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Equivalent Circuit
101 / 102 Basic Electrical Technology Dept of E & E, MIT Manipal
R1 X1
LOAD
Rc Xm
V1
R2 X2r=sX
2
I1
E1
Er= s E2
Ic Im
Rotor
Air Gap
StatorStator
V1 = Supply voltage
R1 = Stator Winding
Resistance
X1 = Stator Leakage
Reactance
I1 = Stator Winding Current
Rc = Core Loss Resistance
Xm = Magnetising
Rotor
Er = Rotor Induced Emf under Running
Conditions
s = Operating Slip
E2 = Standstill Rotor Induced Emf
R2 = Rotor Winding
X2 = Rotor Leakage Reactance at Standstill
X2r = Rotor Leakage Reactance under Running
Condition
Rotor Equivalent circuit
101 / 102 Basic Electrical Technology Dept of E & E, MIT Manipal
• Rotor windings offer resistance, represented by R2
• Presence of leakage flux, represented by X2
Standstill Operating
Emf E2 E2r = s E2
Resistan
ce
R2 R2
Reactanc
e
X2 X2r = s X2
Impedan
ce
Z2= R2 + j
X2
Z2r= R2 + j ( s
X2 )
Current I2 I2r
R2 X2r
E2r
I2r
Rotor Equivalent circuit cont’d …
101 / 102 Basic Electrical Technology Dept of E & E, MIT Manipal
X2
E2 I2r
s
R2
2
2
2
r22
r2
r2
Xj
s
R
E
XjR
E
I
+
=
+
=
X2
s
R2
E2 I2r






−= 1
s
1
RR 2LR2
X2
E
2
I2r
Mechanical load on the motor is represented by






−= 1
s
1
RR 2L
Power Output
101 / 102 Basic Electrical Technology Dept of E & E, MIT Manipal






−= 1
s
1
RR 2LR2
X2
E2
I2r
Gross Power Output
(Rotor Output)






−= 1
s
1
RI3P 2
2
2Gross
Net Power output
(actual Power output
or Shaft output)
PNet = PGross – PFriction & Windage Loss
Power Stages
101 / 102 Basic Electrical Technology Dept of E & E, MIT Manipal 1
Stator
Input
Stator
Losses
Stator Copper Loss
Core Loss
Stator Output
(Rotor Input)
Gross Power
Output
Net
Output
Other
Losses
Friction & Windage Loss
Stator Input = Motor Input (PIN) = √3 VLILCosΦ
Stator Losses = Stator Copper Loss (PSCU) + Core Loss (PCO) =
3I1
2
R1+ PCOtator Output = Stator Input - Stator Losses
Rotor Input = Stator Output
Rotor Losses = Rotor Copper Loss (PRCU) = 3I2
2
R2
Gross Power Output (Pg) = Rotor Input -
Rotor LossesPower Output (PO) = Gross Power Output (Pg) – Friction & Windage Losses (P
InputPowerMotor
OutputPowerNet
ηEfficiency =
Rotor Copper Loss
Rotor
Losses
Relationship between Rotor Quantities
101 / 102 Basic Electrical Technology Dept of E & E, MIT Manipal 2
• Pg = Gross output, Prcu = Rotor copper loss, P2 = Rotor input
Power transferred from stator to rotor = Rotor input =
60
TN2π
P s
2 =
Gross Power developed by the rotor =
60
TN2π
Pg =
Rotor copper loss, Prcu = P2 - Pg
2rcu PsP =
Rotor input (P2) = Rotor copper loss (Prcu) + Gross output (Pg)
2g Ps)-(1P =
s)(1:s:1P:P:P grcu2 −=
s
N
NN
P
P
S
Srcu
=
−
=
2
Relationship between Rotor Quantities
101 / 102 Basic Electrical Technology Dept of E & E, MIT Manipal 2
• Pg = Gross output, Prcu = Rotor copper loss, P2 = Rotor input
Power transferred from stator to rotor = Rotor input =
60
TN2π
P s
2 =
Gross Power developed by the rotor =
60
TN2π
Pg =
Rotor copper loss, Prcu = P2 - Pg
2rcu PsP =
Rotor input (P2) = Rotor copper loss (Prcu) + Gross output (Pg)
2g Ps)-(1P =
s)(1:s:1P:P:P grcu2 −=
s
N
NN
P
P
S
Srcu
=
−
=
2

