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A firm has estimated that the demand for its product comes from two types of customers, type I and type II. Each type I customer - there are 30 of them - has a demand curve given by Q = 20 - P , while each type II customer - there are 50 of them - has a demand curve given by Q = 15 - P . The firm\'s marginal cost is constant and equal to $5. Suppose the firm wants to use a two-part pricing strategy ( T; P ), and it has decided to set P = $5 (we know this need not be optimal, but this is what the firm has decided to set). With P = $5, the profit-maximizing T is T = $50 T = $112.5 T = $75 None of the Above Solution T=$50 .

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Computing an average mark for four tests Design the algorithm and then write a C++ program that prompts the user to enter the first name, family name, M for male or F for female and then the marks for four tests, which are all integer (whole) numbers. The program then computes and prints the average of these marks. Your output should have a header which has the 9 titles (firs name. last name, gender, 4 marks and the average) on one line followed by the actual data and the computed average on the next line, with the two lines separated by one blank line. Solution Answer #include <iostream> #include <iomanip> using namespace std; int main() { char first_name[20],family_name[20],gender; int i,marks[4],total=0; double average_marks; cout<<\"\ Enter First name : \"; cin>>first_name; cout<<\"\ Enter Family name : \"; cin>>family_name; cout<<\"\ Enter Genter M ot F : \"; cin>>gender; cout<<\"\ Enter Marks : \"; for(i=0;i<4;i++) { cin>>marks[i]; total+=marks[i]; } average_marks=double(total/4.0); cout<<\"\ \ First\"<<setw(8)<<\"Famiy\"<<setw(8)<<\"Gender\"<<setw(8)<<\"Marks1\"<<setw(8)<<\"Marks2\"<<setw(8)<<\"Marks3\"<<setw(8)<<\"Marks4\"<<setw(15)<<\"Average_Marks\"<<setw(5)<<\"\ \ \"; cout<<first_name<<setw(8)<<family_name<<setw(8)<<gender<<setw(8); for(i=0;i<4;i++) { cout<<marks[i]<<setw(8); } cout<<setprecision(4)<<average_marks; return 0; } .

Computing an average mark for four tests Design the algorithm and the.docx

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Computer Networks: Write either True or False 1. In LTE, a mobile device may have multiple EPS bearers established: T/F 2. RIP can handle a max of 15 hops: T / F 3. In the hierarchical OSPF, area border routers run multiple instances of OSPF algorithms. T/F 4. An n-bit-CRC can detect with probability 1 any single error burst not longer than n bits. T/F 5. In random access, Carrier Sensing is a technique that guarantees no collision will happen. T/F 6. In Ethernet, due to exponential backoff, if a sender waited for T units of time before sending but experienced a collision, at the next attempt, the sender will wait for 2*T, then resends. T/F 7. ARP is Plug and Play: T/F 8. A MAC address needs to be updated through self learning when the host changes location. T/F 9. The Internet routing protocols require every provider network to advertise every path available through their AS. T/F 10. The Ethernet preamble is used to synchronize the receiver and sender clock rates. T/F Solution 1. True 2. True 3) False 4) True 5) True, it avoides the collision technique 6) False 7) True, ARP is â€œ plug-and-playâ€: nodes create their ARP tables without intervention from net administrator. Routing to another LAN 8) False, No need to update it automatically update when it takes the inputs from, the admionistrator 9) False 10) True .

Computer Networks- Write either True or False 1- In LTE- a mobile devi.docx

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Computation of weighted average shares outstanding during the year: January 1Â Â Â Â Â Â Â Â Â Â Â OutstandingÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 700,000 March 1Â Â Â Â Â Â Â Â Â Â Â Â Â Repurchase (5/6 Solution Computation of no. of shares outstanding during the year .

