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Unsymmetrical Fault Analysis




       Prof. V. B. Pandya
Introduction

• After fault occurrence system becomes
  unblananced
• Types
  1.   Single line to ground ( an L – G fault)
  2.   Double line (an L – L fault)
  3.   Double line to ground (an L – L – G fault)
  4.   One conductor open fault
  5.   Two conductors open fault
• First three are shunt/short circuit faults
  and last two are series/open circuit faults
Sequence networks of generator
             Ic1



                           Ia1
                   Ib1



                    Ib2



                                 Ia2
                     Ic2

                            Ia0
                            Ib0
                            Ic0
An L – G fault
• Consider an unloaded generator with neutral grounded via
  Zn and an LG fault takes place on phase – a through Zf
                           Terminal boundary conditions:
                                             f
                            1.Va     Ia Z          IfZ      f


                            2. I b   0
                            3. I c   0

                            I a1             1     a        a2      Ia
                            Ia2      1       1     a2       a       Ib
                                         3
                            Ia0              1         1        1   Ic
                                                           Ia
                              I a1   Ia2         Ia0
                                                                3
An L – G fault cont..
• As has been seen, all three sequence currents are equal that
  shows three sequence networks viz. positive, negative and zero
  seq. networks form series interconnection with each other.
An L – G fault cont..
 • Magnitude of fault current:
           Va    Va1 Va 2        Va 0       IaZ f         I fZ f

 Va1       Ea    I a1Z1 , Va 2      0       I a 2 Z 2 , Va 0       0      I a0Z0
                                                                              f
   ( Ea      I a1Z1 ) (0       I a 2 Z 2 ) (0           Ia0 Z0 )       Ia Z
   Ea       I a1Z1     Ia2Z2     Ia0 Z0        ( I a1      Ia2     I a 0 )Z f
Since I a1       Ia2     Ia0
                       Ea
   I a1                                 f
            Z1       Z2 Z0       3Z
       f               3Ea                                 Z0      Z0 g       3Z n
   I
            Z1       Z2 Z0       3Z f
An L – L fault
• Consider an unloaded generator with neutral grounded
  via Zn and an L-L fault takes place between phases b & c




                          Terminal boundary conditions:

                               1. I a   0
                                                      f
                               2. I b       Ic    I
                                                          f
                               3.Vb     Vc       Ib Z         IfZ   f
An L – L fault conti…
                                 2
            I a1       1 a a          Ia
            Ia2     1 1 a2 a          Ib
                     3
            Ia0        1 1 1          Ic

                    1     2                1     2
   Ia0    0, I a1     (a a ), I a 2          (a a )
                    3                      3
   I a1    Ia2
An L – L fault conti…
 Va1                1     a         a2   Va
 Va 2      1        1     a2        a    Vb
                3
 Va 0               1     1         1    Vc
        1                       2             1
Va1       (Va       aVb        a Vc ), Va 2     (Va   a 2Vb   aVc )
        3                                     3
            1
      Va1      Va aVb a 2 (Vb I b Z f )
            3
            1
               Va ( a a 2 )Vb a 2 I b Z f )
            3
            1
              (Va Vb a 2 I b Z f )                            1
            3
               1 2      f 1
        Va1      a Ib Z      (Va Vb )
               3          3
An L – L fault conti…
   Similarly
          1
  Va 2        Va a 2Vb a (Vb I b Z f )
          3
           1
              Va ( a a 2 )Vb aI b Z f )
           3
           1
             (Va Vb aI b Z f )            2
           3
              1        f 1
      Va 2      aI b Z     (Va Vb )
              3          3
An L – L fault conti…
         1 2        f         1
  Va1      a Ib Z     Va 2       aI b Z f (equ1 equ 2)
         3                    3
         1 2                         f                1
  Va1      a ( I b1 I b 2 I b 0 ) Z         Va 2        a ( I b1 I b 2 I b 0 ) Z f
         3                                            3
         1 2 2                               f             1
  Va1      a (a I a1 aI a 2 I a 0 ) Z             Va 2         a (a 2 I a1 aI a 2 I a 0 )Z f
         3                                                 3
         1               f             1
  Va1      I a1 (a 1) Z    Va 2            I a 2 (a 2 1) Z f
         3                             3
         1               f             1
  Va1      I a1 (a 1) Z    Va 2            I a 2 (a 2 1) Z f
         3                             3                                                 3
                             1           f              1
Put I a1      Ia2 ,   Va1        I a1Z           Va 2      Ia2Z f
                             2                          2
                                       1
                      Va1 Va 2             ( I a1Z f I a 2 Z f ) I a1Z f           Ia2Z f
                                       2
An L – L fault conti…
          Now Va1                     Ea         I a1Z1 , Va 2     0 Ia2Z2      I a1Z 2
                   Va1 Va 2               ( Ea       I a1Z1 ) (0 I a 2 Z 2 )   I a1Z f
                   ( Ea          I a1Z1 ) ( I a1Z 2 )        I a1Z f
                                          Ea
                   I a1
                             Z1       Z2         Zf

