There are NO thumb Rules in Oracle. Different Versions of Oracle and data Patterns Drives the SQL performance !!!!
This presentation is just to introduce as to How CBO workouts the SQL plans That probably will help you to find what is suitable for given SQL.
How you write a SQL, it matters !!!!
2. Highlights
Background of CBO
Oracle Database Memory Structures
Table Scans
CPU Costing Model
Index and Clustering Factor
Dynamic Sampling and Histogram
Query transformation
Join Methodologies
There are NO thumb Rules in Oracle. Different Versions of Oracle and data
Patterns Drives the SQL performance !!!!
This presentation is just to introduce as to How CBO workouts the SQL plans
That probably will help you to find what is suitable for given SQL.
How you write a SQL, it matters !!!!
2
3. Cost Based Optimization : Evolution
• Traditional : Simple counting of read requests
• System statistics (1) : Accounting for size and time of read requests
• System statistics (2) : Accounting for size and time of read requests and
CPU costs
• System statistics (3) : Accounting for size and time of read requests and
CPU costs and caching.
3
5. Three different layers of operational complexity
• First : The execution plan tells you what the optimizer thinks is going to
happen at run time, and produces a cost based on this model.
• Second : The execution engine starts up and executes the model dictated by
the optimizer- but the actual mechanism is not always identical to the
model (alternatively, the model is not a good description of what
actually happens).
• Finally: there are cases where the resources required to execute the model
vary dramatically with the way in which the incoming data happens to
be distributed.
In other words, the optimizer’s execution plan may not be exactly the run-
time execution path, and the speed of the run-time execution path may be
affected by an unlucky choice of data.
5
6. When CBO makes errors
• Some inappropriate assumptions are built into the cost model.
• The relevant statistics about the data distribution are available, but
misleading.
• The relevant statistics about the data distribution are not available.
• The performance characteristics of the hardware are not known.
• The current workload is not known.
• There are bugs in the code.
6
8. Table Scans
1. db_file_multiblock_read_count :
Multiple block read count allowed in single IO operation.
Is always set to the maximum allowed by the operating system by
default.
Oracle Calculates the IO cost based on the MBRC and system
statistics.
When Oracle executes the tablescan, how many blocks does it try
to read in a multiblock read? Is it the value of MBRCor something
else?
Answer: Oracle still tries to use the actual value for
db_file_multiblock_read_count—scaled up or down if we are
reading from a tablespace with a nondefault block size.
If workload statistics are not gathered then system uses non
workload stats.
8
9. Table Scans
2. Full Table Scan:
When performing a full table scan, it reads the blocks of the table into
buffers and puts them on the LRU end (instead of the MRU end) of the
LRU list.
This is because a fully scanned table usually is needed only briefly, so the
blocks should be moved out quickly to leave more frequently used
blocks in the cache.
You can control this default behavior on a table-by-table basis.
To specify that blocks of the table are to be placed at the MRU end of
the list during a full table scan, use the CACHE clause when creating or
altering a table or cluster.
You can specify this behavior for small lookup tables (Keep pool) or large
static historical tables(Recycle pool) to avoid I/O on subsequent
accesses of the table.
Transactional table MUST not be added to CACHE.
9
10. Table Scans
3. Parallel Execution: (/*+ PARALLEL */ or ALTER TABLE <<T1>> PARALLEL)
I. The user session or shadow process takes on the role of a
coordinator, often called the query coordinator and necessary
number of parallel slave processes.
II. The SQL statement is executed as a sequence of operations.
While the parallel slaves are executing, the query coordinator
performs any portion of the work that cannot be executed in
parallel.
III. Finally, the query coordinator returns results to the user.
Parallel scans use direct path reads to bypass the data buffer and read
blocks directly into local (PGA) memory.
A parallel query will first issue a segment checkpoint to get all dirty blocks
status for the segment written to disk before it reads.
This could lead to a performance problem in rare cases that mixed a large
data buffer, a busy OLTP system, and parallel execution for reports.
10
12. What is Cost ?
According to the CPU costing model:
Cost = (
#SRds * sreadtim +
#MRds * mreadtim +
#CPUCycles / cpuspeed
) / sreadtim
where,
#SRDs - number of single block reads
#MRDs - number of multi block reads
#CPUCycles - number of CPU Cycles
sreadtim - single block read time
mreadtim - multi block read time
cpuspeed - CPU cycles per second
Translated,
The cost is the time spent on single-block reads, plus the time spent on multi block
reads, plus the CPU time required, all divided by the time it takes to do a single-
block read.
