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Set 3 Marking Scheme : Electrochemistry 2010
Chemistry Perfect Score Module Form 4 2010 Marking Scheme Set 3 21
8.
Anode Cathode
Write the formula of all ions
present in the electrolyte.
Na+
, H+
, NO3
-
, OH-
Write the formula of ion/ions
which is/are attracted to anode
and cathode.
NO3
-
, OH-
Na+
, H+
Which is selectively
discharged?
Give a reason.
OH-
Its lower than in
electrochemical series
H+
Its lower than Na+
in
electrochemical series
Write the half equation to
represent the discharge.
4OH-
 2H2O + O2 + 4 e 2H+
+ 2e  H2
What will you observe at the
electrode?
Colourless gas evolved /
produced / liberated
Colourless gas evolved /
produced / liberated
Name the product. Oxygen gas Hydrogen gas
State the test to identify the
product.
-Place a glowing splinter inside
the test tube filled with
collected gas.
-The glowing splinter will be
rekindle.
-Place a lighted splinter near the
mouth of the test tube filled
with collected gas.
-A ‘pop’ sound is heard.
9.
Anode Cathode
Write the formula of all ions
present in the electrolyte.
K+
, H+
, OH-
, Cl-
Write the formula of ion/ions
which is/are attracted to anode
and cathode.
OH-
, Cl-
K+
, H+
Which is selectively
discharged?
Give a reason.
Cl-
The concentration of chloride
ion, Cl-
higher than OH-
.
H+
Its lower than Na+
in
electrochemical series
Write the half equation to
represent the discharge.
2Cl-
 Cl2 + 2e 2H+
+ 2e  H2
What will you observe at the
electrode?
Greenish yellow gas produced. Colourless gas evolved /
produced / liberated
Name the product. Chlorine gas Hydrogen gas
10.
Anode Cathode
Write the formula of all ions
present in the electrolyte.
Cu2+
, H+
, NO3
-
, OH-
Write the formula of ion/ions
which is/are attracted to anode
and cathode.
NO3
-
, OH-
Cu2+
, H+
Which is selectively
discharged?
Give a reason.
No ions were being discharged,
copper metal being ionized.
(factor type of electrode)
Cu2+
, Its lower than H+
in
electrochemical series.
Write the half equation to
represent the discharge.
Cu  Cu2+
+ 2e Cu2+
+ 2e  Cu
Set 3 Marking Scheme : Electrochemistry 2010
Chemistry Perfect Score Module Form 4 2010 Marking Scheme Set 3 22
What will you observe at the
electrodes?
Copper electrode becomes
thinner/ mass decreases.
Brown solid formed / mass
increases / becomes thicker
Name the product. Copper (II) ions Copper metal
What will you observe to the
electrolyte?
Explain why?
Blue solution remains. The concentration of Cu2+
in the solution
remains, because the rate of formation of Cu2+
at anode same as the
rate of discharged of Cu2+
at cathode.
11.
Negative terminal Positive terminal
State all ions present in the
electrolyte.
Cu2+
, H+
, SO4
2-
, OH-
Identify positive terminal and
negative terminal.
Explain why?
Zinc electrode, zinc is more
electropositive than copper /
zinc is higher than copper in
electrochemical series.
Copper electrode, copper is
less electropositive than zinc
/copper is lower than zinc in
electrochemical series.
Write half equation at negative
terminal.
Zn  Zn2+
+ 2e -
Write the formula of ions which
are moved to positive terminal.
- Cu2+
, H+
Which is selectively discharged?
Give a reason. -
Cu2+
, It’s lower than H+
in
electrochemical series.
Half equation at positive
terminal
- Cu2+
+ 2e  Cu
What will you observe at
negative and positive terminal?
Zinc electrode becomes
thinner / mass decreases.
Brown solid formed / mass
increases / becomes thicker
What will you observe to the
electrolyte?
Explain why?
The intensity of blue solution
decreases / blue turns
colourless/ blue becomes paler
Overall / Full ionic equation Zn + Cu2+
 Zn2+
+ Cu
14. (a) Ag  Ag+
+ e
(b) Ag+
+ e  Ag
(c) Becomes thinner / mass decreases
(d) iron covered by grey and silvery layer / becomes thicker
(e) - lower electric current is used
- the surface area of the object to be electroplated is cleaned / polished.
