find the equation of the tangent line at the given point on the curve. 3x^2+4xy+y^2+x-3y=10; (- 1,3) Solution on differentiating we get 6x+4xdy/dx+4y+2ydy/dx+1-3dy/dx=0 dy/dx=(1-4y-6x)/(4x+2y-3) putting x=-1,y=3 dy/dx=5/2 eqn of tangent is 5/2=y-3/x+1 2y-6=5x+5 2y=5x+11.