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RESEARCH INVENTY: International Journal of Engineering and Science
ISBN: 2319-6483, ISSN: 2278-4721, Vol. 2, Issue 1
(January 2013), PP 65-69
www.researchinventy.com

     Fixed Point Theorems for Eight Mappings on Menger Space
                       through Compatibility
                                        1
                                            Ranjeeta Jain, 2 N. Bajaj
            1
            Infinity Management and Engineering College Pathariya Jat Road Sagar (M.P.) 470003
        2
         Department of Mathematics and Statistic Dr. Hari Singh Gour University, Sagar (M.P.) 470003



Abstract: In this paper we prove a common fixed point theorem for eight mappings on Menger spaces using the
notion of compatibility and continuity of maps.

Key words: Menger Space, Compatible Mappings, Weak-compatible Mappings, Common fixed point.

                                               I.   Introduction:
          There have been a number of generalization of metric space.One such generalization is Menger space
initiated by Menger[1].it is a probabilistic generalization in which we assign to any two points x and y, a
distribution function Fx,y.Schweizer and sklar[3] studied this concept and gave some fundamental result on this
space.Sehgal,Bharucha-Reid[5] obtained a generalization of Banach Contraction Principle on a complete
Menger space which is a milestone in developing fixed point theory in Menger space. In 1991 Mishra [2]
introduced the concept of compatible maps in Menger spaces and gave some common fixed point theorems.In
1980,singh and singh [9] gave the following theorem on metric space for self maps which is use to our main
result:

Theorem (A): Let P, Q and T be self maps of a metric space (X, d) such that
             (1) PT=TP and QT=TQ,
             (2) P( X )  Q( X )  T ( X )
             (3) T is continuous ,and
             (4) d ( Px, Qy)  c ( x, y) ,where
             (5) for all x,yX and 0≤c<1.Futher if (5) X is complete then P, Q and T have a unique common
                  fixed point zX.
In 2006, Bijendra Singh and Shishir Jain [8] introduced fixed point theorems in Menger space through semi-
compatibility and gave the following fixed point theorem for six mappings:

Theorem (B): Let A, B, S, T, L and M are self maps on a complete Menger space (X, F, min) satisfying:
       (a) L(X)  ST(X), M(X)  AB(X).
      (b) AB = BA, ST = TS, LB = BL, MT = TM.
       (c) Either AB or L is continuous.
       (d) (L, AB) is semi-compatible and (M, ST) is weak-compatible.
       (e) There exists K  (0, 1) such that,
           FLp, Mq(kx)  min{FABp, Lp (x), FSTq, Mq (x), FSTq, Lp (x), FABp, Mq ((2-)x), FABp, STq(x)} .
           In this paper we generalize and extend the result of Bijendra Singh and Shishir Jain [8] for eight
mapping opposed to six mappings in complete Menger space using the concept of compatibility.
       For the sake of convenience we give some definitions.
Definition (1.1): A probabilistic metric space (PM-space) is a ordered pair (X, F) where X is an abstract act of
elements and F: X  X  L, defined by (p, q)  Fp, q where L is the set of all distribution functions i.e. L = {F p,
q / p, q  X} ,If the function Fp, q satisfy:
    (a) Fp, q (x) = 1 for all x > 0, if and only if p = q,
    (b) Fp, q (0) = 0,
    (c) Fp, q = Fq, p,
    (d) If Fp, q(x) = 1 and Fq, r (y) = 1 then Fp, r (x + y) = 1.


                                                        65
Fixed Point Theorems for Eight Mappings on Menger Space through Compatibility

Definition (1.2): A mapping t : [0, 1]  [0, 1]  [0, 1] is called a t-norm if,
     (a) t(a, 1) = a, t(0, 0) = 0,
     (b) t(a, b) = t(b, a) (symmetry property),
     (c) f(c, d)  t(a, b) for c  a, d  b,
     (d) t(t(a, b), c) = t(a, t(b, c)).
Definition (1.3): A Menger space is a triplet (X, F, t) where (X, F) is a PM-space and t is a t-norm such that for
all p, q, r  X and for all x, y  0, Fp, r (x+y)  t (Fp, q(x), Fq, r(y))
Definition (1.4): Self mappings A and S of a Menger space (X, F, t) are called compatible if
FASX n ,SAX n ()  1 for all                              > 0 when ever {xn} is a sequence in x such that Axn, Sxn  u, for some u in X,
as n  .
Definition (1.5): Self-maps A and S of a Menger space (X, F, t) are said to be weak compatible (or
coincidentally commuting) if they commute at their coincidence points i.e. if Ap = Sp for some p  N then ASp
= SAp.
Lemma [1]: Let {pn} be a sequence in a Menger space (X, F, t) with continuous t-norm and t(x, x)  x.