PAPER 2 : STRUCTURE
1. (a) X : Cathode, Y : Anode
(b) Na+
, Cl-
, H+
, OH-
(c) (i) Hydrogen
(ii) Place a lighted wooden splinter near the mouth of the test tube filled with
collected gas. A ‘pop’ sound is heard.
(iii) 2H+
+ 2e → H2
Set 3 Marking Scheme : Electrochemistry 2010
Chemistry Perfect Score Module Form 4 2010 Marking Scheme Set 3 23
(d) (i) Oxygen
(ii) Place a glowing wooden splinter inside the test tube filled with collected
gas. The glowing splinter will be rekindle.
(iii) 4OH-
→ 2H2O + O2 + 4e
(e) The product produced at the anode will be chlorine gas. Because concentration of
chloride ion, Cl-
is high.
2. (a) Cu2+
, SO4
2-
,H+
, OH-
(b) (i) Oxygen
(ii) 4OH-
→ 2H2O + O2 + 4e
(c) (i) Copper(II) ion
(ii) Cu → Cu2+
+ 2e
(d) (i) Decreases
(ii) Copper(II) ion discharged at the cathode to form copper metal.
Thus, concentration of ion decreases.
(e) (i) Remains constant
(ii) The copper(II) ion produce by copper anode is same as the copper(II) ion
been discharged at the cathode to form copper metal.
Thus, concentration of ion remains constant.
3. (a) Dilute hydrochloride acid/ Aqueous sodium chloride.
(b) Electrode X to electrode Y.
(c) Z → Z2+
+ 2e
(d) The further the distance between two metals in the Electrochemical Series, the
higher the voltage of the cell.
(e) W, Z, X, Y, V
(f) (i) Z
(ii) Voltage = (1.05 + 0.70 + 0.50)V = 2.25 V
(g) (i) W and V
(ii) Voltage = (1.55 + 0.70 + 0.50)V = 2.75 V
PAPER 2 : ESSAY
4. (a) Hydrogen gas, 2H+
+ 2e → H2
(b)
Cell X Differences Cell Y
Positive electrode/cathode :
Copper
Negative electrode/anode :
Zinc
Type of electrode
Positive electrode/anode :
Copper
Negative electrode/cathode :
Copper
Chemical energy →
electrical energy
Change of energy
Electrical energy →
chemical energy
Brown solid deposited
Observation at the
positive electrode
Copper plate dissolves
Zinc plate dissolves
Observation at the
negative electrode
Brown solids deposited
Cu2+
+ 2e → Cu
Half-equation at the
positive electrode
Cu → Cu2+
+ 2e
Zn → Zn2+
+ 2e
Half-equation at the
negative electrode
Cu2+
+ 2e → Cu
Set 3 Marking Scheme : Electrochemistry 2010
Chemistry Perfect Score Module Form 4 2010 Marking Scheme Set 3 24
(c) Material : Impure copper plate, pure copper plate, copper(II0 sulphate solution
Apparatus : Battery, connecting wires, ammeter, beaker
Diagram:
Procedure:
a. Impure copper plate is used as anode.
b. Pure copper late is used as cathode.
c. Copper(II) sulphate solution is used as electrolyte.
d. The circuit is completed by allowing the electric current to flow through the
electrolyte.
Observation :
Anode : Impure copper plate dissolved/becomes thinner.
Cathode : Pure copper plate becomes thicker/ Brown solid deposited.
Chemical equations :
Anode : Cu → Cu2+
+ 2e
Cathode : Cu2+
+ 2e → Cu
PAPER 3 : STRUCTURE
5. (a)
Metal plate Observation Inference
Zinc Zinc dissolves Zinc loses electron to form zinc ion
Iron Brown solid deposited
Copper(II) ion receives electrons to form
copper metal.
(b)
Type of variables Action to be taken
(i) Metal pairs use different pairs of metal
(ii) Voltmeter reading voltmeter readings which varies
(iii) Zinc electrode use the same zinc electrode
(c) The further the distance between two metals in the Electrochemical Series, the
higher the voltmeter reading.
