Ms. Lorie Jane L Letada
Rational Expressions is an algebraic expression where both
numerator and denominator are polynomials. Duringelementaryyears,youhave
learned that a fraction is a ratio of a numerator and denominator where the
denominator is not equal to zero, but in this module, we extend the concept of
fractions to algebraic expressions.
Here is the map of the lessons that will be covered in this module.
Modul
e 2 Rational
Expressions
At the end of this module, the learners will:
1. illustrate rational expressions;
2. simplify rational expressions;
3. perform operations on rational algebraic expressions;
4. solve problems involving rational expressions.
Rational Expressions
Simplifying Rational expressions
Operation of Rational Expressions
Adding and Subtracting
Rational Expressions
Multiplying and Dividing
Rational Expressions
Module 2: Rational Expressions
Read and analyze each item carefully and encircle the letter of the
best answer.
Pre-test!
Ms. Lorie Jane L Letada
A Rational Expressions is reduced to its simplest form if the
numerator and denominator have no common factors. Putting a rational
expression in its simplest form is important as this will make operations
easier.
Simplify the following in its simplest form.
1.
4π
12π
2.
9π
21π
3.
4π€2
6π€β8π€2
Lesson
1
Simplifying Rational
Expressions
Step 1
Factor thenumerator and
denominator and get theGCF.
4a = (2) (2) a
12b= (3) (2) (2) b
GCF: (2) (2)
GCF: 4
Thus, the common factor is 4.
Step 2:
Divideout thecommon factor.
4π
12π
=
4 ( π )
4 (3π)
=
π
3π
Thus, the simplify is
π
3π
.
Step 1
Factor thenumerator and
denominator and get the GCF.
9m =
21n =
GCF:
GCF:
Thus, the common factor is __.
Step 2:
Divide out the common factor.
Step 1
Get theGCF of each term.
4π€2
= (2) (2) (w) (w)
6w = (3) (2) (w)
8π€2
= (2)(2) (2)(w)
GCF: (2) (w)
GCF: 2w
Thus, the common factor is 2w.
Step 2:
Factor the common
numerator and
denominator.
4π€2
6π€β8π€2 =
2π€ ( 2)
2π€ (3β4π€ )
Step 3:
Divide out the common
factor.
4π€2
6π€β8π€2 =
2π€ ( 2)
2π€ (3β4π€ )
=
2
3β4π€
Thus, the simplify is
2
3β4π€
.
Module 2: Rational Expressions
4.
6π2
2πβ4π3
5.
2π₯β2π¦
π¦2β π₯2
6.
3π₯+ 3π¦
π₯2β π¦2
7.
4π+ 4π
π2 β π2
Step 1
Get theGCF of each term.
6π2
=
2p =
4π3
=
GCF:
GCF:
Step 2:
Factor the common
numerator and
denominator.
6π2
2πβ4π3 =
Step 3:
Divide out the common factor.
Step 1
Factor thecommon numerator
and denominator.
2π₯β2π¦
π¦2 β π₯2 =
2 (π¦βπ₯)
( π¦βπ₯ )(π¦+ π₯)
Step 2:
Divide out the common factor.
2π₯β2π¦
π¦2 β π₯2 =
2 (π¦βπ₯)
( π¦βπ₯ )(π¦+ π₯)
=
2
(π₯+ π¦)
You can only apply the
difference of two squares if:
*The two terms are both
perfect squares.
*The operation is subtraction.
Example:
π¦2
β π₯2
= (y β x ) ( y + x )
Step 1
Factor thecommon numerator
and denominator.
3π₯+ 3π¦
π₯2 β π¦2 =
Step 2:
Divide out the common factor. To factor π₯2
β π¦2
, get
the square root of each term.
First Term: βx2 = x
Second Term: βy2= y
Usingx and y, form the
sum (x + y) & thedifference
(x - y).
Thus, x2
- y2
= (x + y) (x β y).
Step 1
Factor thecommon numerator
and denominator.
4π+ 4π
π2β π2 =
Step 2:
Divide out the common factor.
A variable
is perfect
square if
its
exponent
is even
number.
Ms. Lorie Jane L Letada
8.
π2+πβ6
π2β7π+10
9.
π2β7πβ30
π2β5πβ24
10.
π2β49
π2β2πβ35
Simplify each rational expression.
1.
5ππ2
20ππ
= 5.
π₯β1
5π₯β5
=
2.
5πβ
10π
= 6.
π2+2πβ15
π2βπβ6
=
3.
15ππ2
45ππ3 π
= 7.
π2+7π+10
π2+5π
=
4.
π₯2β9
π₯2βπ₯β6
= 8.
π2+8π+12
π2+3πβ18
=
Skill Booster!
Step 1
Factor thecommon numeratorand
denominator.
π2+πβ6
π2β7π+10
=
( π+3)(πβ2 )
( πβ5)(πβ2)
Step 2:
Divide out the common factor.
π2+πβ6
π2β7π+10
=
( π+3)(πβ2 )
( πβ5)(πβ2)
=
(π+3)
(πβ5)
Step 1
Factor thecommon numeratorand
denominator.
π2β7πβ30
π2β5πβ24
=
Step 2:
Divide out the common factor.
Step 1
Factor thecommon numeratorand
denominator.
π2β49
π2β2πβ35
=
(πβ7(π+7)
( πβ7)(π+5 )
Step 2:
Divide out the common factor.
π2β49
π2β2πβ35
=
(πβ7 (π+7)
( πβ7 )(π+5)
=
( π+7)
(π+5)
To factor π2
+ π β 6 ,
find any factors of -6
that when you add the
result is 1,
Hence, the correct pair
is 3 and -2.