Suppose, for all x  [0, 1],  K  (0, 1) such that for all x > 0 and n  N.                                                         FPn , Pn 1 (Kx)  FPn 1 ,Pn (x). Then
{pn} is a Cauchy sequence in X.
Lemma [2]: Let (X, F, t) be a Menger space, if there exists K  (0, 1) such that for p, q  X,
           Fp, q (Kx)  Fp, q(x), Then p = q.
2. Main Results:
Theorem (2.1): Let A, B, S, T, L, M, P and Q are self mappings on a complete Menger space (X, F, min)
satisfying:
(2.1.1) P(X)  ST(X)  L(X)  M(X), Q(X)  AB(X).
 (2.1.2) AB = BA, ST = TS, PB = BP, QT = TQ, LT = TL, MT = TM.
(2.1.3)     Either P is continuous or AB is continuous.
(2.1.4)     (P, AB) is compatible and (L, ST), (Q, ST) and (L, M) are weak compatible.
(2.1.5)     There exists K  (0, 1) such that
            FPu, Qv (Kx)  min {FABu, Lv(x), FSTv, Pu (x), FSTv, Lv(x), FPu, ABu(x), FABu, STv(x), FPu, Mv(x), FPu, Lv (x), FQv,
            STv (x)} for all u, v  X and x > 0. Then self-maps A, B, S, T, L, M, P and Q have a unique common
            fixed point in X.
Proof: Let x0  X, from condition (2.1.1) there exists x1, x2  X such that
Px0 = STx1 = Lx1 = Mx1 = y0 and Qx1 = ABx2 = y1. Inductively we can construct sequence {xn} and {yn} in X.
such that
Px2n = STx2n+1 = Lx2n+1 = Mx2n+1 = y2n and Qx2n+1 = ABx2n+2 = y2n+1 for n = 0, 1, 2, ……
Now we prove {yn} is a Cauchy sequence in X.
Putting u = x2n, v = x2n+1 for x > 0 in (2.1.5) we get,
                                         
 FPx Qx (Kx)  min FABx 2 n , Lx 2n1 ( x ), FSTx 2 n 1 , Px 2n ( x ), FSTx 2 n 1 , Lx 2n1 ( x ), FPx 2 n , ABx 2n ( x ),
                2 n 1

                                                                                                                                                         
    2n,

                                             FABx 2 n , STx 2n 1 ( x ), FPx2 n , Mx 2n 1 ( x ), FPx2 n , Lx 2n 1 ( x ), FQx 2 n 1 , STx 2n 1 ( x )

Fy 2 n , y 2 n1 (Kx)  min  Fy             2 n 1 ,   y 2n   ( x ), Fy 2 n , y 2n ( x ), Fy 2 n , y 2n ( x ), Fy 2 n , y 2n-1 ( x ),
                                         Fy2 n 1 , y2n ( x ), Fy2 n , y2n ( x ), Fy2 n , y2n ( x ), Fy2 n 1 , y2n ( x )            
Hence,          Fy 2 n , y 2 n1 (Kx)  min  Fy                2 n 1 ,   y 2n    ( x ), Fy 2 n , y 2n1 ( x )     
Similarly,               Fy 2 n1, y 2 n2 (Kx)  min  Fy                  2n    , y 2n 1                                  
                                                                                              ( x ), Fy 2 n 1 , y 2n 2 ( x )
Therefore for all n even or odd we have
                                     
Fy y (Kx)  min Fy n 1 , y n ( x ), Fy n , y n 1 ( x )
   n , 2 n 1
                                                                                                   
Consequently,                                                   
                              Fy n , y n1 (x)  min Fy n1 , y n (k 1x), Fy n , y n1 (k 1x)                                  
By repeated application of above inequality we get,
                                 
Fy n , y n1 (x)  min Fy n1 , y n (k 1x), Fy n , y n1 (k m x)                                         
Since     Fy n , y n1 (k-mx)  1 as n   it follows that


                                                                                                               66
Fixed Point Theorems for Eight Mappings on Menger Space through Compatibility

Fy n , y n1 (kx)  Fy n1, y n (x)  n  N and x > 0.
Therefore by Lemma (1), {yn} is a Cauchy sequence in X, which is complete. Hence {yn}  z  X. Also its
subsequences.
        Qx2n+1  z, Lx2n+1  z, STx2n+1  z and Mx2n+1  z         ….. (1)
        Px2n  z and ABx2n  z                                              ….. (2)

Case 1: When P is continuous: As P is continuous then PPx2n  Pz and P(ABx2n)  Pz,
          As(P, AB) is compatible then we have P(AB)x2n  ABz
As the limit of a sequence in Menger space is unique then we have
         ABz = Pz                                                                                                                              ….. (3)
Step 1: Putting u = z, v = x2n+1 in (2.1.5) we get
           FPz, Qx 2n1 (kx )                  
                                        Min FABz, Lx 2n1 (x), FSTx 2n1 , Pz (x), FSTx
                                                                                                     2n1 , Lx 2n 1
                                                                                                                       (x), FPz, ABz (x),
                                                                                                                                           