(d) Between 0.4 – 1.1 V
6. (a) When the concentration of chloride ions is higher, chloride ions will be selectively
discharged at the anode.
(b) (i) Concentration of hydrochloride acid
(ii) Ions discharged at the anode
(iii) Type of electrodes, duration of electrolysis
copper(II) sulphate
solution
Pure copper plateimpure copper
plate
Set 3 Marking Scheme : Electrochemistry 2010
Chemistry Perfect Score Module Form 4 2010 Marking Scheme Set 3 25
(c)
Set 1 ( 0.001 mol dm-3
hydrochloric acid ) Set 2 ( 1.0 mol dm-3
hydrochloric acid )
Anode
Bubbles of colourless gas are released. The
gas lighted up a glowing wooden splinter.
Greenish-yellow gas is released. It turns
blue litmus paper red and then white.
Cathode
Bubbles of colourless gas are released. The
gas produces ‘pop’ sound with lighted
wooden splinter.
Bubbles of colourless gas are released.
The gas produces ‘pop’ sound with
lighted wooden splinter.
(d) Set 1 : 4OH-
→ 2H2O + O2 + 4e
Set 2 : 2 Cl-
→ Cl2 + 2e
(e) Anode : Bubbles of colourless gas are released. The gas lighted up a glowing
wooden splinter.
Cathode : Bubbles of colourless gas are released. The gas produces ‘pop’ sound
with a lighted wooden splinter.
PAPER 3 : ESSAY
7. (a) Does concentration of ions affect the product of electrolysis at the anode?
(b) The higher the concentration of ions at the anode, the higher its tendency to be
discharge.
(c) Manipulated variables : concentration of sodium chloride solution
Responding variables : product formed at anode
Controlled variables : quantity of current, carbon electrodes
(d) Materials : 0.0001 mol dm-3
sodium chloride solution, 2.0 mol dm-3
sodium chloride
solution.
Apparatus : carbon electrode, electrolytic cell, test tubes, dry cell, blue litmus paper,
wooden splinter, Bunsen burner.
(e) Procedure :
1. Electrolytic cell is filled with 0.0001 mol dm-3
sodium chloride solution.
2. The carbon electrodes are connected to the power supply and ammeter.
3. Current is passed through into 0.0001 mol dm-3
sodium chloride solution for
half hour.
4. The gas collected at the anode is tested with a glowing wooden splinter and a
damp blue litmus paper.
5. Experiment is repeated by replacing 0.0001 mol dm-3
sodium chloride
solution with 2.0 mol dm-3
sodium chloride solution.
(f) Tabulation of data:
Solution Observation Product formed at anode
0.0001 mol dm-3
sodium chloride
solution
2.0 mol dm-3
sodium chloride
solution
Set 3 Marking Scheme : Electrochemistry 2010
Chemistry Perfect Score Module Form 4 2010 Marking Scheme Set 3 26
8.
Question
Number
Rubric Score
(a)
[ Able to give the aim of the experiment correctly ]
Example :
To construct the electrochemical series based on the potential differences between
metals
3
(b)
[ Able to state All variables correctly ]
Example :
Manipulated variable : Pairs of different metals//Different types of metals
Responding variable : Potential differences
Constant variable : Concentration of Copper(II) sulphate, positive terminal
3
(c)
[ Able to give the hypothesis correctly]
Example :
The distance between two metals increase/decrease, the potential difference will
increase/ decrease
3
(d)
[ Able to give the list of the apparatus and materials correctly and completely]
Example :
List of apparatus and materials
Copper strip, lead strip, iron strip, zinc strip, aluminium strip, magnesium strip,
copper (II) sulphate solution, sand paper, voltmeter, beaker, connecting wires with
crocodile clip
3
(e)
[ Able to state all procedures correctly ]
Example :
