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Newtons Cooling Law If you were to compare the rate of cooling of the.docx

Newtons Cooling Law
If you were to compare the rate of cooling of the soup inside a sealed styrofoam container, and inside a metal pot, which one might correspond to a larger value of k?
Solution
Rate of change of object = k ( T ( s )- T ( t ))
Where
k is the medium constant
When its hotter than surroundings: T ( t )> T ( s ), the rate of change is negative
When its cooler than surroundings: T ( t )< T ( s ), the rate of change is positive
Hence the rate of cooling the soup inside a sealed Styrofoam container correspond to a larger value of k
.

Newtons Cooling Law
If you were to compare the rate of cooling of the soup inside a sealed styrofoam container, and inside a metal pot, which one might correspond to a larger value of k?
Solution
Rate of change of object = k ( T ( s )- T ( t ))
Where
k is the medium constant
When its hotter than surroundings: T ( t )> T ( s ), the rate of change is negative
When its cooler than surroundings: T ( t )< T ( s ), the rate of change is positive
Hence the rate of cooling the soup inside a sealed Styrofoam container correspond to a larger value of k
.

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Newtons Cooling Law If you were to compare the rate of cooling of the.docx

1. 1. Newtons Cooling Law If you were to compare the rate of cooling of the soup inside a sealed styrofoam container, and inside a metal pot, which one might correspond to a larger value of k? Solution Rate of change of object = k ( T ( s )- T ( t )) Where k is the medium constant When its hotter than surroundings: T ( t )> T ( s ), the rate of change is negative When its cooler than surroundings: T ( t )< T ( s ), the rate of change is positive Hence the rate of cooling the soup inside a sealed Styrofoam container correspond to a larger value of k