solve: log 8 (x-1) + log 8 (x-1) = 2.....its log base 8 but i didnt know how to type it on here....but it just says to solve for x....if possilby could someone help me solve it and show how to do it step by step!? Thank you! Solution log 8 (x-1) + log 8 (x-1) = 2 log8{ (x-1)(x-1) } = 2 log8{ (x-1)^2 } = 2 2 log8{ (x-1) } = 2 log8{ (x-1) } = 1 x - 1 = 8^1 x = 9 .