1. Clean the metals with sand paper
2. Fill a beaker with copper(II)sulphate solution
3. Dip/ place/ immerse the magnesium strip and copper strip into the
copper(II)sulphate solution
4. Connect the electrodes to voltmeter using connecting wire with crocodile clip.
5.. Complete the circuit//switch-on the circuit
6. Record the potential difference between the metals
7. Determine and record which metal strip is the negative terminal
8. Repeat steps 1 to 6 using other metals to replace magnesium strip
3
(f)
[ Able to exhibit the tabulation of data correctly ]
Tabulation of data has the following element :
1. 3 columns and 6 rows
Example :
Pair of metals Potential difference (V) Negative terminal
Mg and Cu
Al and Cu
Zn and Cu
Pb and Cu
Fe and Cu
3

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PS F4 Set 3

  • 1. Set 3 Marking Scheme : Electrochemistry 2010 Chemistry Perfect Score Module Form 4 2010 Marking Scheme Set 3 21 8. Anode Cathode Write the formula of all ions present in the electrolyte. Na+ , H+ , NO3 - , OH- Write the formula of ion/ions which is/are attracted to anode and cathode. NO3 - , OH- Na+ , H+ Which is selectively discharged? Give a reason. OH- Its lower than in electrochemical series H+ Its lower than Na+ in electrochemical series Write the half equation to represent the discharge. 4OH-  2H2O + O2 + 4 e 2H+ + 2e  H2 What will you observe at the electrode? Colourless gas evolved / produced / liberated Colourless gas evolved / produced / liberated Name the product. Oxygen gas Hydrogen gas State the test to identify the product. -Place a glowing splinter inside the test tube filled with collected gas. -The glowing splinter will be rekindle. -Place a lighted splinter near the mouth of the test tube filled with collected gas. -A ‘pop’ sound is heard. 9. Anode Cathode Write the formula of all ions present in the electrolyte. K+ , H+ , OH- , Cl- Write the formula of ion/ions which is/are attracted to anode and cathode. OH- , Cl- K+ , H+ Which is selectively discharged? Give a reason. Cl- The concentration of chloride ion, Cl- higher than OH- . H+ Its lower than Na+ in electrochemical series Write the half equation to represent the discharge. 2Cl-  Cl2 + 2e 2H+ + 2e  H2 What will you observe at the electrode? Greenish yellow gas produced. Colourless gas evolved / produced / liberated Name the product. Chlorine gas Hydrogen gas 10. Anode Cathode Write the formula of all ions present in the electrolyte. Cu2+ , H+ , NO3 - , OH- Write the formula of ion/ions which is/are attracted to anode and cathode. NO3 - , OH- Cu2+ , H+ Which is selectively discharged? Give a reason. No ions were being discharged, copper metal being ionized. (factor type of electrode) Cu2+ , Its lower than H+ in electrochemical series. Write the half equation to represent the discharge. Cu  Cu2+ + 2e Cu2+ + 2e  Cu
  • 2. Set 3 Marking Scheme : Electrochemistry 2010 Chemistry Perfect Score Module Form 4 2010 Marking Scheme Set 3 22 What will you observe at the electrodes? Copper electrode becomes thinner/ mass decreases. Brown solid formed / mass increases / becomes thicker Name the product. Copper (II) ions Copper metal What will you observe to the electrolyte? Explain why? Blue solution remains. The concentration of Cu2+ in the solution remains, because the rate of formation of Cu2+ at anode same as the rate of discharged of Cu2+ at cathode. 11. Negative terminal Positive terminal State all ions present in the electrolyte. Cu2+ , H+ , SO4 2- , OH- Identify positive terminal and negative terminal. Explain why? Zinc electrode, zinc is more electropositive than copper / zinc is higher than copper in electrochemical series. Copper electrode, copper is less electropositive than zinc /copper is lower than zinc in electrochemical series. Write half equation at negative terminal. Zn  Zn2+ + 2e - Write the formula of ions which are moved to positive terminal. - Cu2+ , H+ Which is selectively discharged? Give a reason. - Cu2+ , It’s lower than H+ in electrochemical series. Half equation at positive terminal - Cu2+ + 2e  