12
13. Statistics
Optimizer statistics are a collection of data that describe more details about the
database and the objects in the database.
Optimizer statistics includes :
Table statistics
Number of rows
Number of blocks USER_TABLES / DBA_TABLES
Average row length
Column statistics
Number of distinct values (NDV) in column
USER_TAB_COLUMNS /
Number of nulls in column
DBA_TAB_COLUMNS
Data distribution (histogram)
Average Column length
Index statistics
Number of leaf blocks USER_INDEXES
Levels
Clustering factor
System statistics
I/O performance and utilization DBA_TAB_STATISTICS
CPU performance and utilization 13
14. Cardinality (Selectivity)
In an audience of 1,200 people. How many of them do you think were
born in December? And What if 120 of them don’t remember their birth date ?
Optimizer is thinking ....
• Base selectivity = 1/12 (from density or from 1/num_distinct)
user_tab_col_statistics.num_nulls = 0 user_tab_col_statistics.
• num_nulls = 120 & num_rows = 1200
user_tab_col_statistics.num_distinct = 12 user_tab_col_statistics.n
/13?
• Adjusted selectivity = Base selectivity * (num_rows - num_nulls)
user_tab_histograms.low_value = 1 user_tab_histograms.low
num_rows
user_tab_histograms.high_value = 12 user_tab_histograms.hig
• Adjusted selectivity = (1/12) * ((1200 - 120)/1200) = 0.075
user_tables.num_rows = 1,200 user_tables.num_rows =
• Adjusted cardinality = Adjusted selectivity * num_rows
• So, user_tab_col_statistics.Density = 1/12
Adjusted cardinality = 0.075 * 1200 = 90 So, user_tab_col_statist
Cardinality = 100 Cardinality = 90
Cardinality = num_rows / num_distinct (If no histogram is prepared )
Cardinality = num_rows * density (If histogram is prepared ) 14
15. Cardinality (Selectivity)
Basic formulae of Selectivity :
The selectivity of (predicate1 AND predicate2) =
Selectivity of (predicate1) * Selectivity of (predicate2).
The selectivity of (predicate1 OR predicate2) =
selectivity of (predicate1) + selectivity of (predicate2) minus
selectivity of (predicate1 AND predicate2)
... otherwise, you’ve counted the overlap twice.
The selectivity of (NOT predicate1) = 1 – selectivity of (predicate1)
Range Selectivity = “required range” divided by “total available range”
Cardinality :
Cardinality = Selectivity * num_rows
15
16. Index
Cost = blevel +
ceiling(leaf_blocks * effective index selectivity) +
ceiling(clustering_factor * effective table selectivity)
Translated,
Cost to reach to, the Level of index node from root in Balanced B-Tree + number of
leaf blocks to be walk through to get rowids + cost to access table.
B+ Tree Index :
To Scan the index segment oracle uses Binary tree travels algorithm.
The depth of B+ Tree varies from 1 to 4. Mostly its 2 or 3 and Max 4 for larger table
index
16
18. Index: Clustering Factor
SELECT /*+
cursor_sharing_exact
dynamic_sampling(0)
no_monitoring
no_expand
index (t,"AWBMST_DPUDATE")
noparallel_index(t,"AWBMST_DPUDATE")
*/
Sys_op_countchg(substrb(t.rowid,1,15),&m_history) as clf
FROM AWBMST T;
WHERE DPUDATE IS NOT NULL;
• &m_history represent the number of block visited most recently. This value should be
freelists value of table or 16 in case of ASSM tablespace.
• use dbms_stats.get_index_stats and dbms_stats.set_index_stats to set the correct
value of Clustering factor.
• This should be used only for critical indexes where you find default method of oracle
giving you a wrong statistics and it not recommended to apply for all index always.
18
19. Index: Selection
1. Range-based predicate (e.g., col1 between 1 and 3) would reduce the
benefit of later columns in the index. Any predicates based on columns
appearing after the earliest range-based predicate would be ignored
when calculating the effective index selectivity—although they would
still be used in the effective table selectivity—and this could leave Oracle
with an unreasonably high figure for the cost of that index.
Columns that usually appeared with a range-based predicate toward the
end of the index definition.
