SlideShare a Scribd company logo
1 of 30
Download to read offline
@@@@@ Probability @@@@@


        PROBABILITY
       BY GROUP TWO
Member’s of Group



   U’ul Ulinuha Rahajeng W
   (110210151009)
Member’s of Group



   U’ul Ulinuha Rahajeng W
   (110210151009)
   Aya Shofia Maulida (110210151009)
Member’s of Group



   U’ul Ulinuha Rahajeng W
   (110210151009)
   Aya Shofia Maulida (110210151009)
   Intan Mahyastuti (110210151013)
Member’s of Group



   U’ul Ulinuha Rahajeng W
   (110210151009)
   Aya Shofia Maulida (110210151009)
   Intan Mahyastuti (110210151013)
PROBABILITY’S CASE




 *
 In a bag there is 1 green marbles and 4 blue
 marbles.
1. When you takes one marble at
random then how many opportunities
are being picked green marbles?
1. When you takes one marble at
random then how many opportunities
are being picked green marbles?
2. When you took one marble at
random what is the probability that a
blue marble is drawn?
1. When you takes one marble at
random then how many opportunities
are being picked green marbles?
2. When you took one marble at
random what is the probability that a
blue marble is drawn?
3. When you take one marble at
random then what is the probability of
marbles drawn are green or blue? .
ANSWER


 for question number 1
                            1
 1. Opportunity (green) =   5   = 20%
With a simple understanding. There are 5
marbles then there are 5 choices take
marbles. Among the five marbles there is
only 1 green marbles then there is only one
green choice.
So the chances of green chosen is 1
possibility out of 5 possible options. Or we
can write:
                         1     20
Opportunity (green) = 5 = 100 = 20%
1
What is the meaning of odds    5   this?????


The simple meaning is that if you took 1
marbles so it is unlikely you will get a green
marbles. But if you took 1 marbles 5 times
almost certain you will succeed in green.
1
5 x5 = 1
for question number 2
                          4
2. Opportunity (blue) =   5   = 80%
With a common understanding, there are 4
blue marbles marbles out of 5 total. So
chances are the blue you got 4 choice of 5
options possible. We can write,
Opportunity (blue) = 4 = 100 = 80%
                      5
                           80
4
What is the meaning of odds   5   this?
True. We can guess. Opportunity 4 is almost
                                   5
sure that you is almost certainly managed to
obtain a blue color. When you took the
marbles repeat 5 times then you will be able
to obtain blue green 4 times and only one
time.
for question number 3
3. Opportunity (green or blue)


=1+4
 5 5



    5
=   5



=1
Of course you certainly managed to take the
marbles are green or blue. There are 5
marbles are green or blue color. So you has 5
choices of 5 possible options. your conclusion
certainly succeeded.
In the theory of chances, chances are
definitely going have a chance = 1 = 100%.
In fact, the play super marble, we sometimes
take the marbles directly 2 points or 3 points
according to the results of dice throws us.
***




 ***The Other Problem***
Case : Taking the ball one by one with
replacement.
In a basket there are 7 red balls, 5 blue balls
and the black 8 ball. If 3 balls drawn
randomly drawn ball on condition returned to
the basket, what is the probability that the
balls are drawn successively red, black and
blue?
Because the decision is with replacement,
then the number of balls in the basket for
each decision is fixed, namely: 7 +5 +8 =
20.
So the odds of drawing a ball with a
sequence of red, black, blue is the product of
three chance of drawing the ball on every
decision, namely:
      7 8 5         7
P = 20 x 20 x 20 = 200
Case : Taking the ball one by one without
replacement.
In a box there are 5 red balls, six green balls
and 4 yellow balls. If 3 balls drawn at
random without replacement, what is the
probability that the ball drawn in a row is
red, green, red?
Since taking the ball without replacement,
then the number of balls in the box on every
decision will be different. Chances are the
multiplication of each opportunity on every
decision. Can be calculated by:
      5 6 4        4
P = 15 x 14 x 13 = 19
ThAnK’s FoR yOuR aTtEnTiOn

