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RADICALS
Properties of Surds
                                                     1                 1
                                 n                                             4
     Definition :                    a           a   n
                                                                  16   4
                                                                                   16       2
         m               1   m               m
                                     n                            3                 3            3
     a   n
                     a   n               a                16      4        4
                                                                               16           2        8
          m                  1
                         m           n       m                3
                                                                       4
                                                                           163
                             n
      a   n
                     a                   a               16   4                         4
                                                                                            4096         8

                                                                               m             n       m
                                                                      n
                                                                           a                     a
Jeff Bivin -- LZHS
Simplify the surds
      For positif real numbers a and b

                     n                       n        n
                          a.b                    a. b
              32          16.2               16. 2        4 2
          3 294            3 49.6            3 49. 6 3.7. 6 21 6
          3
              32     3
                         8.4    3
                                    8. 3 4        3
                                                 2 4
Jeff Bivin -- LZHS
Simplify!!!!!


             288         12 2

            500      x   10 5
                           x x   x

                          3
        3
            500          5 4
Jeff Bivin -- LZHS
Algebraic Operation on Surds
      Addition and Subtraction
      Suppose , b
             a            R and c R

                     a c b c= a b          c

          5 5 10 5 = 5 10       5   15 5
           5 3       48 2 27 = 5 3 4 3 6 3      5 4 6   3
                                               3 3

             20      125 3 5 = 2 5 5 5 3 5 = 0

Jeff Bivin -- LZHS
Algebraic Operation on Surds
      Multiplication
      Suppose , b
             a                 R and c, d   R

                         a c .b d = ab. cd
            5 5.10 2 = 5.10 5.2 50 10
                3    2     3     2    3     6   6   2 5 2 6

            2 5      5 3 2 = 2.5 2.3 5.2 = 10 6 10


Jeff Bivin -- LZHS
Algebraic Operation on Surds
      Division
      Suppose , b
             a                    R and c, d       R

                     a c :b d = a:b                        c:d
                                                       1   1
           5 8 :10 2 = 5 :10            8: 2             4   .2 1
                                                       2   2
            2 3.3 2    6 6   1
                    =      =
             12 6     12 6   2
                                                   2           2
                5     2       5     2          5           2       3
                                                                       1
                          3                            3           3
Jeff Bivin -- LZHS
Simplify!!!!!


        0,36             0,16        1

    6 2              5   2 2 5      2 11 10
        a b
                                a    b
        a   b
Jeff Bivin -- LZHS
Simplifying Surds expression
                          (a b) 2 ab
and
 (a b) 2 ab

            2
   a    b         a b     2 ab
            2
    a   b         a b     2 ab

   a    b         a b     2 ab


            a b    2 ab      a   b
Simplifying Surds expression
                          (a b) 2 ab
and
 (a b) 2 ab

            2
   a    b         a b     2 ab
            2
    a   b         a b     2 ab

   a    b         a b     2 ab


            a b    2 ab      a   b
Example!

          5 2 6      3 2   2 3.2   3   2



         8 2 15      3 5   2 3.5   5   3




Jeff Bivin -- LZHS
Try this Questions!!!

                     3 2 2                     1       2

                     7 2 10                    5       2

                      8        48              6       2

                     14 6 5                    9       5

                     0,3
                           1
                               0, 08
                               1
                                           a       b
                                                           15
                                    ....
Jeff Bivin -- LZHS
                           a   b
Rationalizing Fractions Involving
      Surds
      Consider!!

                                              2           2
                         a b a b          a           b


                     a            a               a               Conjugate
                                                          2           2
                     a    b   a       b               a           b            a b
                                                                  2
                                                      2
                     a    b   a       b           a           b           a2    b

Jeff Bivin -- LZHS
Simplify

                     6   6
                             3
                     2   2




Jeff Bivin -- LZHS
Simplify

                10   10   3   30   30
                 3    3   3   9    3




Jeff Bivin -- LZHS
Simplify

      24             24      12      12   2 3    5
      10             10       5       5     5   5


                          2 15    2 15
                            25      5


Jeff Bivin -- LZHS
Simplify

                     1       3   2       3  2
              3          2   3   2   9 3 2 3 2 2


                                         3       2
                                             7


Jeff Bivin -- LZHS
Simplify

                     3       4   5        34   5
            4            5   4   5     16 4 5 4 5 5


                                 34        5   12 3 5
                                      11         11


Jeff Bivin -- LZHS
Simplify

                     2       1   7          21    7
                 1       7   1   7        1 7     7 7


                                 21       7   1       7
                                      6           3


Jeff Bivin -- LZHS
Simplify

                     3       2   3      2 3 3
              2          3   2   3   4 2 3 2 3 3


                                 2 3 3
                                         2 3 3
                                   1


Jeff Bivin -- LZHS
Simplify

                            3       2   3       2   3       2   3
           1           1        2           2           2            4
         3           3
            2           2   3
                                2   2   3
                                            2   3       2           2




Jeff Bivin -- LZHS
Simplify

                     5       5   4   5           4   5
         5
              2          2       3       2 3             162
                     5
              3          3   5   4
                                 3       5   5
                                             3           3




Jeff Bivin -- LZHS
Try this Questions!!!