                                             FABz, STx 2 n 1 ( x ), FPz, Mx 2 n 1 ( x ), FPz, Lx2 n 1 ( x ), FQx2 n 1 , STx 2 n 1 ( x )
Letting n   and using eq (1) and (3) we get
                                    n

           FPz, z (Kx )  min FPz, z ( x ), Fz , Pz ( x ), Fz, z ( x ), FPz, Pz ( x ),
                                        FPz, z ( x ), FPz, z ( x ), FPz, z ( x ), FPz, z ( x ), Fz , z ( x )
         FPz, z (Kx)  FPz, z
         By lemma (2) which gives Pz = z. Therefore ABz = Pz = z
Step 2: As P(X)  ST(X)  L(X)  M(X) then there exist w  X such that z = Pz = STw = Lw = Mw.
Putting u = x2n , v = w in (2.1.5) we get,
                                
FPx 2 n , Qw (Kx )  min FABx2 n , Lw (x), FSTw , Px2n (x), FSTw, Lw (x), FPx2n , ABx2n (x),
                             FABx 2 n , STw ( x ), FPx2 n , Mw ( x ), FPx2 n , Lw ( x ), FQw , STw ( x )               
Letting n   using equation (2) we get
Fz , Qw ( Kx )  min{Fz, z (x), Fz, z (x), Fz, z (x), Fz, z (x), Fz, z (x),
                         Fz, z (x), Fz, z (x), FQw, z (x)}
Fz , Qw (Kx)  Fz , Qw (x)
Therefore by lemma 2, Qw = z
Hence STw = z = Qw = Lw = Mw
As (Q, ST), (L, ST) and (L, M) are weak compatible, we have
             STQw = QSTw, STLw = LSTw and MLw = LMw
Thus           STz = Qz,            STz = Lz          and  Mz = Lz
i.e. STz = Qz = Lz = Mz                                                                                            …… (4)

Step 3: Putting u = x2n , v = z in (2.1.5)
           FPx 2 n , Qz (Kx)  min {FABx 2 n , Lz(x), FSTz, Px 2 n (x) , FSTz, Lz (x) , FPx 2 n ABx 2 n (x),
                                               FABx 2 n , STz (x), FPz 2 n Mz (x), FPx 2 n , Lz (x), FQz, STz (x)}
                            n
letting n  , using eq (2) and (4) we get

Fz, Qz (Kx)  min{Fz, Qz (x), FQz, z (x), FQz, Qz (x), Fz, z (x), Fz, Qz(x), Fz, Qz (x),
                                 Fz, Qz (x), FQz, Qz (x)}
Fz, Qz (Kx)  Fz, Qz (x)
Hence z = Qz
Therefore z = Qz = Lz = Mz = STz [from 4]
Step 4: Putting u = x2n , v = Tz in (2.1.5)
          FPx 2 n ,QTz (Kx)  min{FABx 2 n , LTz (x), FST.Tz, Px 2 n (x), FST.Tz, LTz (x),
                                               FPx 2 n , ABx 2 n (x), FABx 2 n , ST.Tz (x), FPx 2 n , MTz (x),
                               FPx 2 n LTz (x), FQTz, ST.Tz (x)}
As QT = TQ, ST = TS, LT = TL and MT = TM we have
     QTz = TQz = Tz,    LTz = TLz = Tz,                          MTz = TMz = Tz
and ST(Tz) = TS(Tz) = T(STz) = Tz
                                                                           67
Fixed Point Theorems for Eight Mappings on Menger Space through Compatibility

                                     n
letting n   and using eq (2) we get
          Fz, Tz (Kx)  Min {Fz, Tz (x), FTz, z (x), FTz, Tz (x), Fz, z (x), Fz, Tz (x),
                                   Fz, Tz (x), Fz, Tz(x), FTz, Tz (x)}
          Fz, Tz (Kx)  Fz, Tz (x)
Therefore by lemma (2) we get
          Tz = z
Now STz = Tz = z implies Sz = z
Hence Sz = Tz = Qz = Lz = Pz = Mz = z                                                                          …()

Step 5: Putting u = Bz, v = x2n+1 in (2.1.5), we get
    FPBz,Qx2n+1(Kx)  min{ FAB.Bz , Lx 2n 1 (x), FSTx                          (x), FSTx 2n1 ,Lx 2 n1 (x), FPBz, AB.Bz(x),
                                                                  2 n 1, PBz

                                              FAB.Bz,STx 2 n 1 (x), FP.Bz, Mx2n1 (x), FPBz, Lx2n1 (x), FQx2n1 ,STx 2x1 (x)}
As PB = BP and AB = BA. So we have
PBz = BPz = Bz and AB(Bz) = BA(Bz) = B(ABz) = Bz
                                 n
letting n and using eq (1) we get,
FBz, z (Kx)  min {FBz, z (x), Fz, Bz (x), Fz, z (x), FBz, Bz (x), FBz, z (x),
                         FBz, z (x), FBz, z (x), Fz, z (x)}
FBz, z (Kx)  FBz, z (x)
which gives Bz = z and ABz = z implies Az = z
Therefore Az = Bz = Pz = z                                                            .....()
Combining () and () we have
Az = Bz = Pz = Lz = Qz = Tz = Sz = Mz = z i.e. z is the common fixed point of the eight mappings A, B, S, T,
L, M, P and Q in the case I.

