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第11章 变化的电磁场
§11.1 法拉第电磁感应定律
§11.2 动生电动势
§11.3 感生电动势 涡旋电场
§11.4 自感和互感
§11.5 磁场能量
§11.6 位移电流
§11.7 麦克斯韦方程组
§11.8 电磁波的辐射和传播
§11.4 自感和互感
Self-Inductance and Mutual Inductance
Self-Inductance 自感
亨利 J. Henry 1829
self-induced emf
dt
d
L
Φ
ε −=
ISdB
s
∝⋅= ∫∫
rr
Φ
自感电动势
LI=Φ
L Self-Inductance自感系数
自感 退出返回
LI=Φ Wb/A1H1H: =SI
L is a proportionality constant that depends on the
geometry of the circuit
由回路的形状、大小及周围磁介质决定
dt
dL
I
dt
dI
L
dt
d
L −−=−=
Φ
ε
dt
dI
LL −=εIf L is constant
退出返回
If we establish a current I in a coil of N turns, the current
produces a magnetic flux through the coil.
magnetic flux linkage 磁链
线圈
NΦΦΦΨ +…++= 21
If the coil is tightly wound (closely packed), so that the
same magnetic flux passes through all the turns.
LI=ΨΦΨ N=
CAI
dt
dI
L
dt
d
L
−=−=
Ψ
ε
退出返回
Mutual Inductance 互感
12121
IM=Φ 21212 IM=Φ
211 Φ→I 122 Φ→I
互感电动势
返回 退出
dt
d 21
21
Φ
ε −=→
dt
d 12
12
Φ
ε −=→
12121 IM=Φ
21212 IM=Φ
Mutual inductance of loop 2 with respect to loop 121
M
Mutual inductance of loop 1 with respect to loop 212
M
MMM == 2112 Mutual inductance 互感系数
互感
212 MI=Φ121 MI=Φ
退出返回
212 MI=Φ
121 MI=Φ 0if =
dt
dM
dt
dI
M 1
21 −=ε
dt
dM
I
dt
dI
M
dt
d
1
121
21
−−=−=
Φ
ε
返回 退出dt
dM
I
dt
dI
M
dt
d
2
212
12 −−=−=
Φ
ε dt
dI
M 2
12 −=ε
线圈
A magnetic flux (the flux through coil 2 associated with the
current in coil 1) links the N2 turns of coil 2.
21
Φ
21221
ΦΨ N= 1
21
dt
dI
M−=ε121 MI=Ψ
dt
dI
M 2
12 −=ε212
MI=Ψ12112
ΦΨ N=
退出返回
avBavB 21 −= ⎟⎟
⎠
⎞
⎜⎜
⎝
⎛
+
−=
bxx
Iav
00
0 11
2π
µ
∫ ⋅×=
L
ldBv
rrr
)(ε
b,a,x,I 0
(1) the loop is moving to the right with speed v at
position x0
(2) the loop is rest at x0 ,
1.