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L37 3 ph-im

  • 1. Equivalent Circuit 101 / 102 Basic Electrical Technology Dept of E & E, MIT Manipal R1 X1 LOAD Rc Xm V1 R2 X2r=sX 2 I1 E1 Er= s E2 Ic Im Rotor Air Gap StatorStator V1 = Supply voltage R1 = Stator Winding Resistance X1 = Stator Leakage Reactance I1 = Stator Winding Current Rc = Core Loss Resistance Xm = Magnetising Rotor Er = Rotor Induced Emf under Running Conditions s = Operating Slip E2 = Standstill Rotor Induced Emf R2 = Rotor Winding X2 = Rotor Leakage Reactance at Standstill X2r = Rotor Leakage Reactance under Running Condition
  • 2. Rotor Equivalent circuit 101 / 102 Basic Electrical Technology Dept of E & E, MIT Manipal • Rotor windings offer resistance, represented by R2 • Presence of leakage flux, represented by X2 Standstill Operating Emf E2 E2r = s E2 Resistan ce R2 R2 Reactanc e X2 X2r = s X2 Impedan ce Z2= R2 + j X2 Z2r= R2 + j ( s X2 ) Current I2 I2r R2 X2r E2r I2r
  • 3. Rotor Equivalent circuit cont’d … 101 / 102 Basic Electrical Technology Dept of E & E, MIT Manipal X2 E2 I2r s R2 2 2 2 r22 r2 r2 Xj s R E XjR E I + = + = X2 s R2 E2 I2r       −= 1 s 1 RR 2LR2 X2 E 2 I2r Mechanical load on the motor is represented by       −= 1 s 1 RR 2L
  • 4. Power Output 101 / 102 Basic Electrical Technology Dept of E & E, MIT Manipal       −= 1 s 1 RR 2LR2 X2 E2 I2r Gross Power Output (Rotor Output)       −= 1 s 1 RI3P 2 2 2Gross Net Power output (actual Power output or Shaft output) PNet = PGross – PFriction & Windage Loss
  • 5. Power Stages 101 / 102 Basic Electrical Technology Dept of E & E, MIT Manipal 1 Stator Input Stator Losses Stator Copper Loss Core Loss Stator Output (Rotor Input) Gross Power Output Net Output Other Losses Friction & Windage Loss Stator Input = Motor Input (PIN) = √3 VLILCosΦ Stator Losses = Stator Copper Loss (PSCU) + Core Loss (PCO) = 3I1 2 R1+ PCOtator Output = Stator Input - Stator Losses Rotor Input = Stator Output Rotor Losses = Rotor Copper Loss (PRCU) = 3I2 2 R2 Gross Power Output (Pg) = Rotor Input - Rotor LossesPower Output (PO) = Gross Power Output (Pg) – Friction & Windage Losses (P InputPowerMotor OutputPowerNet ηEfficiency = Rotor Copper Loss Rotor Losses
  • 6. Relationship between Rotor Quantities 101 / 102 Basic Electrical Technology Dept of E & E, MIT Manipal 2 • Pg = Gross output, Prcu = Rotor copper loss, P2 = Rotor input Power transferred from stator to rotor = Rotor input = 60 TN2π P s 2 = Gross Power developed by the rotor = 60 TN2π Pg = Rotor copper loss, Prcu = P2 - Pg 2rcu PsP = Rotor input (P2) = Rotor copper loss (Prcu) + Gross output (Pg) 2g Ps)-(1P = s)(1:s:1P:P:P grcu2 −= s N NN P P S Srcu = − = 2
  • 7. Relationship between Rotor Quantities 101 / 102 Basic Electrical Technology Dept of E & E, MIT Manipal 2 • Pg = Gross output, Prcu = Rotor copper loss, P2 = Rotor input Power transferred from stator to rotor = Rotor input = 60 TN2π P s 2 = Gross Power developed by the rotor = 60 TN2π Pg = Rotor copper loss, Prcu = P2 - Pg 2rcu PsP = Rotor input (P2) = Rotor copper loss (Prcu) + Gross output (Pg) 2g Ps)-(1P = s)(1:s:1P:P:P grcu2 −= s N NN P P S Srcu = − = 2