Case II. AB is continuous:
         AS AB is continuous, AB.ABx2n  ABz and (AB)Px2n  ABz.
AS (P, AB) is compatible we have P(AB)x2n  ABz

Step 6: Putting u = ABx2n, v = x2n+1 in (2.1.5) we get
FPABx2 n , Qx 2n1 (kx)  min { FAB.ABx 2 n , Lx 2n1 (x) , FSTx 2 n 1 , PABx2n (x) , FSTx 2 n 1 , Lx 2n1 (x) ,
                                         FP.ABx 2 n , AB.ABx2n (x) , FAB.ABx 2 n , STx 2n1 (x) , FP.ABx 2 n , Mx 2n 1 (x) ,
                                         FP.ABx 2 n , Lx 2n1 (x) , FQx 2 n 1 , STx 2n1 (x)   
Letting n   we get
           FABz, z (kx)  min { FABz, z (x) , Fz , ABz (x) , Fz , z (x) , FABz, ABz (x) , FABz, z (x)
                                          FABz, z (x) , FABz, z (x) , Fz , z (x) 
i.e. FABz , z (kx)  FABz, z (x) . Therefore by lemma (2) we get
              ABz = z
Now applying step 1, we get Pz = z
Therefore ABz = Pz = z
Again applying step 5, to get Bz = z and we get Az = Pz = Bz = z.
Now using steps 2, 3 and 4 of previous case we get
Sz = Tz = Qz = Lz = Mz = z.
i.e. z is the common fixed point of the eight mappings A, B, S, T, M, L, P and Q in the case II also.
Uniqueness: Let z' be another common fixed point of A, B, S, T, L, M, P and Q then Az' = Bz' = Sz' = Tz' = Lz'
= Mz' = Pz' = Qz' = z'.
Putting u = z, v = z' in (2.1.5) we get
           FPz, Qz' (Kx)  min {FABz, Lz' (x), FSTz', Pz (x), FSTz', Lz' (x), FPz, ABz(x),
                                      FABz, STz' (x), FPz, Mz' (x), FPz, Lz' (x), FQz', STz' (x)}
            Fz, z' (Kx)  min {Fz, z' (x), Fz', z (x), Fz', z (x), Fz, z (x), Fz, z' (x), Fz, z’(x) Fz, z' (x), Fz’, z' (x)}
           Fz, z' (Kx)  Fz, z' (x)
which gives by lemma (2) z = z'. Therefore z is a unique common fixed point of A, B, S, T, L, M, P and Q.


                                                                            68
Fixed Point Theorems for Eight Mappings on Menger Space through Compatibility

In the support of the theorem, we have following example:
 Example:- Let (x, F, *) be a Menger space with X = {0,1}, t-norm * defined by           a * b = min (a, b), a, b
 [0, 1] and Fu, v (x) = [exp ( | u – v | / x) ]-1,  u, v  X, x > 0. Defined self maps A, B, S, T, L, M, P and
                              u                      3u                  u                    u
Q such that           Pu =      ,          Su =         ,        Qu =       ,         Tu =      ,
                             16                       4                  32                  12
                   u                    u                     u                    2u                         1     
           Au =      ,           Lu =     ,            Bu =     ,          Mu =       ,      Then for K   , 1
                   4                    3                     2                     3                     2 
                                                1
                 u v             
FPu, Qv (Kx) = exp
                    16  32  / Kx 
                             
                
                                  
                                    
                                              1
                   u v  
                = exp    / x
                          
                    8 16  
                               
              = FABu, STv (x)
FPu, Qv (Kx)  min{FABu, Lv(x), FSTv, Pu (x), FSTv, Lv(x), FPu, ABu(x), FABu, STv(x),
                        FPu, Mv(x), FPu, Lv (x), FQv, STv (x)} for all u, v  X and x > 0.Then all the conditions of
theorem are satisfied and zero is the common fixed point of mappings A, B, S, T, L, M, P and Q

                                                            References:
  [1].   Menger, K.: Statistical metrics, Proc. Nat. Acad. Sci. USA., 28, (1942) 535-537.
  [2].   Mishra, S.N.: Common fixed points of compatible mappings in PM-spaces, Math. Japonica 36, 2 (1991) 283-289.
  [3].   Schweizer, B. and Sklar A.: Statistical metric spaces, Pacific J. Math. 10, (1960) 313-334.
  [4].   Saini R.K. and Chauhan S.S.: Fixed point theorem for eight mappings on metric spaces, Journal of Mathematics and System
         Science, vol. 1 No. 2 (2005).
  [5].   Sehgal,V.M.and Bharucha-Reid,A.T.:Fixed point of contraction mappings in PM-space,Math.Systems Theory,6(1972),97-102
  [6].   Singh Bijendra and Sharma R.K. Common fixed points of compatible maps in Menger spaces, Vikram Mathematical Journal,
         Vol. XVI, (1996) 51-56.
  [7].   Singh, B. and Jain Shishir: A fixed point theorem in Menger space through weak compatibility, Journal of Mathematical Analysis
         and Application 301, (2005) 439-448.
  [8].   Singh Bijendra and Jain Shishir: Fixed point theorems in Menger space through semi compatibility,. Varahmihir Journal 1 (2006)
         117-128
  [9].   Singh,S.L.and Singh,S.P: A fixed point theorem,Indian j.of pure and App. Math,vol no.11,(1980),1584-1586




