work, Energy, Power and Efficiency

2.10.1          Work

    Work is the product of the applied force and its displacement in the direction of the
    net force.
    Work is a scalar quantity.
    When work is done, energy is transferred to the object or changed into a different
    form.
    Work is only done when the object has been displaced. If there is no displacement,
    there is no work done.
    Displacement must be parallel to the force exerted.

                                                W = Fs
where W = work [J]
      F = force creating the work [N]
      s = displacement [m]

Chapter 2: Forces and Motion                                                      Page 11 of 14
Hoo Sze Yen                       www.physicsrox.com                         Physics SPM 2011

2.10.2          Energy

    Energy is the potential or ability of a system to do work.
    Energy is a scalar quantity.

First law of thermodynamics a.k.a. the principle of conservation of energy states
that energy may neither be created nor destroyed; it can only change shape.

2.10.2.1 Kinetic Energy

    Kinetic energy is energy acquired by an object during movement.

                                           E = ½ mv2
where E = kinetic energy [J]
      m = mass [kg]
      v = velocity of the object [m s-1]

2.10.2.2 Potential Energy

    Potential energy is the energy within an object because of its position or state.
    Potential energy is stored energy giving the body potential to do work.

Gravitational potential energy:
                                           E = mgh
where E = potential energy [J]
      m = mass [kg]
      g = gravitational acceleration [m s-2]
      h = height of the location of the object [m]
                                                                     F/N
Elastic potential energy:
                                           E = ½ Fx
where E = potential energy [J]
      F = force exerted [N]
      x = extension or compression of the spring [m]
                                                                                             x/m

2.10.3          Power

  Power is the rate at which energy is used OR the rate at which work is done.
                                          E W
                                      P= =
                                          t  t
where P = power [W]
      E = energy [J]
      W = work [J]
      t = time [s]




Chapter 2: Forces and Motion                                                     Page 12 of 14
Hoo Sze Yen                             www.physicsrox.com                    Physics SPM 2011

2.10.4          Efficiency

Efficiency is the ratio at which the output power is compared to the input power.

                                                  Output power
                                   Efficiency =                × 100%
                                                  Input power


2.11 Maximising Efficiency

The second law of thermodynamics a.k.a. the law of entropy states that in any
energy transformation, some energy will be lost in the form of heat.

    Efficiency should be maximized in order to conserve energy resources.
    For example, to maximize efficiency of refrigerators:
        Use refrigerators that have freezers at the top instead of the side
        Keep the cooling coils clean
        Do not put the fridge too near the wall or in a room that is too hot
        Door seals should be in good condition
        Do not open the fridge door unnecessarily
        Defrost the fridge regularly
        Don’t set the thermostat low all the time
        Send it for repair if the motor is not working properly


2.12 Elasticity
    Elasticity is the ability of an object to return to its original shape and size after the
    applied external force applied onto it has been removed.

2.13.1          Hooke’s Law

Hooke’s Law states that the extension or compression of a spring is directly
proportional to the force acting on it provided the elastic limit of the spring has not
been exceeded.

                                   Spring
                               extension,
                                   x (cm)
                                                              Elastic limit




                                                        Tension force, F




Chapter 2: Forces and Motion                                                      Page 13 of 14
Hoo Sze Yen                      www.physicsrox.com                         Physics SPM 2011


                                          F = kx

where F = force exerted on the spring [N]              Note: Because F=kx and E=½Fx, you
      k = spring constant [N m-1]                      can derive it to:
      x = spring extension / compression [m]                          E = ½ kx2

2.13.2 Spring stiffness

Factors which affect the stiffness of a spring:
 1) Length of spring       The greater the length the spring, the lower the stiffness
 2) Diameter of wire       The greater the diameter of wire, the higher the stiffness
 3) Diameter of coil       The greater the diameter of coil, the lower the stiffness
 4) Type of material

2.13.3 Spring systems

              Parallel arrangement                       Series arrangement




                         W
                                                                  W


The load is equally distributed among the The same load is applied to each spring.
springs.
If n springs are used:                    If n springs are used:
                   x                      Total extension = nx
Total extension =
                   n

                                     END OF CHAPTER




Chapter 2: Forces and Motion                                                    Page 14 of 14

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Forces and Motion Graphs Explained