More Related Content

Viewers also liked

DallaCite2014-2015 Final
DallaCite2014-2015 FinalDallaCite2014-2015 Final
DallaCite2014-2015 Final
Amber Zable
 
D ulrich wp_change_insights
D ulrich wp_change_insightsD ulrich wp_change_insights
D ulrich wp_change_insights
KC19LODO
 
Credit suisse research - global-investment-returns-yearbook-2014
Credit suisse research -  global-investment-returns-yearbook-2014Credit suisse research -  global-investment-returns-yearbook-2014
Credit suisse research - global-investment-returns-yearbook-2014
Sergiy Kurbatov
 
Guía Infoempleo KSCHOOL de las nuevas profesiones
Guía Infoempleo KSCHOOL de las nuevas profesionesGuía Infoempleo KSCHOOL de las nuevas profesiones
Guía Infoempleo KSCHOOL de las nuevas profesiones
Carlos Terrones Lizana
 
Valeant Pharmaceuticals' Investor Day 2012 Download
Valeant Pharmaceuticals' Investor Day 2012 DownloadValeant Pharmaceuticals' Investor Day 2012 Download
Valeant Pharmaceuticals' Investor Day 2012 Download
Valeant_Pharmaceuticals
 

Viewers also liked (15)

1 manual modulo ff
1 manual modulo ff1 manual modulo ff
1 manual modulo ff
 
Trabajo informatica
Trabajo informaticaTrabajo informatica
Trabajo informatica
 
DallaCite2014-2015 Final
DallaCite2014-2015 FinalDallaCite2014-2015 Final
DallaCite2014-2015 Final
 
Charlas
CharlasCharlas
Charlas
 
JONATHAN LIPPMAN CRIMINAL EXHIBIT
JONATHAN LIPPMAN CRIMINAL EXHIBITJONATHAN LIPPMAN CRIMINAL EXHIBIT
JONATHAN LIPPMAN CRIMINAL EXHIBIT
 
D ulrich wp_change_insights
D ulrich wp_change_insightsD ulrich wp_change_insights
D ulrich wp_change_insights
 
Ranking 2015 de Information Technology
Ranking 2015 de Information TechnologyRanking 2015 de Information Technology
Ranking 2015 de Information Technology
 
Luis Salvador Velazquez: esculturas de hielo y arena
Luis Salvador Velazquez: esculturas de hielo y arenaLuis Salvador Velazquez: esculturas de hielo y arena
Luis Salvador Velazquez: esculturas de hielo y arena
 
Credit suisse research - global-investment-returns-yearbook-2014
Credit suisse research -  global-investment-returns-yearbook-2014Credit suisse research -  global-investment-returns-yearbook-2014
Credit suisse research - global-investment-returns-yearbook-2014
 
Guía Infoempleo KSCHOOL de las nuevas profesiones
Guía Infoempleo KSCHOOL de las nuevas profesionesGuía Infoempleo KSCHOOL de las nuevas profesiones
Guía Infoempleo KSCHOOL de las nuevas profesiones
 
Jamba Juicethailand
Jamba JuicethailandJamba Juicethailand
Jamba Juicethailand
 
Miguel Medina - Architectural Portfolio
Miguel Medina - Architectural PortfolioMiguel Medina - Architectural Portfolio
Miguel Medina - Architectural Portfolio
 
Valeant Pharmaceuticals' Investor Day 2012 Download
Valeant Pharmaceuticals' Investor Day 2012 DownloadValeant Pharmaceuticals' Investor Day 2012 Download
Valeant Pharmaceuticals' Investor Day 2012 Download
 
ECE 2DO GRADO
ECE 2DO GRADOECE 2DO GRADO
ECE 2DO GRADO
 
Innovation and the S-Curve
Innovation and the S-CurveInnovation and the S-Curve
Innovation and the S-Curve
 