                                                                    69

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Research Inventy : International Journal of Engineering and Science

  • 1. RESEARCH INVENTY: International Journal of Engineering and Science ISBN: 2319-6483, ISSN: 2278-4721, Vol. 2, Issue 1 (January 2013), PP 65-69 www.researchinventy.com Fixed Point Theorems for Eight Mappings on Menger Space through Compatibility 1 Ranjeeta Jain, 2 N. Bajaj 1 Infinity Management and Engineering College Pathariya Jat Road Sagar (M.P.) 470003 2 Department of Mathematics and Statistic Dr. Hari Singh Gour University, Sagar (M.P.) 470003 Abstract: In this paper we prove a common fixed point theorem for eight mappings on Menger spaces using the notion of compatibility and continuity of maps. Key words: Menger Space, Compatible Mappings, Weak-compatible Mappings, Common fixed point. I. Introduction: There have been a number of generalization of metric space.One such generalization is Menger space initiated by Menger[1].it is a probabilistic generalization in which we assign to any two points x and y, a distribution function Fx,y.Schweizer and sklar[3] studied this concept and gave some fundamental result on this space.Sehgal,Bharucha-Reid[5] obtained a generalization of Banach Contraction Principle on a complete Menger space which is a milestone in developing fixed point theory in Menger space. In 1991 Mishra [2] introduced the concept of compatible maps in Menger spaces and gave some common fixed point theorems.In 1980,singh and singh [9] gave the following theorem on metric space for self maps which is use to our main result: Theorem (A): Let P, Q and T be self maps of a metric space (X, d) such that (1) PT=TP and QT=TQ, (2) P( X )  Q( X )  T ( X ) (3) T is continuous ,and (4) d ( Px, Qy)  c ( x, y) ,where (5) for all x,yX and 0≤c<1.Futher if (5) X is complete then P, Q and T have a unique common fixed point zX. In 2006, Bijendra Singh and Shishir Jain [8] introduced fixed point theorems in Menger space through semi- compatibility and gave the following fixed point theorem for six mappings: Theorem (B): Let A, B, S, T, L and M are self maps on a complete Menger space (X, F, min) satisfying: (a) L(X)  ST(X), M(X)  AB(X). (b) AB = BA, ST = TS, LB = BL, MT = TM. (c) Either AB or L is continuous. (d) (L, AB) is semi-compatible and (M, ST) is weak-compatible. (e) There exists K  (0, 1) such that, FLp, Mq(kx)  min{FABp, Lp (x), FSTq, Mq (x), FSTq, Lp (x), FABp, Mq ((2-)x), FABp, STq(x)} . In this paper we generalize and extend the result of Bijendra Singh and Shishir Jain [8] for eight mapping opposed to six mappings in complete Menger space using the concept of compatibility. For the sake of convenience we give some definitions. Definition (1.1): A probabilistic metric space (PM-space) is a ordered pair (X, F) where X is an abstract act of elements and F: X  X  L, defined by (p, q)  Fp, q where L is the set of all distribution functions i.e. L = {F p, q / p, q  X} ,If the function Fp, q satisfy: (a) Fp, q (x) = 1 for all x > 0, if and only if p = q, (b) Fp, q (0) = 0, (c) Fp, q = Fq, p, (d) If Fp, q(x) = 1 and Fq, r (y) = 1 then Fp, r (x + y) = 1. 65
