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Topic:
Interpretation Of Organic Molecules
By Mass Spectra
Presented By:
Ameer Ali Sandilo
OUTLINES
1. MASS SPECTRUM
2. 13 RULE
3. NITROGEN RULE
4. HYDROGEN INDEX DEFICIENCY
5. ALKANE
6. ALKENE
7. ALKYL HALIDE
8. ALCHOL
9. KETONE
10. CARBOXYLIC ACID
13. CONCLUSION
14. REFERENCES
15. ACKNOWLEDGMENT
1e–
Beam
-2e(1e+1e)
Terminology
Mass spectrum
Mass spectrum
A graph of the relative abundance of each
fragment plotted against its m/z value.
The x-axis, in units of m/z, represents the
formula weight of the detected ions.
The y-axis represents the relative abundance
of each detected ion.
The most abundant ion (tallest peak) is called
the base peak.
The peak at high m/z, is known as molecular
ion peak
.
Fragmentation
peaks
Base
peak
13 RULE
 The Rule of Thirteen is so named because, to generate a base formula
(containing only carbon and hydrogen); the molar mass of the substance
is divided by 13. The numerator from division gives the number of carbon
atoms in the base formula. The remainder, when added to the numerator,
gives the number of hydrogen’s in the base formula.
M+/13 H=n+r CnHn+r
 If you have heteroatoms, you adjust the formula. For example:
 For O, add O and subtract CH4.
 For N, add N and subtract CH2.
 For 35Cl, add Cl and subtract C2H11,etc.
Nitrogen rule
 If a compound contain odd number of nitrogen then, its molecular ion peak
will appear at an odd mass value.
 If a compound contain even number of nitrogen or no nitrogen then, its
molecular ion peak will appear at an even mass value.
 This rule is very useful determining the nitrogen content of an unknown
compound.
Hydrogen Deficient Index (HDI)
OR
Index Of Hydrogen Deficiency
Or
Degree Of Unsaturation
 Its used to determine how many rings, double bonds, and triple bonds are
present in the compound to be drawn.
 Formula for HDI=(x+1)-1/2(y)+1/2(z)
 x=tetravalent y=monovalent z=trivalent

S:NO# NAME OF
HYDROCARBON
FORMULA HDI NO:OF
HYDROGEN
LESS
1 ALKANE CnH2n+2 0 0
2 ALKENE CnH2n 1 2
3 CYCLOALKANE CnH2n-2 1 2
4 ALKYNE CnH2n-2 2 4
5 DIENE CnH2n-2 2 4
6 CYCLOALKENE CnH2n-2 2 4
7 ALKENYNE CnH2n-4 3 6
8 cyclodiene CnH2n-4 3 6
9 ARENE CnH2n-6 4 8
HYDROGEN DEFICIENT INDEX TABLE
Molecularion
peakat86
By applying above three rules on
mass spectrum
For carbon
13 rule=molecular ion peak/13
13)86(6 numerator (n)
-78
8 reminder(r)
It means over compound have 6
carbon.
For hydrogen = n+r
=6+8=14
So base formula is C6H14
HDI=(x+1)-1/2(y)+1/2(z)
=(6+1)-1/2(14)+1/2(0)
=(7)-(7)+(0)
HDI=0
HDI is zero so there will be no
unsaturation .
Nitrogen rule as its molecular ion peak
does not appear at an odd mass
value, so presence of single nitrogen
is not possible
Finally we can say that it’s a compound that doesn’t have any
ring or any double bond
Also we knew that no single nitrogen is present and our
comound have C6H14 no any other hint is given for
heteroatom.
M-15
M-29
M-43
M-57
• Molecular ion peak observed,
their intensity is inversely
proportional to the No: of carbon
atoms.
• Their fragments are at M-15,
M-29, M-43 etc.
• Base peak is observed at 43, 57
etc. Depend upon quantity of
carbon in the chain.
• Bond cleavage takes place at
the site of branches.
• Due to stable carbocation the
further fragmentation is
favored as a result weak M+
peak occurs.
• No: of branches of alkanes is
inversely proportional to the
intensity of molecular ion peak.
Pentane
• Base peak is at 43 due to
higher abundance of propyl
ion
• CH3-CH2-CH2-CH2-CH3
• Possibility of base peak is:
• CH3-CH2-CH2-CH2-CH3
• CH3-CH2-CH2
+ & .CH2-CH3
pentane
Mass spectrum of pentane vs. 2-methylbutane: Both mass spectra are similar to each other with two
notable exception, one the peak in 2-methylbutane at 57 is much more intense than normal pentane and
other is the molecular ion peak is less intense in 2-methylbutane.
.
• Fairly prominent M+ peak.
• Terminal alkenes lose allylic cation if possible.
• Most common fragmentation is the cleavage
of allylic bond.
• Positive charge usually remains with the fragments containing double bond in order to give
a resonance stabilized allylic cation.
