this is a simple concept about spur gear and design in solidworks

2. Reason for choosing this problem
• To know more basic concept about power transmission.
• We will get more information about the technical
component.
• We choose this problem because it is related to our
subject which is studying In regular lecture.

3. Task July 2018 August 2018
Week1 Week2 Week3 Week4 Week5 Week6 Week7
Study of topic
Get basic
Knowledge about
spur gear
Find some formulas
of spur gear
Made a design of
spur Gear in Solid
works
Find research paper
Search :-How the
spur Gear are made

9. Sr. no Topic
name
Site detail author
1 Design and
modification
https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=w
eb&cd=1&ved=2ahUKEwjp3cXAkZPdAhVQfn0KHRElB-
cQFjAAegQIChAC&url=http%3A%2F%2Fdownloads.hindawi.com
%2Fjournals%2Fmpe%2F2015%2F897257.pdf&usg=AOvVaw1qO
xngXg9hki-j80CczO-e
Xiaohe Deng,
Lin Hua, and
Xinghui Han
2 Design of
tooth profile
https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=w
eb&cd=3&cad=rja&uact=8&ved=2ahUKEwjp3cXAkZPdAhVQfn0K
HRElB-
cQFjACegQICRAC&url=http%3A%2F%2Fwww.ijera.com%2Fpape
rs%2FVol2_issue2%2FEI22820827.pdf&usg=AOvVaw1YOmk2HL0
USRQXWKcwJ4_k
Mr. A. Gopi
chand
3 Spur Gear Tooth
Stress Analysis
And Stress
Reduction
http://www.iosrjournals.org/iosr-
jmce/papers/ICRTEM/ME/Volume-
1/IOSRME007.pdf
V.Rajaprabakara
n, Mr.R.Ashokraj

11. m=2
t=20
T=68
Ф=17°
a=2mm
r=mt/2= 2×20÷2 =20mm
R=mT/2= 2×68÷2 =68mm
ra=r+a=20+2=22mm
Ra=R+a=68+2=70mm
*Length of path of approach
KP=(Ra^2-R^2cos^2Ф)^1/2-RsinФ
KP=((70)^2-(68)^2cos^2(17°))^1/2-68sin(17°)
KP=6.02mm
*Length of path of recess,
PL=(ra^2-r^2cos^2Ф)^1/2-rsinФ
PL=((22)^2-(20)^2cos^2(17°))^1/2-20sin17°
PL=5.03mm

12. * length of path of contact
KL=KP+KL
KL=6.02+5.03
KL=11.05mm
* length of arc of contact=length of path of contact/cosФ
=11.55/cos17°
=11.55mm
* Contact ratio = length of arc of contact/πm
= 11.55/3.14 ×2
=1.83 say 2
*Angle turned by pinion = length of arc if contact×360°/Circumference of pinion
=11.55×360°/2πr
=33°6‘
*angle turned by large gear =length of Arc of contact ×360°/circumference of gear
=11.55×360°/(2×3.14×68)
=9°41'