  • 1. Hoo Sze Yen www.physicsrox.com Physics SPM 2011 CHAPTER 2: FORCES AND MOTION 2.1 Linear Motion Linear Motion is the study of motion of an object in a straight line (with constant acceleration). Classification Scalar Vector Physical quantity with… Magnitude only Magnitude and direction Example Distance Displacement Speed Velocity Acceleration 2.1.1 Equations of Linear Motion If s = displacement (succession) [m] u = initial velocity [m s-1] v = final velocity [m s-1] Velocity is the rate of change of displacement. t = time [s] Acceleration is the rate of change of velocity. a = acceleration [m s-2] s = ½ (u + v) t — v−u a= — t From : v = u + at Insert into : s = ½ (u + u + at) t s = ut + ½ at 2 — v−u From : t= a (v − u ) Insert into : s = ½(u + v) t v2 − u2 = 2a 2 2 v = u + 2as — Chapter 2: Forces and Motion Page 1 of 14
  • 2. Hoo Sze Yen www.physicsrox.com Physics SPM 2011 2.2 Linear Motion Graphs 2.2.1 Ticker timer Ticker timers are used to study motion in a short period of time. Ticker timers usually have a frequency of 50 Hz; hence the period of one tick is 0.02 s. Movement Explanation Consistent distance = uniform velocity Short distance = low velocity Long distance = high velocity Increasing distance = increasing velocity / acceleration Decreasing distance = decreasing velocity / deceleration To calculate the average velocity from a ticker tape strip or graph: Total distance Average velocity = Total time To calculate the acceleration from a ticker tape strip or graph: s1 s2 s1 Step 1: Calculate the initial velocity, u = . t s2 Step 2: Calculate the final velocity, v = . t v−u Step 3: Calculate the acceleration, a = . s2 t s1 Remember! Time for acceleration must be ONE LESS tick/strip Chapter 2: Forces and Motion Page 2 of 14
  • 3. Hoo Sze Yen www.physicsrox.com Physics SPM 2011 2.2.2 Linear Motion Graphs Displacement-time Velocity-time graphs Acceleration-time graphs graphs Velocity = slope of the graph Acceleration = slope of the graph Velocity = area under the graph Displacement = area under the graph v=0 s/m v/m s- a/m s- 1 2 (a = 0) t/s t/s t/s v = constant s/m v/m s- a/m s- 1 2 (a = 0) t/s t/s t/s v↑ s/m v/m s- a/m s-2 1 a = constant t/s t/s t/s v↓ s/m v/m s- a/m s-2 1 a = constant t/s t/s t/s v↑ v/m s- a/m s-2 1 a↑ t/s t/s -2 v↑ v/m s - a/m s 1 a↓ t/s t/s a ↑ increasing a/m s-2 rate t/s -2 a ↑ decreasing a/m s rate t/s Chapter 2: Forces and Motion Page 3 of 14
  • 4. Hoo Sze Yen www.physicsrox.com Physics SPM 2011 REMEMBER! gradient gradient DISPLACEMENT VELOCITY ACCELERATION Displacement-time Velocity-time graph Acceleration-time graph graph area under the graph area under the graph 2.3 Inertia Inertia – natural characteristics of an object to oppose any attempted change on its original state, whether at rest or in motion – tendency of an object to remain at rest, or to keep moving at constant speed in a straight line Newton’s First Law of Motion (Law of Inertia) Every object in a state of uniform motion tends to remain in that state of motion unless an external force is applied to it. 2.4 Momentum Momentum = mass × velocity p = mv -1 where p = momentum [kg m s ] m = mass [kg] v = velocity [m s-1] Principle of conservation of momentum In any collision or interaction between two or more objects in an isolated system, the total momentum before collision is equal to the total momentum after collision. m1u1 + m2u2 = m1v1 + m2v2 Chapter 2: Forces and Motion Page 4 of 14
  • 5. Hoo Sze Yen www.physicsrox.com Physics SPM 2011 Three types of collisions: 1) Elastic collision Both objects move separately after collision. Note: In an elastic collision, the kinetic energy is conserved. m1u1 + m2u2 = m1v1 + m2v2 E.g.: a cue ball hitting a snooker ball, bowling ball striking a pin, bumper cars colliding into each other 2) Inelastic collision Both objects move together after collision. m1u1 + m2u2 = (m1 + m2)v E.g.: a boy running and jumping onto a skateboard and both move together after collision 3) Explosion Both objects are initially stationary, and move in opposite directions after the explosion. 0 = m1v1 + m2v2 m1v1 = - m2v2 E.g. : a bullet fired from a stationary gun, a man jumping out of a stationary boat, a boy jumping off a stationary skateboard 2.5 Force Force changes the size, shape, state of rest, velocity and/or direction of an object. Force is a vector quantity. Newton’s Second Law of Motion The acceleration of a body, a, is directly proportional to the net force acting upon it, F, and inversely proportional to its mass, m. F = ma where F = force [N] m = mass [kg] a = acceleration caused by F [m s-2] Chapter 2: Forces and Motion Page 5 of 14