  • 2. Fixed Point Theorems for Eight Mappings on Menger Space through Compatibility Definition (1.2): A mapping t : [0, 1]  [0, 1]  [0, 1] is called a t-norm if, (a) t(a, 1) = a, t(0, 0) = 0, (b) t(a, b) = t(b, a) (symmetry property), (c) f(c, d)  t(a, b) for c  a, d  b, (d) t(t(a, b), c) = t(a, t(b, c)). Definition (1.3): A Menger space is a triplet (X, F, t) where (X, F) is a PM-space and t is a t-norm such that for all p, q, r  X and for all x, y  0, Fp, r (x+y)  t (Fp, q(x), Fq, r(y)) Definition (1.4): Self mappings A and S of a Menger space (X, F, t) are called compatible if FASX n ,SAX n ()  1 for all  > 0 when ever {xn} is a sequence in x such that Axn, Sxn  u, for some u in X, as n  . Definition (1.5): Self-maps A and S of a Menger space (X, F, t) are said to be weak compatible (or coincidentally commuting) if they commute at their coincidence points i.e. if Ap = Sp for some p  N then ASp = SAp. Lemma [1]: Let {pn} be a sequence in a Menger space (X, F, t) with continuous t-norm and t(x, x)  x. Suppose, for all x  [0, 1],  K  (0, 1) such that for all x > 0 and n  N. FPn , Pn 1 (Kx)  FPn 1 ,Pn (x). Then {pn} is a Cauchy sequence in X. Lemma [2]: Let (X, F, t) be a Menger space, if there exists K  (0, 1) such that for p, q  X, Fp, q (Kx)  Fp, q(x), Then p = q. 2. Main Results: Theorem (2.1): Let A, B, S, T, L, M, P and Q are self mappings on a complete Menger space (X, F, min) satisfying: (2.1.1) P(X)  ST(X)  L(X)  M(X), Q(X)  AB(X). (2.1.2) AB = BA, ST = TS, PB = BP, QT = TQ, LT = TL, MT = TM. (2.1.3) Either P is continuous or AB is continuous. (2.1.4) (P, AB) is compatible and (L, ST), (Q, ST) and (L, M) are weak compatible. (2.1.5) There exists K  (0, 1) such that FPu, Qv (Kx)  min {FABu, Lv(x), FSTv, Pu (x), FSTv, Lv(x), FPu, ABu(x), FABu, STv(x), FPu, Mv(x), FPu, Lv (x), FQv, STv (x)} for all u, v  X and x > 0. Then self-maps A, B, S, T, L, M, P and Q have a unique common fixed point in X. Proof: Let x0  X, from condition (2.1.1) there exists x1, x2  X such that Px0 = STx1 = Lx1 = Mx1 = y0 and Qx1 = ABx2 = y1. Inductively we can construct sequence {xn} and {yn} in X. such that Px2n = STx2n+1 = Lx2n+1 = Mx2n+1 = y2n and Qx2n+1 = ABx2n+2 = y2n+1 for n = 0, 1, 2, …… Now we prove {yn} is a Cauchy sequence in X. Putting u = x2n, v = x2n+1 for x > 0 in (2.1.5) we get,  FPx Qx (Kx)  min FABx 2 n , Lx 2n1 ( x ), FSTx 2 n 1 , Px 2n ( x ), FSTx 2 n 1 , Lx 2n1 ( x ), FPx 2 n , ABx 2n ( x ), 2 n 1  2n, FABx 2 n , STx 2n 1 ( x ), FPx2 n , Mx 2n 1 ( x ), FPx2 n , Lx 2n 1 ( x ), FQx 2 n 1 , STx 2n 1 ( x ) Fy 2 n , y 2 n1 (Kx)  min  Fy 2 n 1 , y 2n ( x ), Fy 2 n , y 2n ( x ), Fy 2 n , y 2n ( x ), Fy 2 n , y 2n-1 ( x ), Fy2 n 1 , y2n ( x ), Fy2 n , y2n ( x ), Fy2 n , y2n ( x ), Fy2 n 1 , y2n ( x )  Hence, Fy 2 n , y 2 n1 (Kx)  min  Fy 2 n 1 , y 2n ( x ), Fy 2 n , y 2n1 ( x )  Similarly, Fy 2 n1, y 2 n2 (Kx)  min  Fy 2n , y 2n 1  ( x ), Fy 2 n 1 , y 2n 2 ( x ) Therefore for all n even or odd we have  Fy y (Kx)  min Fy n 1 , y n ( x ), Fy n , y n 1 ( x ) n , 2 n 1  Consequently,  Fy n , y n1 (x)  min Fy n1 , y n (k 1x), Fy n , y n1 (k 1x)  By repeated application of above inequality we get,  Fy n , y n1 (x)  min Fy n1 , y n (k 1x), Fy n , y n1 (k m x)  Since Fy n , y n1 (k-mx)  1 as n   it follows that 66