2. For improving the compressibility of an index, Put the least selective
(most repetitive) columns first.
3. Re-arranging the column sequence in the index changes the
clustering_factor and Index Selectivity...
4. Appearance of column sequence in there WHERE clause does not affect
the index selectivity.
5. If Index in unique in nature then do create them as UK index instead of
normal index, other wise Optimizer has to refer Histogram and figure
out the index uniqueness. That changes optimizers access path option.
19
20. Dynamic Sampling
How and when will DS be use?
During the compilation of a SQL statement, the optimizer decides whether to
use DS or not by considering whether the available statistics are sufficient to
generate a good execution plan. If,
1. Available table statistics are not enough.
2. When the statement contains a complex predicate expression and
extended statistics are not available.
OPTIMIZER_DYNAMIC_SAMPLING
Parameter defines the number of blacks to read for Sampling.
It can have value from 0 to 10. Default is 2.
More the value if DS parameter, more time it takes to compile the SQL
Statement.
20
21. Histogram
Histograms feature in Oracle helps optimizer to determine how data is skewed
(distributed) with in the column
Advantage of Histogram :
1. Histograms are useful for Oracle optimizer to choose the right access
method in a table.
2. It is also useful for optimizer to decide the correct table join order. When
we join multiple tables, histogram helps to minimize the intermediate
result set. Since the smaller size of the intermediate result set will
improve the performance.
21
22. Query transformation
1. Join elimination (JE) :
A technique in which one or more tables can be eliminated from the
execution plan without altering functional behaviour.
22
23. Query transformation
1. Join elimination (JE) :
Example 2 : Elimination by Constraints or reference,
Following table T1 and T2 has FK constraints over T1.N1 and T2.N2 and SQL is
selecting data only from T2 table. So, No need to check if the Key is exists in
T1 and join can be eliminated safely…
23
24. Query transformation
2. Subquery Unnesting :
Subqueries can be unnested in to a join.
Oracle executes a sub query
Subquery is unnested in to a view and then joined to other row sources.
once for each distinct value
In this listing, a correlated subquery is moved in to a view VW_SQ_1,Hashes
from driving table and
unnested and then joined using Hash Join technique. subsequent rows it will
it. For
use the same results from
Hash table instead of re-
executing sub query.
24
26. IN Vs EXISTS , NOT IN Vs NOT EXISTS
What to use ? Why ?
Depends !
Why there is Myth ......
Up to oracle 8i optimizer has suffer through the cardinality approximation issue.
select * from AUDIENCE where month_no in ( 6, 7, 8);
Actual problem :
Internally, the optimizer will convert a predicate in to OR clauses.
The error that 8i suffers from is that after splitting the list into separate
predicates, it applies the standard algorithm for multiple disjuncts (the
technical term for OR’ed predicates) and Fails to process it correctly.
sel(A or B or C) = sel(A) + sel(B) + sel(C) – Sel(A)sel(B) – Sel(B)sel(C) –
sel(C)sel(A) + Sel(A)Sel(B)Sel(C)
Good News, Oracle 9i/10g onwords this issue has been address perfectly !!!
But if you have large set of values then its good to have table type instead of IN LIST as
Table type will allow CBO to rewrite the SQL and use Semi-Nested loop Join for better data
retrieval.
How ??? Stay tuned...... 26
27. IN Vs EXISTS
Then Who and When ???
Both the SQLs gives same Explain plan and Elapse time in this case...
If the main body of your query is highly selective, then an EXISTS clause might be more
appropriate to semi-join to the target table.
if the main body of your query is not so selective (over join Predicate) and the subquery (the
target of the semi-join) is more selective, then an IN clause might be more appropriate.
Good News, This rule is valid only for 8i (or earlier) systems. 9i and later versions it doesn’t matter
much both works same in most of the cases. Still you will have to check for specific cases.
IN and EXISTS uses Semi – Join technique. A “semi-join” between two tables returns rows
from the first table where one or more matches are found in the second table.
If you have to select the data from only one table and no columns from second table, then
use semi-join (IN or EXISTS ) method instead conventional joins. As semi-join searches
second table for first occurrence of matching values and stops there. 27
28. NOT IN Vs NOT EXISTS
Handling of NULL values :
• If a sub query returns NULL values, NOT IN condition evaluates to False and
returns zero rows, as it could not compare NULL values.
