2. Find the equation of the parabola that satisfied the following conditions.Vertex (0,0), latus rectum = 16, opens to the right. Solution Latus rectum for standard parabola = |4a| Hence |a| for the given parabola = 4 As vertex is at (0,0) and the parabola open to the right focus is (4,0) The standard equation is y² = 4ax. The equation of the given parabola = y² = 4*4x = 16x.