  • 3. Fixed Point Theorems for Eight Mappings on Menger Space through Compatibility Fy n , y n1 (kx)  Fy n1, y n (x)  n  N and x > 0. Therefore by Lemma (1), {yn} is a Cauchy sequence in X, which is complete. Hence {yn}  z  X. Also its subsequences. Qx2n+1  z, Lx2n+1  z, STx2n+1  z and Mx2n+1  z ….. (1) Px2n  z and ABx2n  z ….. (2) Case 1: When P is continuous: As P is continuous then PPx2n  Pz and P(ABx2n)  Pz, As(P, AB) is compatible then we have P(AB)x2n  ABz As the limit of a sequence in Menger space is unique then we have ABz = Pz ….. (3) Step 1: Putting u = z, v = x2n+1 in (2.1.5) we get FPz, Qx 2n1 (kx )   Min FABz, Lx 2n1 (x), FSTx 2n1 , Pz (x), FSTx 2n1 , Lx 2n 1 (x), FPz, ABz (x),  FABz, STx 2 n 1 ( x ), FPz, Mx 2 n 1 ( x ), FPz, Lx2 n 1 ( x ), FQx2 n 1 , STx 2 n 1 ( x ) Letting n   and using eq (1) and (3) we get n FPz, z (Kx )  min FPz, z ( x ), Fz , Pz ( x ), Fz, z ( x ), FPz, Pz ( x ), FPz, z ( x ), FPz, z ( x ), FPz, z ( x ), FPz, z ( x ), Fz , z ( x ) FPz, z (Kx)  FPz, z By lemma (2) which gives Pz = z. Therefore ABz = Pz = z Step 2: As P(X)  ST(X)  L(X)  M(X) then there exist w  X such that z = Pz = STw = Lw = Mw. Putting u = x2n , v = w in (2.1.5) we get,  FPx 2 n , Qw (Kx )  min FABx2 n , Lw (x), FSTw , Px2n (x), FSTw, Lw (x), FPx2n , ABx2n (x), FABx 2 n , STw ( x ), FPx2 n , Mw ( x ), FPx2 n , Lw ( x ), FQw , STw ( x )  Letting n   using equation (2) we get Fz , Qw ( Kx )  min{Fz, z (x), Fz, z (x), Fz, z (x), Fz, z (x), Fz, z (x), Fz, z (x), Fz, z (x), FQw, z (x)} Fz , Qw (Kx)  Fz , Qw (x) Therefore by lemma 2, Qw = z Hence STw = z = Qw = Lw = Mw As (Q, ST), (L, ST) and (L, M) are weak compatible, we have STQw = QSTw, STLw = LSTw and MLw = LMw Thus STz = Qz, STz = Lz and Mz = Lz i.e. STz = Qz = Lz = Mz …… (4) Step 3: Putting u = x2n , v = z in (2.1.5) FPx 2 n , Qz (Kx)  min {FABx 2 n , Lz(x), FSTz, Px 2 n (x) , FSTz, Lz (x) , FPx 2 n ABx 2 n (x), FABx 2 n , STz (x), FPz 2 n Mz (x), FPx 2 n , Lz (x), FQz, STz (x)} n letting n  , using eq (2) and (4) we get Fz, Qz (Kx)  min{Fz, Qz (x), FQz, z (x), FQz, Qz (x), Fz, z (x), Fz, Qz(x), Fz, Qz (x), Fz, Qz (x), FQz, Qz (x)} Fz, Qz (Kx)  Fz, Qz (x) Hence z = Qz Therefore z = Qz = Lz = Mz = STz [from 4] Step 4: Putting u = x2n , v = Tz in (2.1.5) FPx 2 n ,QTz (Kx)  min{FABx 2 n , LTz (x), FST.Tz, Px 2 n (x), FST.Tz, LTz (x), FPx 2 n , ABx 2 n (x), FABx 2 n , ST.Tz (x), FPx 2 n , MTz (x), FPx 2 n LTz (x), FQTz, ST.Tz (x)} As QT = TQ, ST = TS, LT = TL and MT = TM we have QTz = TQz = Tz, LTz = TLz = Tz, MTz = TMz = Tz and ST(Tz) = TS(Tz) = T(STz) = Tz 67
  • 4. Fixed Point Theorems for Eight Mappings on Menger Space through Compatibility n letting n   and using eq (2) we get Fz, Tz (Kx)  Min {Fz, Tz (x), FTz, z (x), FTz, Tz (x), Fz, z (x), Fz, Tz (x), Fz, Tz (x), Fz, Tz(x), FTz, Tz (x)} Fz, Tz (Kx)  Fz, Tz (x) Therefore by lemma (2) we get Tz = z Now STz = Tz = z implies Sz = z Hence Sz = Tz = Qz = Lz = Pz = Mz = z …() Step 5: Putting u = Bz, v = x2n+1 in (2.1.5), we get FPBz,Qx2n+1(Kx)  min{ FAB.Bz , Lx 2n 1 (x), FSTx (x), FSTx 2n1 ,Lx 2 n1 (x), FPBz, AB.Bz(x), 2 n 1, PBz FAB.Bz,STx 2 n 1 (x), FP.Bz, Mx2n1 (x), FPBz, Lx2n1 (x), FQx2n1 ,STx 2x1 (x)} As PB = BP and AB = BA. So we have PBz = BPz = Bz and AB(Bz) = BA(Bz) = B(ABz) = Bz n letting n and using eq (1) we get, FBz, z (Kx)  min {FBz, z (x), Fz, Bz (x), Fz, z (x), FBz, Bz (x), FBz, z (x), FBz, z (x), FBz, z (x), Fz, z (x)} FBz, z (Kx)  FBz, z (x) which gives Bz = z and ABz = z implies Az = z Therefore Az = Bz = Pz = z .....