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point charges of .29 ÂµC and .82 ÂµC are place .65 m apart. what is the magnitude of the
electric field, in newtons per co...

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point charges of -29 C and -82 C are place -65 m apart- what is the ma.docx

8. Feb 2023

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point charges of .29 ÂµC and .82 ÂµC are place .65 m apart. what is the magnitude of the electric field, in newtons per coulomb, halfway between them?
Solution
Electric field due to a point charge is given by:
E = k|q|/r 2
So,
E = kq1/r 2 - kq2/r 2
= (9*10^9)/(0.65/2)^2 * [0.82 - 0.29]*10^-6
= 4.52 x 10 4 N/C
.

point charges of .29 ÂµC and .82 ÂµC are place .65 m apart. what is the magnitude of the electric field, in newtons per coulomb, halfway between them?
Solution
Electric field due to a point charge is given by:
E = k|q|/r 2
So,
E = kq1/r 2 - kq2/r 2
= (9*10^9)/(0.65/2)^2 * [0.82 - 0.29]*10^-6
= 4.52 x 10 4 N/C
.

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point charges of -29 C and -82 C are place -65 m apart- what is the ma.docx

1. point charges of .29 ÂµC and .82 ÂµC are place .65 m apart. what is the magnitude of the electric field, in newtons per coulomb, halfway between them? Solution Electric field due to a point charge is given by: E = k|q|/r 2 So, E = kq1/r 2 - kq2/r 2 = (9*10^9)/(0.65/2)^2 * [0.82 - 0.29]*10^-6 = 4.52 x 10 4 N/C