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# Note- Once you start the quiz- the timer will not stop so d start unti.docx

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# Note- Once you start the quiz- the timer will not stop so d start unti.docx

Note: Once you start the quiz, the timer will not stop so d start until you have the time complete it. DQuestion 3 Ipts At what temperature range is the reaction below, which is endothermic, spontaneous? C12(g) 2 Cl(g) ? O At all temperatures O Low temperatures O High temperatures O At no temperatures Previous Next
Solution
Since the reaction is endothermic as given in the problem
Hence, Delta H > 0
For the reaction to be spontaneous, Delta G must be negative
Delta G = Delta H - T * Delta S
Delta S will be positive for this reaction since entropy is increasing because we are forming 2 moles of gaseous products at output
Hence when temperature is high, the Delta G will become negative making it spontaneous
Hence the correct answer is C (At high temperatures)
.

Note: Once you start the quiz, the timer will not stop so d start until you have the time complete it. DQuestion 3 Ipts At what temperature range is the reaction below, which is endothermic, spontaneous? C12(g) 2 Cl(g) ? O At all temperatures O Low temperatures O High temperatures O At no temperatures Previous Next
Solution
Since the reaction is endothermic as given in the problem
Hence, Delta H > 0
For the reaction to be spontaneous, Delta G must be negative
Delta G = Delta H - T * Delta S
Delta S will be positive for this reaction since entropy is increasing because we are forming 2 moles of gaseous products at output
Hence when temperature is high, the Delta G will become negative making it spontaneous
Hence the correct answer is C (At high temperatures)
.

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### Note- Once you start the quiz- the timer will not stop so d start unti.docx

1. 1. Note: Once you start the quiz, the timer will not stop so d start until you have the time complete it. DQuestion 3 Ipts At what temperature range is the reaction below, which is endothermic, spontaneous? C12(g) 2 Cl(g) ? O At all temperatures O Low temperatures O High temperatures O At no temperatures Previous Next Solution Since the reaction is endothermic as given in the problem Hence, Delta H > 0 For the reaction to be spontaneous, Delta G must be negative Delta G = Delta H - T * Delta S Delta S will be positive for this reaction since entropy is increasing because we are forming 2 moles of gaseous products at output Hence when temperature is high, the Delta G will become negative making it spontaneous Hence the correct answer is C (At high temperatures)