0>
dt
dI ?2 =ε
(3) the loop is moving to the right with speed v at
position x0, 0>
dt
dI
?3 =ε
?1 =ε
I a
b
v
r
0x
(1)
clockwise
返回 退出
∫∫ −=
21
1
ll
vBdlvBdlε
0
000
22
0
0
x
bx
ln
Ia
adx
x
I
bx
x
+
== ∫
+
π
µ
π
µ
Φ
dt
dΦ
ε −=2
0
0
0
2 x
bx
lndt
dI
a
+
−=
π
µ
⎟⎟
⎠
⎞
⎜⎜
⎝
⎛
+
−+
+
−=
bxx
Iav
x
bxdt
dI
a
00
0
0
0
0 11
2
ln
2 π
µ
π
µ
(2)
dt
x,Id )( 0
3
Φ
ε −=
(3)
dx
0x
x
I a
b
v
r
0x a
b
I
12 εε +=
退出返回
v
r
0x a
b
I
0
00
2 x
bx
ln
Ia +
=
π
µ
Φor
MI=Φ
0
00
2 x
bx
ln
a
I
M
+
==
π
µΦ
dt
dM
I
dt
dI
M −−=3ε 21 εε +=
dt
dM
I−=1ε
dt
dI
M−=2ε
退出返回

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Phy b11 2-1

  • 1. 第11章 变化的电磁场 §11.1 法拉第电磁感应定律 §11.2 动生电动势 §11.3 感生电动势 涡旋电场 §11.4 自感和互感 §11.5 磁场能量 §11.6 位移电流 §11.7 麦克斯韦方程组 §11.8 电磁波的辐射和传播
  • 2. §11.4 自感和互感 Self-Inductance and Mutual Inductance Self-Inductance 自感 亨利 J. Henry 1829 self-induced emf dt d L Φ ε −= ISdB s ∝⋅= ∫∫ rr Φ 自感电动势 LI=Φ L Self-Inductance自感系数 自感 退出返回
  • 3. LI=Φ Wb/A1H1H: =SI L is a proportionality constant that depends on the geometry of the circuit 由回路的形状、大小及周围磁介质决定 dt dL I dt dI L dt d L −−=−= Φ ε dt dI LL −=εIf L is constant 退出返回
  • 4. If we establish a current I in a coil of N turns, the current produces a magnetic flux through the coil. magnetic flux linkage 磁链 线圈 NΦΦΦΨ +…++= 21 If the coil is tightly wound (closely packed), so that the same magnetic flux passes through all the turns. LI=ΨΦΨ N= CAI dt dI L dt d L −=−= Ψ ε 退出返回
  • 5. Mutual Inductance 互感 12121 IM=Φ 21212 IM=Φ 211 Φ→I 122 Φ→I 互感电动势 返回 退出 dt d 21 21 Φ ε −=→ dt d 12 12 Φ ε −=→
  • 6. 12121 IM=Φ 21212 IM=Φ Mutual inductance of loop 2 with respect to loop 121 M Mutual inductance of loop 1 with respect to loop 212 M MMM == 2112 Mutual inductance 互感系数 互感 212 MI=Φ121 MI=Φ 退出返回
  • 7. 212 MI=Φ 121 MI=Φ 0if = dt dM dt dI M 1 21 −=ε dt dM I dt dI M dt d 1 121 21 −−=−= Φ ε 返回 退出dt dM I dt dI M dt d 2 212 12 −−=−= Φ ε dt dI M 2 12 −=ε
  • 8. 线圈 A magnetic flux (the flux through coil 2 associated with the current in coil 1) links the N2 turns of coil 2. 21 Φ 21221 ΦΨ N= 1 21 dt dI M−=ε121 MI=Ψ dt dI M 2 12 −=ε212 MI=Ψ12112 ΦΨ N= 退出返回
  • 9. avBavB 21 −= ⎟⎟ ⎠ ⎞ ⎜⎜ ⎝ ⎛ + −= bxx Iav 00 0 11 2π µ ∫ ⋅×= L ldBv rrr )(ε b,a,x,I 0 (1) the loop is moving to the right with speed v at position x0 (2) the loop is rest at x0 , 1. 0> dt dI ?2 =ε (3) the loop is moving to the right with speed v at position x0, 0> dt dI ?3 =ε ?1 =ε I a b v r 0x (1) clockwise 返回 退出 ∫∫ −= 21 1 ll vBdlvBdlε
  • 10. 0 000 22 0 0 x bx ln Ia adx x I bx x + == ∫ + π µ π µ Φ dt dΦ ε −=2 0 0 0 2 x bx lndt dI a + −= π µ ⎟⎟ ⎠ ⎞ ⎜⎜ ⎝ ⎛ + −+ + −= bxx Iav x bxdt dI a 00 0 0 0 0 11 2 ln 2 π µ π µ (2) dt x,Id )( 0 3 Φ ε −= (3) dx 0x x I a b v r 0x a b I 12 εε += 退出返回
  • 11. v r 0x a b I 0 00 2 x bx ln Ia + = π µ Φor MI=Φ 0 00 2 x bx ln a I M + == π µΦ dt dM I dt dI M −−=3ε 21 εε += dt dM I−=1ε dt dI M−=2ε 退出返回