Cu What will you observe at negative and positive terminal? Zinc electrode becomes thinner / mass decreases. Brown solid formed / mass increases / becomes thicker What will you observe to the electrolyte? Explain why? The intensity of blue solution decreases / blue turns colourless/ blue becomes paler Overall / Full ionic equation Zn + Cu2+  Zn2+ + Cu 14. (a) Ag  Ag+ + e (b) Ag+ + e  Ag (c) Becomes thinner / mass decreases (d) iron covered by grey and silvery layer / becomes thicker (e) - lower electric current is used - the surface area of the object to be electroplated is cleaned / polished. PAPER 2 : STRUCTURE 1. (a) X : Cathode, Y : Anode (b) Na+ , Cl- , H+ , OH- (c) (i) Hydrogen (ii) Place a lighted wooden splinter near the mouth of the test tube filled with collected gas. A ‘pop’ sound is heard. (iii) 2H+ + 2e → H2
  • 3. Set 3 Marking Scheme : Electrochemistry 2010 Chemistry Perfect Score Module Form 4 2010 Marking Scheme Set 3 23 (d) (i) Oxygen (ii) Place a glowing wooden splinter inside the test tube filled with collected gas. The glowing splinter will be rekindle. (iii) 4OH- → 2H2O + O2 + 4e (e) The product produced at the anode will be chlorine gas. Because concentration of chloride ion, Cl- is high. 2. (a) Cu2+ , SO4 2- ,H+ , OH- (b) (i) Oxygen (ii) 4OH- → 2H2O + O2 + 4e (c) (i) Copper(II) ion (ii) Cu → Cu2+ + 2e (d) (i) Decreases (ii) Copper(II) ion discharged at the cathode to form copper metal. Thus, concentration of ion decreases. (e) (i) Remains constant (ii) The copper(II) ion produce by copper anode is same as the copper(II) ion been discharged at the cathode to form copper metal. Thus, concentration of ion remains constant. 3. (a) Dilute hydrochloride acid/ Aqueous sodium chloride. (b) Electrode X to electrode Y. (c) Z → Z2+ + 2e (d) The further the distance between two metals in the Electrochemical Series, the higher the voltage of the cell. (e) W, Z, X, Y, V (f) (i) Z (ii) Voltage = (1.05 + 0.70 + 0.50)V = 2.25 V (g) (i) W and V (ii) Voltage = (1.55 + 0.70 + 0.50)V = 2.75 V PAPER 2 : ESSAY 4. (a) Hydrogen gas, 2H+ + 2e → H2 (b) Cell X Differences Cell Y Positive electrode/cathode : Copper Negative electrode/anode : Zinc Type of electrode Positive electrode/anode : Copper Negative electrode/cathode : Copper Chemical energy → electrical energy Change of energy Electrical energy → chemical energy Brown solid deposited Observation at the positive electrode Copper plate dissolves Zinc plate dissolves Observation at the negative electrode Brown solids deposited Cu2+ + 2e → Cu Half-equation at the positive electrode Cu → Cu2+ + 2e Zn → Zn2+ + 2e Half-equation at the negative electrode Cu2+ + 2e → Cu
  • 4. Set 3 Marking Scheme : Electrochemistry 2010 Chemistry Perfect Score Module Form 4 2010 Marking Scheme Set 3 24 (c) Material : Impure copper plate, pure copper plate, copper(II0 sulphate solution Apparatus : Battery, connecting wires, ammeter, beaker Diagram: Procedure: a. Impure copper plate is used as anode. b. Pure copper late is used as cathode. c. Copper(II) sulphate solution is used as electrolyte. d. The circuit is completed by allowing the electric current to flow through the electrolyte. Observation : Anode : Impure copper plate dissolved/becomes thinner. Cathode : Pure copper plate becomes thicker/ Brown solid deposited. Chemical equations : Anode : Cu → Cu2+ + 2e Cathode : Cu2+ + 2e → Cu PAPER 3 : STRUCTURE 5. (a) Metal plate Observation Inference Zinc Zinc dissolves Zinc loses electron to form zinc ion Iron Brown solid deposited Copper(II) ion receives electrons to form copper metal. (b) Type of variables Action to be taken (i) Metal pairs use different pairs of metal (ii) Voltmeter reading voltmeter readings which varies (iii) Zinc electrode use the same zinc electrode (c) The further the distance between two metals in the Electrochemical Series, the higher the voltmeter reading. (d) Between 0.4 – 1.1 V 6. (a) When the concentration of chloride ions is higher, chloride ions will be selectively discharged at the anode. (b) (i) Concentration of hydrochloride acid (ii) Ions discharged at the anode (iii) Type of electrodes, duration of electrolysis copper(II) sulphate solution Pure copper plateimpure copper plate