Similar to probability

13.4 Independent Events
13.4 Independent Events13.4 Independent Events
13.4 Independent Events
vmonacelli
 
Probability-Multiple-Event-Demonstration.pptx
Probability-Multiple-Event-Demonstration.pptxProbability-Multiple-Event-Demonstration.pptx
Probability-Multiple-Event-Demonstration.pptx
ReemTaha14
 
01_Probability of Simple Events.ppt
01_Probability of Simple Events.ppt01_Probability of Simple Events.ppt
01_Probability of Simple Events.ppt
ReinabelleMarquez1
 
Questions of basic probability for aptitude test
Questions of basic probability for aptitude test Questions of basic probability for aptitude test
Questions of basic probability for aptitude test
Dr. Trilok Kumar Jain
 
Your Statistics Homework Solver is Here! 📊📚
Your Statistics Homework Solver is Here! 📊📚Your Statistics Homework Solver is Here! 📊📚
Your Statistics Homework Solver is Here! 📊📚
Statistics Homework Helper
 
7.8 simple probability 1
7.8 simple probability   17.8 simple probability   1
7.8 simple probability 1
bweldon
 

Similar to probability (20)

Probability
ProbabilityProbability
Probability
 
Applied Math 40S March 5, 2008
Applied Math 40S March 5, 2008Applied Math 40S March 5, 2008
Applied Math 40S March 5, 2008
 
Simple stats maths fun docx
Simple stats maths fun docxSimple stats maths fun docx
Simple stats maths fun docx
 
13.4 Independent Events
13.4 Independent Events13.4 Independent Events
13.4 Independent Events
 
Aptitude Training - PROBABILITY
Aptitude Training - PROBABILITYAptitude Training - PROBABILITY
Aptitude Training - PROBABILITY
 
Probability-Multiple-Event-Demonstration.pptx
Probability-Multiple-Event-Demonstration.pptxProbability-Multiple-Event-Demonstration.pptx
Probability-Multiple-Event-Demonstration.pptx
 
INDEPENDENT AND DEPENDENT EVENTS
INDEPENDENT AND DEPENDENT EVENTSINDEPENDENT AND DEPENDENT EVENTS
INDEPENDENT AND DEPENDENT EVENTS
 
01_Probability of Simple Events.ppt
01_Probability of Simple Events.ppt01_Probability of Simple Events.ppt
01_Probability of Simple Events.ppt
 
Concept of Probability.pptx
Concept of Probability.pptxConcept of Probability.pptx
Concept of Probability.pptx
 
Probability
ProbabilityProbability
Probability
 
Questions of basic probability for aptitude test
Questions of basic probability for aptitude test Questions of basic probability for aptitude test
Questions of basic probability for aptitude test
 
Questions of basic probability for aptitude test
Questions of basic probability for aptitude test Questions of basic probability for aptitude test
Questions of basic probability for aptitude test
 
Applied 40S March 16, 2009
Applied 40S March 16, 2009Applied 40S March 16, 2009
Applied 40S March 16, 2009
 
Lets Explore Probability.pptx
Lets Explore Probability.pptxLets Explore Probability.pptx
Lets Explore Probability.pptx
 
Your Statistics Homework Solver is Here! 📊📚
Your Statistics Homework Solver is Here! 📊📚Your Statistics Homework Solver is Here! 📊📚
Your Statistics Homework Solver is Here! 📊📚
 
7.8 simple probability 1
7.8 simple probability   17.8 simple probability   1
7.8 simple probability 1
 
Fun-With-Probability-Simple-Eventss.pptx
Fun-With-Probability-Simple-Eventss.pptxFun-With-Probability-Simple-Eventss.pptx
Fun-With-Probability-Simple-Eventss.pptx
 