 Now               fault current
 If           Ib          I b1      Ib 2         0
              a 2 I a1           aI a 2        I a1 (a 2    a)
          f           (a 2          a ) Ea                   j 3 Ea
      I
                     Z1          Z2        Zf          Z1     Z2       Zf
An L – L sequence network interconnection
• Zero sequence network does not appear and positive and
  negative sequence networks are connected via drop in Zf
An L – L – G fault
• Consider an unloaded generator with neutral grounded via Zn
  and an L-L-G fault takes place between phases b, c & ground
An L – L – G fault conti…
Terminal boundary conditions:
 1. I a      0           2. I b      Ic        I   f
                                                           3.Vb     Vc           IfZ   f



  Va1                    1     a         a2        Va
  Va 2           1       1     a2        a         Vb , I a       Ia0        I a1      Ia2
                     3
  Va 0                   1     1          1        Vc
Ia     Ia0       I a1         Ia2        0                               4
          1                          2                 1
Va1         (Va          aVb        a Vc )               (Va Vb )
          3                                            3                     5
          1                                            1
Va 2        (Va          a 2Vb       aVc )               (Va Vb )
          3                                            3
          1                                   1                     1
Va 0        (Va          Vb      Vc )           (Va       2Vb )       (Va        Vb ) Vb
          3                                   3                     3
An L – L – G fault conti…
                        1
         Va 0      Vb     (Va Vb )
                        3                                    6

                     f f    1
         Va 0      I Z        (Va Vb )
                            3
   From equ ns 4, 5, 6
                                   f   f     1
   Va1     Va 2      Va 0      I Z             (Va      Vb )
                                             3
          1                 1
   Ia0      ( I a Ib Ic )     (Ib                    Ic )
          3                 3
          1        f  1 f
            (0 I )        I
          3           3
       I f 3I a 0                                                          7

         Va1      Va 2      Va 0       IfZ   f
                                                 Va 0       3I a 0 Z   f
An L – L – G sequence network interconnection
• Positive, negative and zero sequence network including fault
  impedance drop are in parallel from equation 7
An L – L – G fault conti…
                                   f     f                            f
   Va1       Va 2    Va 0      I Z           Va 0         3I a 0 Z
                                                  f
   (i ) Ea      I a1Z       Va 0       3I a 0 Z
                                                          f
         Ea     I a1Z          Ia0 Z0        3I a 0 Z                     8

                         Ea    I a1Z1
         Ia0                        f
                         Z0    3Z
   (ii ) Va1        Ea    I a1Z1         Va 2         0       Ia2Z2
                         Ea    I a1Z1
         Ia2
                              Z2
                                                                              9
An L – L – G fault conti…
 As I a          I a1        Ia2      Ia0    0, put equ ns 8,9 in this one
                 Ea      I a1Z1             Ea I a1Z1
   I a1                                                      0
                        Z2                  Z 0 3Z f
             Ea            I a1Z1         Ea             I a1Z1
   I a1                                                              0
             Z2              Z2        Z 0 3Z f       Z 0 3Z f
             Z1                 Z1                    1          1
   I a1    1                                     Ea
             Z2              Z 0 3Z f                 Z2     Z 0 3Z f
                            1             1
                            Z2        Z 0 3Z f                            Z 0 3Z f    Z2
   I a1          Ea                                     Ea
                          Z1              Z1                     Z 0 3Z f Z 2   Z1 Z 0 3Z f   Z1Z 2
                        1
                          Z2           Z 0 3Z f
                                      Ea
          I a1
                                 Z 2 Z 0 3Z f
                      Z1
                                 Z2     Z 0 3Z f
Thank You