Computation of weighted average shares outstanding during the year- J.docx

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Comprehensive Problem 5 (Part Level Submission) On December 1- 2014- J.docx

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Completely classify liquid FeFe. Pure Substance Compound Mixture Element Homogeneous Mixture Heterogeneous Mixture Solution liquid FeFe is an element because is a simplest type of a pure substance which is composed of only one type of matter. For examples; silver, gold platinum etc. Element: An element is a simplest type of a pure substance which is composed of only one type of matter. For examples; silver, gold platinum etc. Pure substance: A compound is a pure substance which is composed of two or more type of matter in definite proportion. For examples; water which is composed by Hydrogen and oxygen etc. Compound: A compound is a pure substance which is composed of two or more type of matter in definite proportion. For examples; water which is composed by Hydrogen and oxygen etc. Mixture: A mixture is made from two or more type of matter in any proportion. Mixture are generally two types: This is also known as solution, in which the composition of the substances is uniform. Lemon-flavored water is an example of homogeneous mixture because in this the composition of the substances is uniform. In this form of mixture the composition of substance are not uniform and the component of mixture also visible. Stuffed mushrooms is an example of Heterogeneous mixture because in this form of mixture the composition of substance are not uniform and the component of mixture also visible. .

Completely classify liquid FeFe- Pure Substance Compound Mixture Eleme.docx

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Complete the following table by calculating the missing entries and indicating whether the solution is, acidic or basic. (Make sure you show your work!) OH1 Acidic or basic? [H\'1 pH pOH 6.8 x 10-3 M 2.1 x 109 M 6.73 4.25 HTML Editor OH-] Acidic or Basic? pH pOH 6.8 x 103 M 2.167 2.1 x 109 M 6.73 4.25 table tbody tr tod 19 words Solution [H+] = 6.8x10^-3M [H+][OH-] = Kw where Kw = ionic product of water = 1.0x10^-14 [OH-] = Kw/[H+] = 1.0x10^-14/6.8x10^-3 = 1.47x10^-12 [OH] = 1.47x10^-12M [H+] = 6.8x10^-3 -log[H+] = -log( 6.8x10^-3) PH= 2.167 PH+POH= 14 POH= 14-PH POH= 14-2.167 =11.833 [H+] = 6.8x10^-3M, [OH-]= 1.47x10^-12M, PH= 2.167 , POH= 11.833 PH<7, so the nature of solution is acidic. b) [OH-] = 2.1x10^-9M [H+] = 1.0x10^-14/2.1x10^-9 = 4.76x10^-6 [H+] = 4.76x10^-6M -log[H+] = -log( 4.76x10^-6) PH= 5.322 POH= 14-5.322 POH= 8.678 [H+] = 4.76x10^-6M , [OH-] = 2.1x10^-9M , PH= 5.322, POH= 8.678 PH<7, so the nature of the solution is acidic c) PH= 6.73 -log[H+] = 6.73 [H+] = 10^-6.73 [H+] = 1.86x10^-7M [OH-] = 1.0x10^-14/1.86x10^-7 [OH-] = 5.376x10^-8M POH= 14-6.73 POH= 7.27 [H+] = 1.86x10^-7M. [OH-] = 5.376x10^-8, PH= 6.73, POH= 7.27 PH<7, so the nature of the solution is acidic nature, d) POH=4.25 PH= 14-4.25=9.75 PH= 9.75 -log[H+] = 9.75 [H+] = 10^-9.75 [H+] = 1.778x10^-10M [OH-] = 1.0x10^-14/1.778x10^-10 [OH-] = 5.62x10^-5 [H+] 1.778x10^-10M, [OH-] = 5.62x10^-5M , PH= 9.75, POH= 4.25 PH>7, so the nature of the solution is basic . .

Complete the following table by calculating the missing entries and in.docx

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Compare the models and information found with Nonaka Solution developed a four stage spiral model of organizational learning. They started by differentiating Polanyi\'s concept of \"tacit knowledge\" from \"explicit knowledge\" and describe a process of alternating between the two. Tacit knowledge is personal, context specific, subjective knowledge, whereas explicit knowledge is codified, systematic, formal, and easy to communicate. The tacit knowledge of key personnel within the organization can be made explicit, codified in manuals, and incorporated into new products and processes. This process they called \"externalization\". The reverse process (from explicit to tacit) they call \"internalization\" because it involves employees internalizing an organization\'s formal rules, procedures, and other forms of explicit knowledge. They also use the term \"socialization\" to denote the sharing of tacit knowledge, and the term \"combination\" to denote the dissemination of codified knowledge. According to this model, knowledge creation and organizational learning take a path of socialization, externalization, combination, internalization, socialization, externalization, combination . . . etc. in an infinite spiral. Recently Nonaka returned to this theme in an attempt to move this model of knowledge conversion forwards. Social media challenge knowledge management because of encouraging conversations, networking and participation in more distributed, diverse and dynamic ways of knowledge development and increasingly important individuals .