• NOT EXISTS checks for non existence of the row, so it able to return rows even
if sub query has NULL values.
Anti - Join :
• An “anti-join” between two tables returns rows from the first table where no
matches are found in the second table.
• NOT IN and NOT EXISTS uses Anti – Join access path method.
• Consider NOT IN, if sub query never returns NULL values and whether the
query might benefit from a merge or hash anti-join.
• Else use NOT EXISTS.
28
29. Joins – Access Path Techniques
1. Nested Loop
2. Hash Join
3. Merge Join
4. SEMI Join
5. ANTI Join
How Oracle select access path in a conventional join ?
The nested loops algorithm is desirable when the predicates on the first table
are very selective and the join columns in the second table are selectively
indexed.
The merge and hash join algorithms, are more desirable when predicates are
not very selective or the join columns in the second table are not selectively
indexed. And if both the data set are of large size.
29
30. Joins – Nested Loop (old mechanism)
for r1 in (select rows from table_1 where colx = {value})
loop
for r2 in (select rows from table_2 that match current row from table_1)
loop
output values from current row of table_1 and current row of table_2
end loop
end loop
T1
T2
30
31. Joins – Nested Loop (New mechanism)
1. Mechanism finds the first row in the outer table, traverses the index, and stops in the
leaf block, picking up just the relevant rowids for the inner table.
2. Repeats this for all subsequent rows in the outer table.
3. When all the target rowids have been found, the engine can sort them and then visit
the inner table in a single pass, working along the length of the table just once,
picking the rows in whatever order they happen to appear.
4. optimizer_index_caching is used to adjust the cost calculation for index blocks of the
inner table in nested loops and for the index blocks used during in-list iterator. It is
not used in the calculation of costs for simple index unique scans or range scans into
a single table.
Index Access
31
32. Joins – Hash Join
1. Build Table : It acquire one data set and convert it into the equivalent of an
inmemory single-table hash cluster (assuming it have enough memory :
hash_area_size) using an internal hashing function on the join column(s) to
generate the hash key.
2. Probe Table : Start to acquire data from the second table, applying the
same hashing function to the join column(s) as it read each row, and
checking to see whether it can locate a matching row in the in-memory
hash cluster.
Types of Hash Join:
- Optimal Hash Join
- Onepass Hash Join
- Multipass Hash Join
32
33. Joins – Hash Join (Optimal hash join)
(hash_area_size := 1024 = 10% PGA size)
Cost = Cost of acquiring data from the build table + Cost of acquiring data from the probe table
+ Cost of performing the Hashing and Matching 33
35. Joins – Merge Join
Table 1 Table 2
Merge Merge
Sort Sort
To next step
35
36. Conclusions
1. Understand your data
2. Data distribution is important
3. Think about your parameters
4. Choose your Index Rightly
5. Help Oracle with the truth
There are NO Thumb Rules But, They are the different
options provided by Oracle to tune SQL !!!
36
37. References
1. Cost-Based Oracle, Book by : Jonathan Lewis
2. http://docs.oracle.com/cd/B10500_01/server.920/a96524/c08memor.htm
3. http://www.dba-oracle.com/art_otn_cbo.htm
4. http://docs.oracle.com/cd/B28359_01/server.111/b28318/memory.htm
5. http://blogs.oracle.com/optimizer/entry/dynamic_sampling_and_its_impact
_on_the_optimizer
6. http://orainternals.wordpress.com/2010/05/01/query-transformation-part-
1/
7. http://www.dbspecialists.com/files/presentations/semijoins.html
37
Parallel scans use direct path reads to bypass the data buffer and read blocks directly into local (PGA) memory.This helps to reduce the impact on the data buffer (but might mean you want a small Oracle buffer and a largefile system buffer in some special cases).But if the block in the data buffer is dirty (newer than the block on disk), then you might think a directread would not see the latest version, and may therefore get the wrong result. To solve this problem, a parallelquery will first issue a segment checkpoint to get all dirty blocks for the segment written to disk before itreads. (The cost is exposed through statistic DBWR parallel query checkpoint buffers written in10g, and otherwise indicated by enqueues of type TC.)This could lead to a performance problem in rare cases that mixed a large data buffer, a busy OLTPsystem, and parallel execution for reports—the work done by the database writer (DBWR) walking the checkpointqueue to find the relevant dirty blocks could have an undesirable impact on the OLTP activity.
