The document discusses the concept of approximating the area under a curve using rectangles. It shows that as the width of the rectangles decreases, the approximation becomes more accurate. It then derives that the equation for the curve is equal to the derivative of the area function, and that the exact area under the curve between two points can be calculated as the integral of the function between those points.
27. As the widths decrease, the estimate becomes more accurate, lets
investigate one of these rectangles.
y
y = f(x)
x
28. As the widths decrease, the estimate becomes more accurate, lets
investigate one of these rectangles.
y
y = f(x)
x
29. As the widths decrease, the estimate becomes more accurate, lets
investigate one of these rectangles.
y
y = f(x)
c x
A(c) is the area from 0 to c
30. As the widths decrease, the estimate becomes more accurate, lets
investigate one of these rectangles.
y
y = f(x)
c x x
A(c) is the area from 0 to c
A(x) is the area from 0 to x
31. A(x) – A(c) denotes the area from c to x, and can be estimated by
the rectangle;
32. A(x) – A(c) denotes the area from c to x, and can be estimated by
the rectangle;
f(x)
x-c
33. A(x) – A(c) denotes the area from c to x, and can be estimated by
the rectangle;
f(x)
x-c
A x Ac x c f x
34. A(x) – A(c) denotes the area from c to x, and can be estimated by
the rectangle;
f(x)
x-c
A x Ac x c f x
A x Ac
f x
xc
35. A(x) – A(c) denotes the area from c to x, and can be estimated by
the rectangle;
f(x)
x-c
A x Ac x c f x
A x Ac
f x
xc
Ac h Ac
h = width of rectangle
h
36. A(x) – A(c) denotes the area from c to x, and can be estimated by
the rectangle;
f(x)
x-c
A x Ac x c f x
A x Ac
f x
xc
Ac h Ac
h = width of rectangle
h
As the width of the rectangle decreases, the estimate becomes more
accurate.
38. i.e. as h 0, the Area becomes exact
Ac h Ac
f x lim
h 0 h
39. i.e. as h 0, the Area becomes exact
Ac h Ac
f x lim
h 0 h
A x h A x
lim
h 0
as h 0, c x
h
40. i.e. as h 0, the Area becomes exact
Ac h Ac
f x lim
h 0 h
A x h A x
lim
h 0
as h 0, c x
h
A x
41. i.e. as h 0, the Area becomes exact
Ac h Ac
f x lim
h 0 h
A x h A x
lim
h 0
as h 0, c x
h
A x
the equation of the curve is the derivative of the Area function.
42. i.e. as h 0, the Area becomes exact
Ac h Ac
f x lim
h 0 h
A x h A x
lim
h 0
as h 0, c x
h
A x
the equation of the curve is the derivative of the Area function.
The area under the curve y f x between x a and x b is;
43. i.e. as h 0, the Area becomes exact
Ac h Ac
f x lim
h 0 h
A x h A x
lim
h 0
as h 0, c x
h
A x
the equation of the curve is the derivative of the Area function.
The area under the curve y f x between x a and x b is;
b
A f x dx
a
44. i.e. as h 0, the Area becomes exact
Ac h Ac
f x lim
h 0 h
A x h A x
lim
h 0
as h 0, c x
h
A x
the equation of the curve is the derivative of the Area function.
The area under the curve y f x between x a and x b is;
b
A f x dx
a
F b F a
45. i.e. as h 0, the Area becomes exact
Ac h Ac
f x lim
h 0 h
A x h A x
lim
h 0
as h 0, c x
h
A x
the equation of the curve is the derivative of the Area function.
The area under the curve y f x between x a and x b is;
b
A f x dx
a
F b F a
where F x is the primitive function of f x
46. e.g. (i) Find the area under the curve y x 3 , between x = 0 and
x= 2
47. e.g. (i) Find the area under the curve y x 3 , between x = 0 and
2
x= 2
A x 3 dx
0
48. e.g. (i) Find the area under the curve y x 3 , between x = 0 and
2
x= 2
A x 3 dx
0
2
x4
1
4 0
49. e.g. (i) Find the area under the curve y x 3 , between x = 0 and
2
x= 2
A x 3 dx
0
2
x4
1
4 0
2 04
1 4
4
50. e.g. (i) Find the area under the curve y x 3 , between x = 0 and
2
x= 2
A x 3 dx
0
2
x4
1
4 0
2 04
1 4
4
4 units 2
51. e.g. (i) Find the area under the curve y x 3 , between x = 0 and
2
x= 2
A x 3 dx
0
2
x4
1
4 0
2 04
1 4
4
4 units 2
3
ii x 2 1dx
2
52. e.g. (i) Find the area under the curve y x 3 , between x = 0 and
2
x= 2
A x 3 dx
0
2
x4
1
4 0
2 04
1 4
4
4 units 2
3 3
ii x 1dx
2 1 x 3 x
2
2 3
53. e.g. (i) Find the area under the curve y x 3 , between x = 0 and
2
x= 2
A x 3 dx
0
2
x4
1
4 0
2 04
1 4
4
4 units 2
3 3
ii x 1dx
2 1 x 3 x
2
2 3
1 33 3 1 2 3 2
3 3
54. e.g. (i) Find the area under the curve y x 3 , between x = 0 and
2
x= 2
A x 3 dx
0
2
x4
1
4 0
2 04
1 4
4
4 units 2
3 3
ii x 1dx
2 1 x 3 x
2
2 3
1 33 3 1 2 3 2
3 3
22
3