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Modul ENRICHMENT Matematik SPM 2014
Tajuk: The Straight Line
Garis Lurus
Masa: 20 minit
TAJUK: The Straight Line/ Garis Lurus
1. In Diagram 1, MN is a straight line.
Dalam Rajah 1, MN ialah sebuah garis lurus.
Find the gradient of MN.
Cari kecerunan garis MN
A -2
B
C
−
D 2
2. Given that the equation of a straight line is x – 2y + 3 = 0. Find the x-intercept of
the straight line.
Diberi persamaan garis lurus ialah x – 2y + 3 = 0. Cari pintasan-x bagi garis lurus
tersebut
A −1
B −2
C −3
D −4
3. In Diagram 2, the length of OC is 2 units.
Dalam rajah 2, panjang OC ialah 2 unit.
The gradient of line BC is
Diagram 1
Rajah 1
R
a
j
a
h
1
Diagram 2
Rajah 2
R
a
j
a
h
1
Kecerunan garis BC ialah
A 3
B 4
C −4
D −3
4. Based on Diagram 3, find the equation of line PR.
Berdasarkan rajah 3, Cari persamaan garis PR
A y = -x – 6
B y = -x + 6
C y = x + 6
D y = x – 6
5. In Diagram 4, the equation of the line WZ is y = x.
Q (8, k) is a point on the line WZ.
Dalam rajah 4, persamaan garis WZ ialah WZ is y = x.
Q (8, k) ialah satu titik pada garis WZ.
Find the value of k.
Cari nilai bagi k.
A 6
B 7
C 8
D 9
Diagram 3
Rajah 3
R
a
j
a
h
1
Diagram 4
Rajah 4
R
a
j
a
h
1
6. The equation of a straight line passing through the point ( -3, 8 ) and parallel to
the line y = x + 5 is
Persamaan garis lurus yang melalui titik ( -3, 8 ) dan selari dengan garis y = x + 5 is
ialah
A y = x + 8
B 3y = 2x + 10
C 3y = 2x + 30
D y = x -3
7. In Diagram 5, OE = OG. Find the gradient of line EG.
Dalam rajah 5, OE = OG. Cari kecerunan garis EG.
A 1
B −1
C 2
D −2
8. The coordinates of point P are (-2, 5), and the gradient of the straight line PQ is 3. The
coordinates of point Q could be
Koordinat bagi P ialah (-2, 5), dan kecerunan garis lurus PQ ialah 3. Koordinat yang
mungkin bagi Q ialah
A (1, 1)
B (5, 1)
C (−1, 8)
D (−5, 4)
Diagram 5
Rajah 5
R
a
j
a
h
1
9. The y-intercept of the straight line 4y = 3 – 2x is
Pintasan-y bagi garis 4y = 3 – 2x ialah
A
B −
C −
D
10. In Diagram 7, the length of OP is 10 units. The equation of line PR is
Dalam rajah 7, panjang OP ialah 10 unit. Persamaan garis PR ialah
A y = x + 8
B y = x + 8
C y = x + 4
D y = x + 4
Diagram 7
Rajah 7
R
a
j
a
h
1
ANSWER/ Jawapan
The Straight Line/ Garis Lurus
1. Gradient/ Kecerunan MN
m = −
= −
= − Answer/ Jawapan : C
2. – 2 + 3 =0, at -intercept , the value of =0 / Pada pintasan- , nilai of =0
–2(0)+3 =0
=− 3
Answer/ Jawapan : C
3. B (0,6) c(2,0)
Gradient/ Kecerunan BC
= −
= −3
Answer/ Jawapan : D
4. R ( , ) = (−2, -8), P ( , ) = (8, 2),
m =
=
=
m = 1
= m +c
c = 2 – 8
= −6
= – 6, Answer/ Jawapan : D
5. Q ( 8, k)
=
k = (8)
= 6 , Answer/ Jawapan : A
6. Passing through (-3, 8) and parallel with = + 5
So, m =
= m +c
8 = (−3)+ c
8 = −2 + C
C = 10
Then, = + 10
= + 30, Answer/ Jawapan : C
7. m = −
m = − 1
Answer/ Jawapan : B
8. m =
=
=
Therefore, the coordinates of point Q = (-1, 8)
Answer/ Jawapan : C
9. = , at -intercept, the value of / pada pintasan- , nilai = 0
=
=
=
Answer/ Jawapan : A
10. R ( , ) = (0, - 8), P ( , ) = (10, 0),
m =
= −
=
=−
= m +c
Then, =− + 8
Answer/ Jawapan : B