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Unsymmetrical fault analysis 2003 final new 2007

  • 1. Unsymmetrical Fault Analysis Prof. V. B. Pandya
  • 2. Introduction • After fault occurrence system becomes unblananced • Types 1. Single line to ground ( an L – G fault) 2. Double line (an L – L fault) 3. Double line to ground (an L – L – G fault) 4. One conductor open fault 5. Two conductors open fault • First three are shunt/short circuit faults and last two are series/open circuit faults
  • 3. Sequence networks of generator Ic1 Ia1 Ib1 Ib2 Ia2 Ic2 Ia0 Ib0 Ic0
  • 4. An L – G fault • Consider an unloaded generator with neutral grounded via Zn and an LG fault takes place on phase – a through Zf Terminal boundary conditions: f 1.Va Ia Z IfZ f 2. I b 0 3. I c 0 I a1 1 a a2 Ia Ia2 1 1 a2 a Ib 3 Ia0 1 1 1 Ic Ia I a1 Ia2 Ia0 3
  • 5. An L – G fault cont.. • As has been seen, all three sequence currents are equal that shows three sequence networks viz. positive, negative and zero seq. networks form series interconnection with each other.
  • 6. An L – G fault cont.. • Magnitude of fault current: Va Va1 Va 2 Va 0 IaZ f I fZ f Va1 Ea I a1Z1 , Va 2 0 I a 2 Z 2 , Va 0 0 I a0Z0 f ( Ea I a1Z1 ) (0 I a 2 Z 2 ) (0 Ia0 Z0 ) Ia Z Ea I a1Z1 Ia2Z2 Ia0 Z0 ( I a1 Ia2 I a 0 )Z f Since I a1 Ia2 Ia0 Ea I a1 f Z1 Z2 Z0 3Z f 3Ea Z0 Z0 g 3Z n I Z1 Z2 Z0 3Z f
  • 7. An L – L fault • Consider an unloaded generator with neutral grounded via Zn and an L-L fault takes place between phases b & c Terminal boundary conditions: 1. I a 0 f 2. I b Ic I f 3.Vb Vc Ib Z IfZ f
  • 8. An L – L fault conti… 2 I a1 1 a a Ia Ia2 1 1 a2 a Ib 3 Ia0 1 1 1 Ic 1 2 1 2 Ia0 0, I a1 (a a ), I a 2 (a a ) 3 3 I a1 Ia2
  • 9. An L – L fault conti… Va1 1 a a2 Va Va 2 1 1 a2 a Vb 3 Va 0 1 1 1 Vc 1 2 1 Va1 (Va aVb a Vc ), Va 2 (Va a 2Vb aVc ) 3 3 1 Va1 Va aVb a 2 (Vb I b Z f ) 3 1 Va ( a a 2 )Vb a 2 I b Z f ) 3 1 (Va Vb a 2 I b Z f ) 1 3 1 2 f 1 Va1 a Ib Z (Va Vb ) 3 3
  • 10. An L – L fault conti… Similarly 1 Va 2 Va a 2Vb a (Vb I b Z f ) 3 1 Va ( a a 2 )Vb aI b Z f ) 3 1 (Va Vb aI b Z f ) 2 3 1 f 1 Va 2 aI b Z (Va Vb ) 3 3