  • 6. Hoo Sze Yen www.physicsrox.com Physics SPM 2011 2.5.1 Balanced Forces Balanced forces is a state where net force is zero An object that is stationary, or moving with uniform velocity in a straight line, is said to be in a state of balanced forces. Example: An airplane moving with uniform velocity at constant height is in a state of balanced forces. Weight = Lift Thrust = Drag 2.5.2 Unbalanced Forces Unbalanced forces may cause an object to start moving, to speed it up, to slow it down, or to bring it to a stop. The greater the unbalanced force, the greater the acceleration or deceleration produced. 2.6 Impulse and Impulsive Force Impulse = change of momentum Ft = mv – mu Impulsive force = change of momentum in a very short period of time mv − mu F= t where Ft = impulse [kg m s-1] F = impulsive force [N] m = mass [kg] u = initial velocity [m s-1] v = final velocity [m s-1] Chapter 2: Forces and Motion Page 6 of 14
  • 7. Hoo Sze Yen www.physicsrox.com Physics SPM 2011 2.7 Safety Features in Vehicles 1. Padded dashboards 8. Antilock brake systems (ABS) 2. Shatterproof windscreen glass 9. Variable-ratio response steering 3. Inflatable airbags systems 4. Collapsible steering wheels 10. Intelligent speed adaptation systems 5. Headrest 11. Reverse collision warning systems 6. Padded seats 12. Bumper bars 7. Seatbelt 2.8 Gravity All objects are pulled towards the centre of the earth by a force known as the earth’s gravitational force. Any object dropped towards earth which falls under the influence of the earth’s gravitational force (without any influence of other external forces, such as air friction) is said to be going through a free fall. In reality, free falls only happen within a vacuum space. The diagram on the right shows the non-uniform gravitational field of the Earth, g which is represented by radial lines directed towards the centre of the Earth. The field is strongest where the lines are closest. 2.8.1 Free fall An object undergoing free fall will fall at the rate of gravitational acceleration which is at a constant of 9.81 m s-2 at sea level. The gravitational acceleration is not influenced by the size or mass of the object. Baseball Bowling ball Objects dropped from the same height will fall at the same rate and will hit the ground at the same time, regardless of the mass. However, for objects with very small mass and very large surface area like feathers, pieces of paper and cloth, they will fall at a lower rate. This is because the larger the surface area, the greater the air resistance. If the same objects are placed in a vacuum tube, they will fall at the same rate. Chapter 2: Forces and Motion Page 7 of 14
  • 8. Hoo Sze Yen www.physicsrox.com Physics SPM 2011 2.8.2 Weight Weight = gravitational force acting on the respective object W = mg where W = weight [N] m = mass [m] g = gravitational acceleration [m s-2] 2.8.3 Lifts R Common formula: R = mg + ma a Where R = reading of the scale [N] m = mass of person [kg] g = gravitational acceleration [m s-2] W = mg a = upward acceleration of the lift [m s-2] If the lift is stationary or moving with uniform velocity (a = 0): R = mg If the lift is moving upwards with acceleration: R = mg + ma If the lift is moving upwards with deceleration: R = mg + m(-a) R = mg – ma If the lift is moving downwards with acceleration: R = mg - ma If the lift is moving downwards with deceleration: R = mg – m(-a) R = mg + ma Chapter 2: Forces and Motion Page 8 of 14
  • 9. Hoo Sze Yen www.physicsrox.com Physics SPM 2011 2.9 Forces in Equilibrium Equilibrium: - resultant force = 0 - acceleration = 0 (stationary or uniform velocity) Newton’s Third Law For every action there is an equal and opposite reaction. Fx = F cos θ Fy = F sin θ 2.9.1 Nett / Resultant Forces Using the parallelogram method You can solve resultant force by using scaled diagram or calculation. 1. Scaled diagram Draw the forces to scale using a ruler and a protractor. Magnitude of resultant force is obtained by measuring and converting back to value using the scale, and the angle is measured with a protractor. 2. Calculator R Rx = F1 + F2 cos θ F2 Ry = F2 R Rx + R y 2 2 α θ R= y F1 Ry Angle of R, α = tan-1 R Rx Note: If two equal forces are acting upon an object at an angle, the simplified solution is: x F R = F cos θ + F cos θ θ R = 2 F cos θ θ F Chapter 2: Forces and Motion Page 9 of 14
  • 10. Hoo Sze Yen www.physicsrox.com Physics SPM 2011 2.9.2 Pulleys Based on the force formula: Assume motion F = ma T and acceleration F = Net force acting on the system T in this direction m = Total mass of the system m2 a = Acceleration of the system F2 m1 F1 F1 – F2 = (m1 + m2) a To find out the rope tension: F = ma F1 – T = m1a T = F2 – m2a Example: Calculate the acceleration and rope tension in the following system. To calculate acceleration: To calculate tension: Isolate the left side of the pulley (5 kg F = ma object is moving down): 50 – 30 = 5 kg (5+3)a T F = ma 3 kg a = 2.5 m s-2 50 – T = 5(2.5) T = 37.5 N 5 kg 50 N OR Isolate the right side of the pulley (3 kg object is moving up): T F = ma T – 30 = 3(2.5) T = 37.5 N 3 kg 30 N You will get the same value of tension whether you isolate the left or right side. Chapter 2: Forces and Motion Page 10 of 14
