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Mass of the solid sphere M = 2000 kg
radius of the sphere R = 5 m
mass of the point mass m = 2.3 kg
(a). Gravitational force at 5.04 m is F = GMm/r 2
Where G = Gravitational constant = 6.67 x10 -11 Nm 2/ kg 2
r = distance = 5.04 m
Substitute values you get F = (6.67 x10 -11)(2000)(2.3) / 5.04 2
= 1.2078x10 -8 N
(b). r ' = 2.55 m
Gravitational force at 2.55 m is F = GMm r '/R 3
Where G = Gravitational constant = 6.67 x10 -11 Nm 2/ kg 2
R = distance = 5.00 m
Substitute values you get F = (6.67 x10 -11)(2000)(2.3)(2.55) / 53
= 6.259x10 -9 N
Solution
Mass of the solid sphere M = 2000 kg
radius of the sphere R = 5 m
mass of the point mass m = 2.3 kg
(a). Gravitational force at 5.04 m is F = GMm/r 2
Where G = Gravitational constant = 6.67 x10 -11 Nm 2/ kg 2
r = distance = 5.04 m
Substitute values you get F = (6.67 x10 -11)(2000)(2.3) / 5.04 2
= 1.2078x10 -8 N
(b). r ' = 2.55 m
Gravitational force at 2.55 m is F = GMm r '/R 3
Where G = Gravitational constant = 6.67 x10 -11 Nm 2/ kg 2
R = distance = 5.00 m
Substitute values you get F = (6.67 x10 -11)(2000)(2.3)(2.55) / 53
= 6.259x10 -9 N

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Mass of the solid sphere M = 2000 kgradius of the sphere R = 5 m.pdf

  • 1. Mass of the solid sphere M = 2000 kg radius of the sphere R = 5 m mass of the point mass m = 2.3 kg (a). Gravitational force at 5.04 m is F = GMm/r 2 Where G = Gravitational constant = 6.67 x10 -11 Nm 2/ kg 2 r = distance = 5.04 m Substitute values you get F = (6.67 x10 -11)(2000)(2.3) / 5.04 2 = 1.2078x10 -8 N (b). r ' = 2.55 m Gravitational force at 2.55 m is F = GMm r '/R 3 Where G = Gravitational constant = 6.67 x10 -11 Nm 2/ kg 2 R = distance = 5.00 m Substitute values you get F = (6.67 x10 -11)(2000)(2.3)(2.55) / 53 = 6.259x10 -9 N Solution Mass of the solid sphere M = 2000 kg radius of the sphere R = 5 m mass of the point mass m = 2.3 kg (a). Gravitational force at 5.04 m is F = GMm/r 2 Where G = Gravitational constant = 6.67 x10 -11 Nm 2/ kg 2 r = distance = 5.04 m Substitute values you get F = (6.67 x10 -11)(2000)(2.3) / 5.04 2 = 1.2078x10 -8 N (b). r ' = 2.55 m Gravitational force at 2.55 m is F = GMm r '/R 3 Where G = Gravitational constant = 6.67 x10 -11 Nm 2/ kg 2 R = distance = 5.00 m Substitute values you get F = (6.67 x10 -11)(2000)(2.3)(2.55) / 53 = 6.259x10 -9 N