So, the factors of
π2
+ π β 6 = (m +3)
(m -2).
* When you multiply
positive & negative
numbers, the result is
negative.
Example: (5 )(-3)=-15
*When you add positive
& negative numbers,the
sign used in the result
will be based which
absolute num. is greater.
Examples: 5 +-3 =2
*When you add positive
& negative numbers,the
sign used in the result
will be based which
absolute num. is greater.
Examples: 5 +-3 =2
Module 2: Rational Expressions
To multiply rational expressions, recall the rules for multiplying
fractions. If the denominators are not equal to zero, then we simply
multiply the numerators and denominators. The same rule applies to
rational expressions.
If a, b, c, and d represent polynomials where b β 0 and d β 0. Then,
Multiply each rational expression and simplify.
1.
π
ππ
β
π
ππ
=
2.
π
ππ
β
π
ππ
=
3.
ππ
ππ π β
π π
πππ π =
Lesson
2
Multipication of Rational
Expressions
π
π
β
π
π
=
ππ
ππ
Step 1 Factor each expression.
π
ππ
β
π
ππ
=
π
( π)(π)
β
( π) (π)
( π) (π)
Step 2 Cancel all common
factors.
π
( π)(π)
*
( π) (π)
( π) (π)
Step 3: Write what is left.
π
ππ
β
π
ππ
=
π
( π) (π)
=
π
π
Step 1 Factor each expression. Step 2 Cancel all common
factors.
Step 3: Write what is left.
Step 1: Factor each expression.
ππ
ππ π β
π π
πππ π =
( π )( π)
( π)(π π)
β
( π π)(π π
)
( π)( π)(π π)
Step 2 Cancel all common factors.
ππ
ππ π β
π π
πππ π =
( π ) ( π)
( π) (π π)
β
( π π) (π π
)
( π) ( π) (π π)
Step 3: Write what is left.
ππ
ππ π β
π π
πππ π =
π
(π)(π)
=
π
π
Ms. Lorie Jane L Letada
4.
ππ
ππ π β
ππ π
πππ π =
π.
ππ π
βπ
π π βππ+π
β
ππβπ
ππ+ππ
=
π.
π+π
π
β
πππ π
π π +ππ+ππ
=
π.
ππ
ππ+π
β
ππ+π
ππ π =
π .
π
πβπ
β
(πβπ ) π
π
=
Step 1: Factor each
expression.
Step 2 : Cancel all common
factors.
Step 3: Write what is left.
Step 1: Factor each expression.
ππ π
βπ
π π βππ+π
β
ππβπ
ππ+ππ
=
( ππβπ )(ππ+π)
( πβπ)(πβπ)
*
π ( πβπ )
π(ππ+π)
Step 2 : Cancel all common factors.
ππ π
βπ
π π βππ+π
β
ππβπ
ππ+ππ
=
( ππβπ )(ππ+π)
( πβπ)(πβπ)
*
π ( πβπ )
π(ππ+π)
Step 3: Write what is left.
ππ π
βπ
π πβππ+π
β
ππβπ
ππ+ππ
=
( ππβπ )
( πβπ)
β
π
π
=
π ( ππβπ )
π ( πβπ )
Showyour solution here .β¦.
Step 1: Factor each expression.
ππ
ππ+π
β
ππ+π
ππ π = ππ
π(ππ+π)
β
(ππ+π)
π ( ππ )
Step 2 : Cancel all common factors.
ππ
ππ+π
β
ππ+π
ππ π = ππ
π(ππ+π)
β
(ππ+π)
π ( ππ )
ππ
ππ+π
β
ππ+π
ππ π =
π
π ( π)
=
π
ππ
Showyour solution here .β¦.
Cancelation involving
rationalexpressions should
be applied carefully. In the
expression
2π₯β3
π₯β3
,youcannot
cancel x in the numerator
and denominator even
though
π₯
π₯
is equal to1
because it is not a factor of
2π₯β3
π₯β3
. πΌπ ππππ‘,
2π₯β3
π₯β3
is already in simplest
form.
Factor, in
mathematics, a
number or
algebraic
expression that
divides another
number or
expression
evenlyβi.e., with
no remainder. For
example, 3 and 6
are factors of 12
because 12 Γ·3 =4
exactly and 12 Γ·6
= 2 exactly.
Module 2: Rational Expressions
Math Focus
To multiply rational expressions:
ο· Write each numerator and denominator in factored form.
ο· Divide out any numerator factor with any matching
denominator factor.
ο· Multiply numerator by numerator and denominator by
denominator.
ο· Simplify as needed.
Multiply each rational expression and simplify .
1.
ππ
ππ
β
π
π
= 5.
(π π
+ππ+π )
πβπ
*
π+π
π π+ππ+π
=
2.
πππ
ππ π β
ππ π
πππ π = 6.
(π π
βπ )
ππ π
*
(ππ π
ππ+π
=
3.
πππ
ππ π β
ππ π
πππ π = 7.
(π π
+ππ+π )
π+π
*
ππ+ππ
π+π
= =
4.
ππ+π
ππβπ
*
(π π
+πβπ )
π
=
Skill Booster!
Ms. Lorie Jane L Letada
In dividing rational expressions, observe the same rules as when
dividing fractions.
If the denominators are not equal to zero, then
Lesson
3
Division of Rational
Expressions
π
π
Γ·
π
π
=
π
π
β
π
π
=
ππ
ππ