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3. Feb 2023•0 gefällt mir•3 views

3. Feb 2023•0 gefällt mir•3 views

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A sample of xenon gas at a pressure of 805 mm Hg and a temperature of 40 Â° C, occupies a volume of 6.47 liters. If the gas is cooled at constant pressure to a temperature of 5 Â° C, the volume of the gas sample will be L. Solution for an ideal gas PV/T = constant at constant pressure V/T = constant so Vf / Tf = Vi / Ti Vf = Vi (Tf/Ti) given Vi = 6.47 L Ti = 40 C = 40 + 273 K = 313 K Tf = 5 C = 5 + 273 K = 278 K plug in the values Vf = 6.47 L x ( 278 K / 313 K) Vf = 5.7465 L so the final volume of the gas sample is 5.7465 L .

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- 1. A sample of xenon gas at a pressure of 805 mm Hg and a temperature of 40 Â° C, occupies a volume of 6.47 liters. If the gas is cooled at constant pressure to a temperature of 5 Â° C, the volume of the gas sample will be L. Solution for an ideal gas PV/T = constant at constant pressure V/T = constant so Vf / Tf = Vi / Ti Vf = Vi (Tf/Ti) given Vi = 6.47 L Ti = 40 C = 40 + 273 K = 313 K Tf = 5 C = 5 + 273 K = 278 K plug in the values Vf = 6.47 L x ( 278 K / 313 K) Vf = 5.7465 L so
- 2. the final volume of the gas sample is 5.7465 L