Which means the cost is the total predicted execution time for the statement, expressedin units of the single-block read time.
Optimizer statistics are a collection of data that describe more details about the database and the objects in the database. These statistics are used by the query optimizer to choose the best execution plan for each SQL statement. As a general rule, the figures for bytes in execution plans are derived from the avg_col_len columns ofuser_tab_columns.special case of select * from table, the optimizer seems to use the avg_row_len fromuser_tables as the row size if the statistics have been generated by dbms_stats
Page 64 to 66
As far as possible try to mention more relational predicates in Where clause, By that optimizer will exactly know the which selectivity to workout and what degree of join to use.All Constraints defined on Table will add to your Join/Where Clause predicate. Example : if there is predicate Coln > 90. Oracle has to rewrite this as Coln > 90 AND Coln IS NOT NULL. If this column is never going to have NULL values then do add NOT null constraint on column, optimizer will not add extra predicate as its pretty sure that it will never gone encounter any NULL value.Same goes for Indexes if they are unique do create them as Unique, else optimizer will have to use Histogram and figure it out.
select (1/12 + 1/12 + 1/12 - 1/12*1/12 - 1/12*1/12 - 1/12*1/12 + 1/12*1/12*1/12) * 1200 from dual= 275.6944 but that should be 300 right ????
hash_area_size = 0.1 * pga_aggregate_targetBuild Table : It acquire one data set and convert it into the equivalent of an inmemorysingle-table hash cluster (assuming it have enough memory : hash_area_size) using an internal hashing function on the join column(s) to generate the hash key. The number of buckets in the hash table always seems to be an even power of two (common values for small hash joins are 1,024 or 4,096 buckets)Probe Table : Start to acquire data from the second table, applying the same hashing function to the join column(s) as it read each row, and checking to see whether it can locate a matching row in the in-memory hash cluster.If there are no rows in the relevant bucket, Oracle can immediately discard the row from the probe table. If there are some rows in the relevant bucket, Oracle does an exact check on the join column(s) to see if there is a proper match.
1. The first data set is acquired and scattered into the hash table. As a bucket is used, thecorresponding bit in the bitmap is set.2. As the memory fills up, clusters are dumped to disk. The dumping is done using a cautiousstrategy that tries to keep as many complete partitions in memory for as long as possible.When the build table is exhausted, it is possible that some partitions will still be heldcompletely in memory, while the rest have only a few (but at least one) clusters left inmemory. It may be that one partition has just a few clusters, in memory and the resthave only one each. Whatever the outcome, Oracle will have a detailed map of wherethe data from each partition can be found. Moreover, whenever a hash bucket has beenused (whether the relevant data items are in memory or on disk), the corresponding bitis set in the bitmap—which is always held completely in memory. At this point, Oracletidies up the hash table, trying to get as many complete partitions into memory as possibleand dumping any excess from other partitions to disk. As part of the rebuild,Oracle will reserve some clusters (a minimum of one per partition) for processing theprobe table.3. Once the hash table has been tidied up, Oracle starts to acquire rows from the seconddata set, applying the same hash function to the join column(s) of each row. The resultof the hash function is used to check the relevant bit in the bitmap (a detail I chose toignore in my description of the first example).4. Oracle takes one of several possible actions, depending on the result of the test.4a)Event: The bit is clear (0).Action: There is no match, and the row is discarded.4b)Event: The bit is set (1), and the relevant hash bucket is in a partition that is inmemory.Action: Check the hash bucket—if the probe row matches the build row, report it;otherwise discard it.4c)Event: The bit is set (1), but the relevant hash bucket is in a partition that is on disk.Action: Put the probe row to one side. It may match a build row that is on disk, but itwould be too expensive to reread the relevant build partition at this point to check it.Oracle has a complete map showing where all the data is and how many rowsthere are in each partition, so it picks a matched pair of dumped partitions (one build, oneprobe), and performs a hash join between them. As an extra optimization detail, Oracle canchoose to swap the roles of the two partitions at this point because it knows exactly how muchdata there is in each partition, and there may be some benefit in using whichever is the smallerone to build the new in-memory hash.So, in the case of a high-volume hash join, the hash table can spill to disk, with the probetable following it. The cost of the join ought to allow for the I/O performed in dumping theexcess to disk and reloading it for the second phase of the join. This type of hash join is recorded asa onepassworkarea execution because the probe dataset is reread from disk just once.