1) The slope of the line through (2, 5) and (-1, -7) is -3. 2) The solutions for x2 - 5x = 9 are x = 3, x = -3. 3) The solution for 3x + 7 < 5x - 10 in interval notation is (-∞, 2).

1. Algebra Review A Trashketball Game

2. Find the slope of the line. . . through (2, 5) and (-1, -7) 4

3. Solve for x. x2 - 5x = 9

4. Solve. Write the answer in interval notation. 3x + 7 < 5x - 10

5. Write the equation of the line. . . through (-2, 8) and (1, 2). (Use slope-intercept form) y = -2x + 4

6. Solve for x. 3x2 + x + 2 = 0

7. Solve. 3(x – 4) + 2x ≥ 6(x – 1) (-∞,-

8. Write the equation of the line. . . through (6, 5), perpendicular to 3x + 2y = 7. Use slope-intercept form. y = 2/3 x + 1

9. Solve for x. 16x2 = 24x x = 0, 3 2

10. Write the equation of lines through (7, -2). . . Horizontal Vertical y = -2 x = 7