McLafferty rearrangement may occur when there is a gamma carbon with hydrogen.
• 1-butene and 2-butene Mass spectra are identical –not a good method for alkene
isomer.
1-butene fragmentation
M-15
M-29
m/z=41 CH2=CH-CH2+
m/z=27 +HC=CH2
M+2 (isotopic) peak is observed.
• For bromine isotopic abundance is 1:1 and for chlorine it is of 1:3, due
to natural abundance of halogen (bromine & chlorine).
• Elimination reaction takes place.
• α- cleavage takes place.
• Molecular ion peak is observed.
Possible fragmentation of 2-Chloropropane
MASS SPECTRUM OF 2-chloropropane
• Intensity of molecular ion peak is depend upon substitute.
• Substitute is inversely proportional to the abundance of molecular ion
peak.
• Primary M+ peak is weak.
• Secondary M+ peak is weakest.
• Tertiary M+ peak is usually absent.
• M-17 peak is observed due to removal of –OH group.
• M-18 peak is observed due to formation of water.
(Elimination reaction)
• Base peak is observed at:
• m/z = 31 for primary.
• m/z = 45 for secondary.
• m/z = 59 for tertiary.
Possible Fragmentation
• Elimination.
• α- cleavage.
• β-cleavage.
2-pentanol
-H
• Base peak is usually lose of alkyl radical.
• The peak formed due to acylium ion is most abundant peak at m/z = 43
• Loss of large alkyl radical favors the ketone in α- cleavage.
• McLafferty rearrangement also occurs.
• α- cleavage takes place.
• Molecular ion peak is observed.
2-pentanone fragmentation
 M-17 (-OH group) indicates the presence of carboxylic acid.
• Peaks observed at:
• Molecular ion is observed but low abundance.
 M-45 (-COOH group) is also observed.
 Possible Fragmentation
• α- cleavage.
• β-cleavage.
• McLafferty rearrangement
Butanoic acid
 Identify molecule.
 Identify the functional group.
 Identify molecular ion peak.
 Construct the molecule by using base peak, fragmentation & functional
group.
• Introduction to Spectroscopy by Pavia.
• Elementary Organic Spectroscopy by Y.R.Sharma.
• Organic chemistry 4th edition by paula yurkanis bruice chapter no#13
mass spectrometry & infrared spectroscopy
• Organic Chemistry by Robert Thornton Morrison, 6th edition.
• Web Sources.
 I am extremely grateful to almighty ALLAH for His blessings over me
during up and downs of my life.
Interpretation Of Organic Molecules By Mass Spectra
Interpretation Of Organic Molecules By Mass Spectra

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Interpretation Of Organic Molecules By Mass Spectra

  • 1.
  • 2. Topic: Interpretation Of Organic Molecules By Mass Spectra Presented By: Ameer Ali Sandilo
  • 3. OUTLINES 1. MASS SPECTRUM 2. 13 RULE 3. NITROGEN RULE 4. HYDROGEN INDEX DEFICIENCY 5. ALKANE 6. ALKENE 7. ALKYL HALIDE 8. ALCHOL 9. KETONE 10. CARBOXYLIC ACID 13. CONCLUSION 14. REFERENCES 15. ACKNOWLEDGMENT
  • 5. Mass spectrum Mass spectrum A graph of the relative abundance of each fragment plotted against its m/z value. The x-axis, in units of m/z, represents the formula weight of the detected ions. The y-axis represents the relative abundance of each detected ion. The most abundant ion (tallest peak) is called the base peak. The peak at high m/z, is known as molecular ion peak . Fragmentation peaks Base peak
  • 6. 13 RULE  The Rule of Thirteen is so named because, to generate a base formula (containing only carbon and hydrogen); the molar mass of the substance is divided by 13. The numerator from division gives the number of carbon atoms in the base formula. The remainder, when added to the numerator, gives the number of hydrogen’s in the base formula. M+/13 H=n+r CnHn+r  If you have heteroatoms, you adjust the formula. For example:  For O, add O and subtract CH4.  For N, add N and subtract CH2.  For 35Cl, add Cl and subtract C2H11,etc.
  • 7. Nitrogen rule  If a compound contain odd number of nitrogen then, its molecular ion peak will appear at an odd mass value.  If a compound contain even number of nitrogen or no nitrogen then, its molecular ion peak will appear at an even mass value.  This rule is very useful determining the nitrogen content of an unknown compound.
