1.
When 0Ne (mass 22.9945 u) decays to Na (mass Express your answer using four significant
figures 22.9898 u), what is the maximum kinetic energy of the emitted electron? Ignore recoil of
the daughter nucleus. Ke max MeV Submit Previous Answers Request Answer X Incorrect; Try
Again; 4 attempts remaining Part B What is the energy of the neutrino in this case? Express your
answer using four significant figures. MeV
Solution
10 Ne^23 ---->Â Â 11 Na ^23 + -1 e ^0
m1= 22.9945 u
m2= 22.989770 u
? m= m1-m2
?m= 0.00473u
Maximum kinetic energy will be
KE max= ( 0.00473) ( 931.5 MeV) = 4.4 Me V
when the neutrino has all of the kinetic energy, the minimumkinetic energy of the electron is 0
The sum of the kinetic energy of the electron and the energyof the neutrino must be from
?m=m1-m2 , so the energy range of the neutrion willbe 0 ? Ey ? 4.4 MeV