Advanced s
Advanced sAdvanced s
Advanced s
 
Algebra unit 9.6.2
Algebra unit 9.6.2Algebra unit 9.6.2
Algebra unit 9.6.2
 
Algebra unit 9.6.2
Algebra unit 9.6.2Algebra unit 9.6.2
Algebra unit 9.6.2
 

probability

  • 1. @@@@@ Probability @@@@@ PROBABILITY BY GROUP TWO
  • 2. Member’s of Group U’ul Ulinuha Rahajeng W (110210151009)
  • 3. Member’s of Group U’ul Ulinuha Rahajeng W (110210151009) Aya Shofia Maulida (110210151009)
  • 4. Member’s of Group U’ul Ulinuha Rahajeng W (110210151009) Aya Shofia Maulida (110210151009) Intan Mahyastuti (110210151013)
  • 5. Member’s of Group U’ul Ulinuha Rahajeng W (110210151009) Aya Shofia Maulida (110210151009) Intan Mahyastuti (110210151013)
  • 6. PROBABILITY’S CASE * In a bag there is 1 green marbles and 4 blue marbles.
  • 7. 1. When you takes one marble at random then how many opportunities are being picked green marbles?
  • 8. 1. When you takes one marble at random then how many opportunities are being picked green marbles? 2. When you took one marble at random what is the probability that a blue marble is drawn?
  • 9. 1. When you takes one marble at random then how many opportunities are being picked green marbles? 2. When you took one marble at random what is the probability that a blue marble is drawn? 3. When you take one marble at random then what is the probability of marbles drawn are green or blue? .
  • 10. ANSWER for question number 1 1 1. Opportunity (green) = 5 = 20%
  • 11. With a simple understanding. There are 5 marbles then there are 5 choices take marbles. Among the five marbles there is only 1 green marbles then there is only one green choice.
  • 12. So the chances of green chosen is 1 possibility out of 5 possible options. Or we can write: 1 20 Opportunity (green) = 5 = 100 = 20%
  • 13. 1 What is the meaning of odds 5 this????? The simple meaning is that if you took 1 marbles so it is unlikely you will get a green marbles. But if you took 1 marbles 5 times almost certain you will succeed in green. 1 5 x5 = 1
  • 14. for question number 2 4 2. Opportunity (blue) = 5 = 80%
  • 15. With a common understanding, there are 4 blue marbles marbles out of 5 total. So chances are the blue you got 4 choice of 5 options possible. We can write, Opportunity (blue) = 4 = 100 = 80% 5 80
  • 16. 4 What is the meaning of odds 5 this?
  • 17. True. We can guess. Opportunity 4 is almost 5 sure that you is almost certainly managed to obtain a blue color. When you took the marbles repeat 5 times then you will be able to obtain blue green 4 times and only one time.
  • 18. for question number 3 3. Opportunity (green or blue) =1+4 5 5 5 = 5 =1
  • 19. Of course you certainly managed to take the marbles are green or blue. There are 5 marbles are green or blue color. So you has 5 choices of 5 possible options. your conclusion certainly succeeded.
  • 20. In the theory of chances, chances are definitely going have a chance = 1 = 100%.
  • 21. In fact, the play super marble, we sometimes take the marbles directly 2 points or 3 points according to the results of dice throws us.
  • 22. *** ***The Other Problem***
  • 23. Case : Taking the ball one by one with replacement.
  • 24. In a basket there are 7 red balls, 5 blue balls and the black 8 ball. If 3 balls drawn randomly drawn ball on condition returned to the basket, what is the probability that the balls are drawn successively red, black and blue?
  • 25. Because the decision is with replacement, then the number of balls in the basket for each decision is fixed, namely: 7 +5 +8 = 20.
  • 26. So the odds of drawing a ball with a sequence of red, black, blue is the product of three chance of drawing the ball on every decision, namely: 7 8 5 7 P = 20 x 20 x 20 = 200
  • 27. Case : Taking the ball one by one without replacement.
  • 28. In a box there are 5 red balls, six green balls and 4 yellow balls. If 3 balls drawn at random without replacement, what is the probability that the ball drawn in a row is red, green, red?
  • 29. Since taking the ball without replacement, then the number of balls in the box on every decision will be different. Chances are the multiplication of each opportunity on every decision. Can be calculated by: 5 6 4 4 P = 15 x 14 x 13 = 19
  • 30. ThAnK’s FoR yOuR aTtEnTiOn