() Combining () and () we have Az = Bz = Pz = Lz = Qz = Tz = Sz = Mz = z i.e. z is the common fixed point of the eight mappings A, B, S, T, L, M, P and Q in the case I. Case II. AB is continuous: AS AB is continuous, AB.ABx2n  ABz and (AB)Px2n  ABz. AS (P, AB) is compatible we have P(AB)x2n  ABz Step 6: Putting u = ABx2n, v = x2n+1 in (2.1.5) we get FPABx2 n , Qx 2n1 (kx)  min { FAB.ABx 2 n , Lx 2n1 (x) , FSTx 2 n 1 , PABx2n (x) , FSTx 2 n 1 , Lx 2n1 (x) , FP.ABx 2 n , AB.ABx2n (x) , FAB.ABx 2 n , STx 2n1 (x) , FP.ABx 2 n , Mx 2n 1 (x) , FP.ABx 2 n , Lx 2n1 (x) , FQx 2 n 1 , STx 2n1 (x)  Letting n   we get FABz, z (kx)  min { FABz, z (x) , Fz , ABz (x) , Fz , z (x) , FABz, ABz (x) , FABz, z (x) FABz, z (x) , FABz, z (x) , Fz , z (x)  i.e. FABz , z (kx)  FABz, z (x) . Therefore by lemma (2) we get ABz = z Now applying step 1, we get Pz = z Therefore ABz = Pz = z Again applying step 5, to get Bz = z and we get Az = Pz = Bz = z. Now using steps 2, 3 and 4 of previous case we get Sz = Tz = Qz = Lz = Mz = z. i.e. z is the common fixed point of the eight mappings A, B, S, T, M, L, P and Q in the case II also. Uniqueness: Let z' be another common fixed point of A, B, S, T, L, M, P and Q then Az' = Bz' = Sz' = Tz' = Lz' = Mz' = Pz' = Qz' = z'. Putting u = z, v = z' in (2.1.5) we get FPz, Qz' (Kx)  min {FABz, Lz' (x), FSTz', Pz (x), FSTz', Lz' (x), FPz, ABz(x), FABz, STz' (x), FPz, Mz' (x), FPz, Lz' (x), FQz', STz' (x)} Fz, z' (Kx)  min {Fz, z' (x), Fz', z (x), Fz', z (x), Fz, z (x), Fz, z' (x), Fz, z’(x) Fz, z' (x), Fz’, z' (x)} Fz, z' (Kx)  Fz, z' (x) which gives by lemma (2) z = z'. Therefore z is a unique common fixed point of A, B, S, T, L, M, P and Q. 68
  • 5. Fixed Point Theorems for Eight Mappings on Menger Space through Compatibility In the support of the theorem, we have following example: Example:- Let (x, F, *) be a Menger space with X = {0,1}, t-norm * defined by a * b = min (a, b), a, b  [0, 1] and Fu, v (x) = [exp ( | u – v | / x) ]-1,  u, v  X, x > 0. Defined self maps A, B, S, T, L, M, P and u 3u u u Q such that Pu = , Su = , Qu = , Tu = , 16 4 32 12 u u u 2u 1  Au = , Lu = , Bu = , Mu = , Then for K   , 1 4 3 2 3 2  1   u v   FPu, Qv (Kx) = exp  16  32  / Kx         1  u v   = exp   / x     8 16     = FABu, STv (x) FPu, Qv (Kx)  min{FABu, Lv(x), FSTv, Pu (x), FSTv, Lv(x), FPu, ABu(x), FABu, STv(x), FPu, Mv(x), FPu, Lv (x), FQv, STv (x)} for all u, v  X and x > 0.Then all the conditions of theorem are satisfied and zero is the common fixed point of mappings A, B, S, T, L, M, P and Q References: [1]. Menger, K.: Statistical metrics, Proc. Nat. Acad. Sci. USA., 28, (1942) 535-537. [2]. Mishra, S.N.: Common fixed points of compatible mappings in PM-spaces, Math. Japonica 36, 2 (1991) 283-289. [3]. Schweizer, B. and Sklar A.: Statistical metric spaces, Pacific J. Math. 10, (1960) 313-334. [4]. Saini R.K. and Chauhan S.S.: Fixed point theorem for eight mappings on metric spaces, Journal of Mathematics and System Science, vol. 1 No. 2 (2005). [5]. Sehgal,V.M.and Bharucha-Reid,A.T.:Fixed point of contraction mappings in PM-space,Math.Systems Theory,6(1972),97-102 [6]. Singh Bijendra and Sharma R.K. Common fixed points of compatible maps in Menger spaces, Vikram Mathematical Journal, Vol. XVI, (1996) 51-56. [7]. Singh, B. and Jain Shishir: A fixed point theorem in Menger space through weak compatibility, Journal of Mathematical Analysis and Application 301, (2005) 439-448. [8]. Singh Bijendra and Jain Shishir: Fixed point theorems in Menger space through semi compatibility,. Varahmihir Journal 1 (2006) 117-128 [9]. Singh,S.L.and Singh,S.P: A fixed point theorem,Indian j.of pure and App. Math,vol no.11,(1980),1584-1586 69