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Ex 1.จงทำำให้เป็นรูปอย่ำงง่ำยและมีเลขชี้กำำลังเป็นจำำนวนเต็มบวก
1. ( ) 4035 −−−
zyx
=
404345
)z()y()x( −−−−−
=
01220
zyx
=
1220
yx
2. 3743
4305
2
4
cba
cba
−−−
−−−
=
3)4()7()3()4(0
3
52
cba
2
)2( −−−−−−−
−
−
=
744
3
10
cba
2
2 −
−
−
= 7
44)3()10(
c
ba2 −−−
= 7
447
c
ba2−
= 77
44
c2
ba
3.
2
533
404
8
2
−
−−
−






yx
yx
=
2
3
9
4
yx
2
2
−






= ( ) 235
yx2
−−
=
2610
yx2 −−
= 26
10
yx
2
4. 524
323
−+
+−
⋅
⋅
nn
nn
yx
yx
=
)5n2()3n()4n()2n3(
yx −−++−−
⋅
=
8n6n2
yx +−−
⋅
5. 12
12
2
144
−−
−−
−
+−
xx
xx
=
x
1
x
2
1
x
4
x
4
2
2
−
+−
=
2
2
2
x
x2
x
xx44
−
+−
= x2
xx44 2
−
+−
= x2
)x2)(x2(
−
−−
= 2 – x
6. 1
3
1
2
5
2
15
6
+
+
−−
+−
⋅ n
n
n
n
= 1n
3n
1n
2n
5
2
)53(
)23(
+
+
−−
+−
⋅
⋅
⋅
= 1n
3n
1n1n
2n2n
5
2
53
23
+
+
−−−−
+−+−
⋅
= )1n()1n(
)3n()2n()1n()2n(
5
23
++−−
+++−−−−+−
= 0
53
5
23
= 53
23
2
7. 1
1
22
2423
−
−
−
⋅−⋅
nn
nn
= 1nn
1nn
222
22423
−
−
⋅−
⋅⋅−⋅
=
)
2
1
1(2
)
2
4
3(2
n
n
−
−
=
2
1
2
2
2
4
2
6
−
−
=
2
1
2
2
= 1
2
2
2
×
= 2
8.
2
46
9
1
24381 




⋅⋅ −
= ( )222024
333 −−
⋅⋅
= 44
33 −
⋅
= 0
3
Ex 2. จงเขียนจำำนวนต่อไปนี้ให้อยู่ในรูปสัญกรณ์วิทยำศำสตร์
1. 1,002,000,000 =
1.002 × 109
2. 0.0000004123 =
4.123 × 10-7
3. 0.0078 = 7.8
× 10-3
4. 17,600,000 =
1.76 × 107
5. 323 × 105
= 3.23 ×
102
× 105
= 3.23 × 107
6. 6,000 × 10-7
= 6 ×
103
× 10-7
= 6 × 10-4
3
Ex 3. จงหาค่าในแต่ละข้อต่อไปนี้
1.
( )( )
0012.0
008.0006.0
=
( )( )
4
33
1012
108106
−
−−
×
××
= 




 ×





 ×
−
−−
4
33
10
1010
12
86
=
2
104 −
×
2.
( )( )
00033.0
000009.0000,220
=
( )( )
5
64
1033
1091022
×
×× −
=
7
106 −
×
3.
( )( )
000000048.0
000,000,000,240000064.0
=
( )( )
9
97
1048
10241064
−
−
×
××
=
11
1032×
=
11
10102.3 ××
=
12
102.3 ×
4.
( ) ( )
( ) 2
2
000,12
0009.0000,320
=
( ) ( )
( )23
424
1012
1091032
×
××
=
( )( )
( )6
48
101212
109103232
××
×××
=
6
1064×
=
6
10104.6 ××
=
7
104.6 ×

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00000070 1 20130107-130231

  • 1. 1 Ex 1.จงทำำให้เป็นรูปอย่ำงง่ำยและมีเลขชี้กำำลังเป็นจำำนวนเต็มบวก 1. ( ) 4035 −−− zyx = 404345 )z()y()x( −−−−− = 01220 zyx = 1220 yx 2. 3743 4305 2 4 cba cba −−− −−− = 3)4()7()3()4(0 3 52 cba 2 )2( −−−−−−− − − = 744 3 10 cba 2 2 − − − = 7 44)3()10( c ba2 −−− = 7 447 c ba2− = 77 44 c2 ba 3. 2 533 404 8 2 − −− −       yx yx = 2 3 9 4 yx 2 2 −       = ( ) 235 yx2 −− = 2610 yx2 −− = 26 10 yx 2 4. 524 323 −+ +− ⋅ ⋅ nn nn yx yx = )5n2()3n()4n()2n3( yx −−++−− ⋅ = 8n6n2 yx +−− ⋅ 5. 12 12 2 144 −− −− − +− xx xx = x 1 x 2 1 x 4 x 4 2 2 − +− = 2 2 2 x x2 x xx44 − +− = x2 xx44 2 − +− = x2 )x2)(x2( − −− = 2 – x 6. 1 3 1 2 5 2 15 6 + + −− +− ⋅ n n n n = 1n 3n 1n 2n 5 2 )53( )23( + + −− +− ⋅ ⋅ ⋅ = 1n 3n 1n1n 2n2n 5 2 53 23 + + −−−− +−+− ⋅ = )1n()1n( )3n()2n()1n()2n( 5 23 ++−− +++−−−−+− = 0 53 5 23 = 53 23
  • 2. 2 7. 1 1 22 2423 − − − ⋅−⋅ nn nn = 1nn 1nn 222 22423 − − ⋅− ⋅⋅−⋅ = ) 2 1 1(2 ) 2 4 3(2 n n − − = 2 1 2 2 2 4 2 6 − − = 2 1 2 2 = 1 2 2 2 × = 2 8. 2 46 9 1 24381      ⋅⋅ − = ( )222024 333 −− ⋅⋅ = 44 33 − ⋅ = 0 3 Ex 2. จงเขียนจำำนวนต่อไปนี้ให้อยู่ในรูปสัญกรณ์วิทยำศำสตร์ 1. 1,002,000,000 = 1.002 × 109 2. 0.0000004123 = 4.123 × 10-7 3. 0.0078 = 7.8 × 10-3 4. 17,600,000 = 1.76 × 107 5. 323 × 105 = 3.23 × 102 × 105 = 3.23 × 107 6. 6,000 × 10-7 = 6 × 103 × 10-7 = 6 × 10-4
  • 3. 3 Ex 3. จงหาค่าในแต่ละข้อต่อไปนี้ 1. ( )( ) 0012.0 008.0006.0 = ( )( ) 4 33 1012 108106 − −− × ×× =       ×       × − −− 4 33 10 1010 12 86 = 2 104 − × 2. ( )( ) 00033.0 000009.0000,220 = ( )( ) 5 64 1033 1091022 × ×× − = 7 106 − × 3. ( )( ) 000000048.0 000,000,000,240000064.0 = ( )( ) 9 97 1048 10241064 − − × ×× = 11 1032× = 11 10102.3 ×× = 12 102.3 × 4. ( ) ( ) ( ) 2 2 000,12 0009.0000,320 = ( ) ( ) ( )23 424 1012 1091032 × ×× = ( )( ) ( )6 48 101212 109103232 ×× ××× = 6 1064× = 6 10104.6 ×× = 7 104.6 ×