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The straight line

  • 1. Modul ENRICHMENT Matematik SPM 2014 Tajuk: The Straight Line Garis Lurus Masa: 20 minit
  • 2. TAJUK: The Straight Line/ Garis Lurus 1. In Diagram 1, MN is a straight line. Dalam Rajah 1, MN ialah sebuah garis lurus. Find the gradient of MN. Cari kecerunan garis MN A -2 B C − D 2 2. Given that the equation of a straight line is x – 2y + 3 = 0. Find the x-intercept of the straight line. Diberi persamaan garis lurus ialah x – 2y + 3 = 0. Cari pintasan-x bagi garis lurus tersebut A −1 B −2 C −3 D −4 3. In Diagram 2, the length of OC is 2 units. Dalam rajah 2, panjang OC ialah 2 unit. The gradient of line BC is Diagram 1 Rajah 1 R a j a h 1 Diagram 2 Rajah 2 R a j a h 1
  • 3. Kecerunan garis BC ialah A 3 B 4 C −4 D −3 4. Based on Diagram 3, find the equation of line PR. Berdasarkan rajah 3, Cari persamaan garis PR A y = -x – 6 B y = -x + 6 C y = x + 6 D y = x – 6 5. In Diagram 4, the equation of the line WZ is y = x. Q (8, k) is a point on the line WZ. Dalam rajah 4, persamaan garis WZ ialah WZ is y = x. Q (8, k) ialah satu titik pada garis WZ. Find the value of k. Cari nilai bagi k. A 6 B 7 C 8 D 9 Diagram 3 Rajah 3 R a j a h 1 Diagram 4 Rajah 4 R a j a h 1
  • 4. 6. The equation of a straight line passing through the point ( -3, 8 ) and parallel to the line y = x + 5 is Persamaan garis lurus yang melalui titik ( -3, 8 ) dan selari dengan garis y = x + 5 is ialah A y = x + 8 B 3y = 2x + 10 C 3y = 2x + 30 D y = x -3 7. In Diagram 5, OE = OG. Find the gradient of line EG. Dalam rajah 5, OE = OG. Cari kecerunan garis EG. A 1 B −1 C 2 D −2 8. The coordinates of point P are (-2, 5), and the gradient of the straight line PQ is 3. The coordinates of point Q could be Koordinat bagi P ialah (-2, 5), dan kecerunan garis lurus PQ ialah 3. Koordinat yang mungkin bagi Q ialah A (1, 1) B (5, 1) C (−1, 8) D (−5, 4) Diagram 5 Rajah 5 R a j a h 1
  • 5. 9. The y-intercept of the straight line 4y = 3 – 2x is Pintasan-y bagi garis 4y = 3 – 2x ialah A B − C − D 10. In Diagram 7, the length of OP is 10 units. The equation of line PR is Dalam rajah 7, panjang OP ialah 10 unit. Persamaan garis PR ialah A y = x + 8 B y = x + 8 C y = x + 4 D y = x + 4 Diagram 7 Rajah 7 R a j a h 1
  • 6. ANSWER/ Jawapan The Straight Line/ Garis Lurus 1. Gradient/ Kecerunan MN m = − = − = − Answer/ Jawapan : C 2. – 2 + 3 =0, at -intercept , the value of =0 / Pada pintasan- , nilai of =0 –2(0)+3 =0 =− 3 Answer/ Jawapan : C 3. B (0,6) c(2,0) Gradient/ Kecerunan BC = − = −3 Answer/ Jawapan : D 4. R ( , ) = (−2, -8), P ( , ) = (8, 2), m = = = m = 1 = m +c c = 2 – 8 = −6 = – 6, Answer/ Jawapan : D 5. Q ( 8, k) = k = (8) = 6 , Answer/ Jawapan : A
  • 7. 6. Passing through (-3, 8) and parallel with = + 5 So, m = = m +c 8 = (−3)+ c 8 = −2 + C C = 10 Then, = + 10 = + 30, Answer/ Jawapan : C 7. m = − m = − 1 Answer/ Jawapan : B 8. m = = = Therefore, the coordinates of point Q = (-1, 8) Answer/ Jawapan : C 9. = , at -intercept, the value of / pada pintasan- , nilai = 0 = = = Answer/ Jawapan : A 10. R ( , ) = (0, - 8), P ( , ) = (10, 0), m = = − = =− = m +c Then, =− + 8 Answer/ Jawapan : B