  • 11. Hoo Sze Yen www.physicsrox.com Physics SPM 2011 2.9.3 Inclined Planes R Fr θ θ W=mg R = mg cos θ Fr = mg sin θ where W = weight of object [N] m = mass of object [kg] g = gravitational acceleration [m s-2] R = reaction caused by weight of object perpendicular to plane [N] Fr = friction caused by weight of object parallel to plane [N] When solving questions with inclined planes, use the following shortcut: Weight of object parallel to the plane = mg sin θ mg sin θ θ 2.10 Work, Energy, Power and Efficiency 2.10.1 Work Work is the product of the applied force and its displacement in the direction of the net force. Work is a scalar quantity. When work is done, energy is transferred to the object or changed into a different form. Work is only done when the object has been displaced. If there is no displacement, there is no work done. Displacement must be parallel to the force exerted. W = Fs where W = work [J] F = force creating the work [N] s = displacement [m] Chapter 2: Forces and Motion Page 11 of 14
  • 12. Hoo Sze Yen www.physicsrox.com Physics SPM 2011 2.10.2 Energy Energy is the potential or ability of a system to do work. Energy is a scalar quantity. First law of thermodynamics a.k.a. the principle of conservation of energy states that energy may neither be created nor destroyed; it can only change shape. 2.10.2.1 Kinetic Energy Kinetic energy is energy acquired by an object during movement. E = ½ mv2 where E = kinetic energy [J] m = mass [kg] v = velocity of the object [m s-1] 2.10.2.2 Potential Energy Potential energy is the energy within an object because of its position or state. Potential energy is stored energy giving the body potential to do work. Gravitational potential energy: E = mgh where E = potential energy [J] m = mass [kg] g = gravitational acceleration [m s-2] h = height of the location of the object [m] F/N Elastic potential energy: E = ½ Fx where E = potential energy [J] F = force exerted [N] x = extension or compression of the spring [m] x/m 2.10.3 Power Power is the rate at which energy is used OR the rate at which work is done. E W P= = t t where P = power [W] E = energy [J] W = work [J] t = time [s] Chapter 2: Forces and Motion Page 12 of 14
  • 13. Hoo Sze Yen www.physicsrox.com Physics SPM 2011 2.10.4 Efficiency Efficiency is the ratio at which the output power is compared to the input power. Output power Efficiency = × 100% Input power 2.11 Maximising Efficiency The second law of thermodynamics a.k.a. the law of entropy states that in any energy transformation, some energy will be lost in the form of heat. Efficiency should be maximized in order to conserve energy resources. For example, to maximize efficiency of refrigerators: Use refrigerators that have freezers at the top instead of the side Keep the cooling coils clean Do not put the fridge too near the wall or in a room that is too hot Door seals should be in good condition Do not open the fridge door unnecessarily Defrost the fridge regularly Don’t set the thermostat low all the time Send it for repair if the motor is not working properly 2.12 Elasticity Elasticity is the ability of an object to return to its original shape and size after the applied external force applied onto it has been removed. 2.13.1 Hooke’s Law Hooke’s Law states that the extension or compression of a spring is directly proportional to the force acting on it provided the elastic limit of the spring has not been exceeded. Spring extension, x (cm) Elastic limit Tension force, F Chapter 2: Forces and Motion Page 13 of 14
  • 14. Hoo Sze Yen www.physicsrox.com Physics SPM 2011 F = kx where F = force exerted on the spring [N] Note: Because F=kx and E=½Fx, you k = spring constant [N m-1] can derive it to: x = spring extension / compression [m] E = ½ kx2 2.13.2 Spring stiffness Factors which affect the stiffness of a spring: 1) Length of spring The greater the length the spring, the lower the stiffness 2) Diameter of wire The greater the diameter of wire, the higher the stiffness 3) Diameter of coil The greater the diameter of coil, the lower the stiffness 4) Type of material 2.13.3 Spring systems Parallel arrangement Series arrangement W W The load is equally distributed among the The same load is applied to each spring. springs. If n springs are used: If n springs are used: x Total extension = nx Total extension = n END OF CHAPTER Chapter 2: Forces and Motion Page 14 of 14