  • 11. An L – L fault conti… 1 2 f 1 Va1 a Ib Z Va 2 aI b Z f (equ1 equ 2) 3 3 1 2 f 1 Va1 a ( I b1 I b 2 I b 0 ) Z Va 2 a ( I b1 I b 2 I b 0 ) Z f 3 3 1 2 2 f 1 Va1 a (a I a1 aI a 2 I a 0 ) Z Va 2 a (a 2 I a1 aI a 2 I a 0 )Z f 3 3 1 f 1 Va1 I a1 (a 1) Z Va 2 I a 2 (a 2 1) Z f 3 3 1 f 1 Va1 I a1 (a 1) Z Va 2 I a 2 (a 2 1) Z f 3 3 3 1 f 1 Put I a1 Ia2 , Va1 I a1Z Va 2 Ia2Z f 2 2 1 Va1 Va 2 ( I a1Z f I a 2 Z f ) I a1Z f Ia2Z f 2
  • 12. An L – L fault conti… Now Va1 Ea I a1Z1 , Va 2 0 Ia2Z2 I a1Z 2 Va1 Va 2 ( Ea I a1Z1 ) (0 I a 2 Z 2 ) I a1Z f ( Ea I a1Z1 ) ( I a1Z 2 ) I a1Z f Ea I a1 Z1 Z2 Zf Now fault current If Ib I b1 Ib 2 0 a 2 I a1 aI a 2 I a1 (a 2 a) f (a 2 a ) Ea j 3 Ea I Z1 Z2 Zf Z1 Z2 Zf
  • 13. An L – L sequence network interconnection • Zero sequence network does not appear and positive and negative sequence networks are connected via drop in Zf
  • 14. An L – L – G fault • Consider an unloaded generator with neutral grounded via Zn and an L-L-G fault takes place between phases b, c & ground
  • 15. An L – L – G fault conti… Terminal boundary conditions: 1. I a 0 2. I b Ic I f 3.Vb Vc IfZ f Va1 1 a a2 Va Va 2 1 1 a2 a Vb , I a Ia0 I a1 Ia2 3 Va 0 1 1 1 Vc Ia Ia0 I a1 Ia2 0 4 1 2 1 Va1 (Va aVb a Vc ) (Va Vb ) 3 3 5 1 1 Va 2 (Va a 2Vb aVc ) (Va Vb ) 3 3 1 1 1 Va 0 (Va Vb Vc ) (Va 2Vb ) (Va Vb ) Vb 3 3 3
  • 16. An L – L – G fault conti… 1 Va 0 Vb (Va Vb ) 3 6 f f 1 Va 0 I Z (Va Vb ) 3 From equ ns 4, 5, 6 f f 1 Va1 Va 2 Va 0 I Z (Va Vb ) 3 1 1 Ia0 ( I a Ib Ic ) (Ib Ic ) 3 3 1 f 1 f (0 I ) I 3 3 I f 3I a 0 7 Va1 Va 2 Va 0 IfZ f Va 0 3I a 0 Z f
  • 17. An L – L – G sequence network interconnection • Positive, negative and zero sequence network including fault impedance drop are in parallel from equation 7
  • 18. An L – L – G fault conti… f f f Va1 Va 2 Va 0 I Z Va 0 3I a 0 Z f (i ) Ea I a1Z Va 0 3I a 0 Z f Ea I a1Z Ia0 Z0 3I a 0 Z 8 Ea I a1Z1 Ia0 f Z0 3Z (ii ) Va1 Ea I a1Z1 Va 2 0 Ia2Z2 Ea I a1Z1 Ia2 Z2 9
  • 19. An L – L – G fault conti… As I a I a1 Ia2 Ia0 0, put equ ns 8,9 in this one Ea I a1Z1 Ea I a1Z1 I a1 0 Z2 Z 0 3Z f Ea I a1Z1 Ea I a1Z1 I a1 0 Z2 Z2 Z 0 3Z f Z 0 3Z f Z1 Z1 1 1 I a1 1 Ea Z2 Z 0 3Z f Z2 Z 0 3Z f 1 1 Z2 Z 0 3Z f Z 0 3Z f Z2 I a1 Ea Ea Z1 Z1 Z 0 3Z f Z 2 Z1 Z 0 3Z f Z1Z 2 1 Z2 Z 0 3Z f Ea I a1 Z 2 Z 0 3Z f Z1 Z2 Z 0 3Z f