  • 5. Set 3 Marking Scheme : Electrochemistry 2010 Chemistry Perfect Score Module Form 4 2010 Marking Scheme Set 3 25 (c) Set 1 ( 0.001 mol dm-3 hydrochloric acid ) Set 2 ( 1.0 mol dm-3 hydrochloric acid ) Anode Bubbles of colourless gas are released. The gas lighted up a glowing wooden splinter. Greenish-yellow gas is released. It turns blue litmus paper red and then white. Cathode Bubbles of colourless gas are released. The gas produces ‘pop’ sound with lighted wooden splinter. Bubbles of colourless gas are released. The gas produces ‘pop’ sound with lighted wooden splinter. (d) Set 1 : 4OH- → 2H2O + O2 + 4e Set 2 : 2 Cl- → Cl2 + 2e (e) Anode : Bubbles of colourless gas are released. The gas lighted up a glowing wooden splinter. Cathode : Bubbles of colourless gas are released. The gas produces ‘pop’ sound with a lighted wooden splinter. PAPER 3 : ESSAY 7. (a) Does concentration of ions affect the product of electrolysis at the anode? (b) The higher the concentration of ions at the anode, the higher its tendency to be discharge. (c) Manipulated variables : concentration of sodium chloride solution Responding variables : product formed at anode Controlled variables : quantity of current, carbon electrodes (d) Materials : 0.0001 mol dm-3 sodium chloride solution, 2.0 mol dm-3 sodium chloride solution. Apparatus : carbon electrode, electrolytic cell, test tubes, dry cell, blue litmus paper, wooden splinter, Bunsen burner. (e) Procedure : 1. Electrolytic cell is filled with 0.0001 mol dm-3 sodium chloride solution. 2. The carbon electrodes are connected to the power supply and ammeter. 3. Current is passed through into 0.0001 mol dm-3 sodium chloride solution for half hour. 4. The gas collected at the anode is tested with a glowing wooden splinter and a damp blue litmus paper. 5. Experiment is repeated by replacing 0.0001 mol dm-3 sodium chloride solution with 2.0 mol dm-3 sodium chloride solution. (f) Tabulation of data: Solution Observation Product formed at anode 0.0001 mol dm-3 sodium chloride solution 2.0 mol dm-3 sodium chloride solution
  • 6. Set 3 Marking Scheme : Electrochemistry 2010 Chemistry Perfect Score Module Form 4 2010 Marking Scheme Set 3 26 8. Question Number Rubric Score (a) [ Able to give the aim of the experiment correctly ] Example : To construct the electrochemical series based on the potential differences between metals 3 (b) [ Able to state All variables correctly ] Example : Manipulated variable : Pairs of different metals//Different types of metals Responding variable : Potential differences Constant variable : Concentration of Copper(II) sulphate, positive terminal 3 (c) [ Able to give the hypothesis correctly] Example : The distance between two metals increase/decrease, the potential difference will increase/ decrease 3 (d) [ Able to give the list of the apparatus and materials correctly and completely] Example : List of apparatus and materials Copper strip, lead strip, iron strip, zinc strip, aluminium strip, magnesium strip, copper (II) sulphate solution, sand paper, voltmeter, beaker, connecting wires with crocodile clip 3 (e) [ Able to state all procedures correctly ] Example : 1. Clean the metals with sand paper 2. Fill a beaker with copper(II)sulphate solution 3. Dip/ place/ immerse the magnesium strip and copper strip into the copper(II)sulphate solution 4. Connect the electrodes to voltmeter using connecting wire with crocodile clip. 5.. Complete the circuit//switch-on the circuit 6. Record the potential difference between the metals 7. Determine and record which metal strip is the negative terminal 8. Repeat steps 1 to 6 using other metals to replace magnesium strip 3 (f) [ Able to exhibit the tabulation of data correctly ] Tabulation of data has the following element : 1. 3 columns and 6 rows Example : Pair of metals Potential difference (V) Negative terminal Mg and Cu Al and Cu Zn and Cu Pb and Cu Fe and Cu 3