Compare the models and information found with NonakaSolutiondeveloped.docx

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Compare the models and information found with NonakaSolutiondeveloped (2).docx

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Complete the following Java code such that it opens a file named FruitList.txt, reads the first line from the file, and then prints the first line on console screen. Your Java code should handle possible exception(s). Assume that the file contains the name of a fruit in each line. You don\'t need to provide comments. // complete import statement(s) here public class FileRead { public static void main(String[] args) { // complete the code here } } Solution import java.io.File; import java.util.Scanner; /** * @author * */ public class FileRead { /** * @param args */ public static void main(String[] args) { // complete the code here Scanner scanner = null; try { File file = new File(\"FruitList.txt\"); scanner = new Scanner(file); // checks the file contains data if (scanner.hasNext()) { // prints first line System.out.println(scanner.nextLine()); } } catch (Exception e) { // TODO: handle exception } } } FruitList.txt Apple Orange Papaya Banana Jack Fruit Watermelon KIWI Grapes Mango Pineapple OUTPUT: Apple .

Complete the following Java code such that it opens a file named Fruit.docx

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Compare the models and information found with NonakaSolutiondeveloped (1).docx

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Compare and contrast the Internal Rate of Return (IRR), the Net Present Value (NPV) and Payback approaches to capital rationing. Which do you think is better? Why? Solution Capital rationing is used when the capital is short or limited in supply and the organization cannot afford to choose all the projects. Therefore, organizations have to make best use of available capital resource and hence it chooses the project based on profitability. Internal rate of return is a rate of return at which NPV is zero. IRR is a measure of profitability. NPV or net present value is the difference between Present value of cash flows and initial investment. It measures the net addition to shareholders wealth. Payback period is the period of time the project takes to recover the initial investment. Payback period is the measure of liquidity. Profitability index is the best method when capital is rationed. If Profitability index method is not available, we should prefer using IRR method .

Compare and contrast the Internal Rate of Return (IRR)- the Net Presen.docx

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Consider a system consisting of processes P1, P2, ... , P11, each of which has a unique priority number. Write a monitor that allocates three identical line printers to these processes, using the priority numbers for deciding the order of allocation. Solution Monitors are implemented by using queues to keep track of the processes attempting to become active int he monitor. To be active, a monitor must obtain a lock to allow it to execute the monitor code. Processes that are blocked are put in a queue of processes waiting for an unblocking event to occur. The code for monitor is as follows: type printer = monitor var P: array[0â€¦2] of boolean; X: condition; procedure acquire (id: integer, printer-id: integer); begin if P[0] and P[1] and P[2] then X.wait(id) if not P[0] then printer-id := 0; else if not P[1] then printer-id := 1; else printer-id := 2; P[printer-id]:=true; end; procedure release (printer-id: integer) begin P[printer-id]:=false; X.signal; end; begin P[0] := P[1] := P[2] := false; end ; .

Consider a system consisting of processes P1- P2- --- - P11- each of w.docx

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Consider a healthcare organization that you are familiar with and present one or two challenges that is likey to arise during the investment decision making process, as well as any possible solutions. Solution Solution- These types of decision needed before the investment made that are following below: Maintain emergency funds: When they would invest in property and equipment, then there would be a lot of uncertainty in the market rate of property and equipment material. So, they must maintain the emergency fund if their price raised in the market as compared to investment capital budget. (Bordonaro, 2014) Draw a financial roadmap: They must build financial guideline, especially if they never made it in earlier. It will encourage the confidence that the plan would perfect because they have past experience in this kind of financial roadmap. (Bordonaro, 2014) The main challenge is arising in the decision making that the lack of money because entire project will spend a lot of money and no initial return from it, but through the maintain emergency fund and draw a financial roadmap we can reduce the challenges of it and hope it would help to become successful in the aggressive capital investment in the perspective of health care organization. .

Consider a healthcare organization that you are familiar with and pres.docx

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