  • 8. Hydrogen Deficient Index (HDI) OR Index Of Hydrogen Deficiency Or Degree Of Unsaturation  Its used to determine how many rings, double bonds, and triple bonds are present in the compound to be drawn.  Formula for HDI=(x+1)-1/2(y)+1/2(z)  x=tetravalent y=monovalent z=trivalent 
  • 9. S:NO# NAME OF HYDROCARBON FORMULA HDI NO:OF HYDROGEN LESS 1 ALKANE CnH2n+2 0 0 2 ALKENE CnH2n 1 2 3 CYCLOALKANE CnH2n-2 1 2 4 ALKYNE CnH2n-2 2 4 5 DIENE CnH2n-2 2 4 6 CYCLOALKENE CnH2n-2 2 4 7 ALKENYNE CnH2n-4 3 6 8 cyclodiene CnH2n-4 3 6 9 ARENE CnH2n-6 4 8 HYDROGEN DEFICIENT INDEX TABLE
  • 10. Molecularion peakat86 By applying above three rules on mass spectrum For carbon 13 rule=molecular ion peak/13 13)86(6 numerator (n) -78 8 reminder(r) It means over compound have 6 carbon. For hydrogen = n+r =6+8=14 So base formula is C6H14 HDI=(x+1)-1/2(y)+1/2(z) =(6+1)-1/2(14)+1/2(0) =(7)-(7)+(0) HDI=0 HDI is zero so there will be no unsaturation . Nitrogen rule as its molecular ion peak does not appear at an odd mass value, so presence of single nitrogen is not possible Finally we can say that it’s a compound that doesn’t have any ring or any double bond Also we knew that no single nitrogen is present and our comound have C6H14 no any other hint is given for heteroatom. M-15 M-29 M-43 M-57
  • 11. • Molecular ion peak observed, their intensity is inversely proportional to the No: of carbon atoms. • Their fragments are at M-15, M-29, M-43 etc. • Base peak is observed at 43, 57 etc. Depend upon quantity of carbon in the chain. • Bond cleavage takes place at the site of branches. • Due to stable carbocation the further fragmentation is favored as a result weak M+ peak occurs. • No: of branches of alkanes is inversely proportional to the intensity of molecular ion peak.
  • 13. • Base peak is at 43 due to higher abundance of propyl ion • CH3-CH2-CH2-CH2-CH3 • Possibility of base peak is: • CH3-CH2-CH2-CH2-CH3 • CH3-CH2-CH2 + & .CH2-CH3 pentane
  • 14. Mass spectrum of pentane vs. 2-methylbutane: Both mass spectra are similar to each other with two notable exception, one the peak in 2-methylbutane at 57 is much more intense than normal pentane and other is the molecular ion peak is less intense in 2-methylbutane. .
  • 15. • Fairly prominent M+ peak. • Terminal alkenes lose allylic cation if possible. • Most common fragmentation is the cleavage of allylic bond. • Positive charge usually remains with the fragments containing double bond in order to give a resonance stabilized allylic cation. McLafferty rearrangement may occur when there is a gamma carbon with hydrogen. • 1-butene and 2-butene Mass spectra are identical –not a good method for alkene isomer.
  • 17. M+2 (isotopic) peak is observed. • For bromine isotopic abundance is 1:1 and for chlorine it is of 1:3, due to natural abundance of halogen (bromine & chlorine). • Elimination reaction takes place. • α- cleavage takes place. • Molecular ion peak is observed.
  • 18. Possible fragmentation of 2-Chloropropane
  • 19. MASS SPECTRUM OF 2-chloropropane
  • 20. • Intensity of molecular ion peak is depend upon substitute. • Substitute is inversely proportional to the abundance of molecular ion peak. • Primary M+ peak is weak. • Secondary M+ peak is weakest. • Tertiary M+ peak is usually absent. • M-17 peak is observed due to removal of –OH group. • M-18 peak is observed due to formation of water. (Elimination reaction)
  • 21. • Base peak is observed at: • m/z = 31 for primary. • m/z = 45 for secondary. • m/z = 59 for tertiary. Possible Fragmentation • Elimination. • α- cleavage. • β-cleavage.
  • 23. -H
  • 24. • Base peak is usually lose of alkyl radical. • The peak formed due to acylium ion is most abundant peak at m/z = 43 • Loss of large alkyl radical favors the ketone in α- cleavage. • McLafferty rearrangement also occurs. • α- cleavage takes place. • Molecular ion peak is observed.
  • 26.  M-17 (-OH group) indicates the presence of carboxylic acid. • Peaks observed at: • Molecular ion is observed but low abundance.  M-45 (-COOH group) is also observed.  Possible Fragmentation • α- cleavage. • β-cleavage. • McLafferty rearrangement
  • 28.  Identify molecule.  Identify the functional group.  Identify molecular ion peak.  Construct the molecule by using base peak, fragmentation & functional group.
  • 29. • Introduction to Spectroscopy by Pavia. • Elementary Organic Spectroscopy by Y.R.Sharma. • Organic chemistry 4th edition by paula yurkanis bruice chapter no#13 mass spectrometry & infrared spectroscopy • Organic Chemistry by Robert Thornton Morrison, 6th edition. • Web Sources.
  • 30.  I am extremely grateful to almighty ALLAH for His blessings over me during up and downs of my life.