Find the equation for the line passes through (1,3) and (2,-1) Solution The equation of the line through the points (x1,y1) and (x2, y2) is y-y1 = {(y2-y1)/(x2-x1)}(x-x1). Thegiven points are ((1,3) and (2-1). So substituting (x1,y1) = (1,3) and (x2,y2) = (2,-1), we get: y-3 = {(-1-3)/(2-1)}(x-1) y-3 = -4(x-1) = -4x+1. 4x+y-3-1 =0 4x+y-4 = 0. Is the equation that passes through (1,3) and (2,-1)..

1. Find the equation for the line passes through (1,3) and (2,-1)
Solution
The equation of the line through the points (x1,y1) and (x2, y2) is
y-y1 = {(y2-y1)/(x2-x1)}(x-x1).
Thegiven points are ((1,3) and (2-1).
So substituting (x1,y1) = (1,3) and (x2,y2) = (2,-1), we get:
y-3 = {(-1-3)/(2-1)}(x-1)
y-3 = -4(x-1) = -4x+1.
4x+y-3-1 =0
4x+y-4 = 0. Is the equation that passes through (1,3) and (2,-1).