                          1                   1
                                                2
                         2 2                  4


                               1         3
                                              ...
                                4        12

                     5    6
                               a b 30               9
                     5    6
                         a b   ......?

Jeff Bivin -- LZHS
Exponential Equations
        Properties

                         B       C
                     a       a           B C

       3x      27    3x 33    x 3
                               1             1        1       1
                1       2x   1 2  52 x   5   2   2x       x
       52 x        5   5   5 5                        2       4
                5
                  1
   3
       36 x   3

                  27         x       1
Jeff Bivin -- LZHS
Try this Questions!!!

                           x 2                              1
                       5                 125        x
                                                            2

                      4x    2       3
                                        16 x   5    x       4

                       1                                    5
                                         32    2x
                                                    x
                     273 x      7
                                                            2
                                 1
                                   x 3
                                 2
                     0, 09                              x       2
                                               1
                      0,33 x        1




Jeff Bivin -- LZHS
To be continued…

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Perpangkatan

  • 2. Properties of Surds 1 1 n 4 Definition : a a n 16 4 16 2 m 1 m m n 3 3 3 a n a n a 16 4 4 16 2 8 m 1 m n m 3 4 163 n a n a a 16 4 4 4096 8 m n m n a a Jeff Bivin -- LZHS
  • 3. Simplify the surds For positif real numbers a and b n n n a.b a. b 32 16.2 16. 2 4 2 3 294 3 49.6 3 49. 6 3.7. 6 21 6 3 32 3 8.4 3 8. 3 4 3 2 4 Jeff Bivin -- LZHS
  • 4. Simplify!!!!! 288 12 2 500 x 10 5 x x x 3 3 500 5 4 Jeff Bivin -- LZHS
  • 5. Algebraic Operation on Surds Addition and Subtraction Suppose , b a R and c R a c b c= a b c 5 5 10 5 = 5 10 5 15 5 5 3 48 2 27 = 5 3 4 3 6 3 5 4 6 3 3 3 20 125 3 5 = 2 5 5 5 3 5 = 0 Jeff Bivin -- LZHS
  • 6. Algebraic Operation on Surds Multiplication Suppose , b a R and c, d R a c .b d = ab. cd 5 5.10 2 = 5.10 5.2 50 10 3 2 3 2 3 6 6 2 5 2 6 2 5 5 3 2 = 2.5 2.3 5.2 = 10 6 10 Jeff Bivin -- LZHS
  • 7. Algebraic Operation on Surds Division Suppose , b a R and c, d R a c :b d = a:b c:d 1 1 5 8 :10 2 = 5 :10 8: 2 4 .2 1 2 2 2 3.3 2 6 6 1 = = 12 6 12 6 2 2 2 5 2 5 2 5 2 3 1 3 3 3 Jeff Bivin -- LZHS
  • 8. Simplify!!!!! 0,36 0,16 1 6 2 5 2 2 5 2 11 10 a b a b a b Jeff Bivin -- LZHS
  • 9. Simplifying Surds expression (a b) 2 ab and (a b) 2 ab 2 a b a b 2 ab 2 a b a b 2 ab a b a b 2 ab a b 2 ab a b
  • 10. Simplifying Surds expression (a b) 2 ab and (a b) 2 ab 2 a b a b 2 ab 2 a b a b 2 ab a b a b 2 ab a b 2 ab a b
  • 11. Example! 5 2 6 3 2 2 3.2 3 2 8 2 15 3 5 2 3.5 5 3 Jeff Bivin -- LZHS
  • 12. Try this Questions!!! 3 2 2 1 2 7 2 10 5 2 8 48 6 2 14 6 5 9 5 0,3 1 0, 08 1 a b 15 .... Jeff Bivin -- LZHS a b
  • 13. Rationalizing Fractions Involving Surds Consider!! 2 2 a b a b a b a a a Conjugate 2 2 a b a b a b a b 2 2 a b a b a b a2 b Jeff Bivin -- LZHS
  • 14. Simplify 6 6 3 2 2 Jeff Bivin -- LZHS
  • 15. Simplify 10 10 3 30 30 3 3 3 9 3 Jeff Bivin -- LZHS
  • 16. Simplify 24 24 12 12 2 3 5 10 10 5 5 5 5 2 15 2 15 25 5 Jeff Bivin -- LZHS
  • 17. Simplify 1 3 2 3 2 3 2 3 2 9 3 2 3 2 2 3 2 7 Jeff Bivin -- LZHS
  • 18. Simplify 3 4 5 34 5 4 5 4 5 16 4 5 4 5 5 34 5 12 3 5 11 11 Jeff Bivin -- LZHS
  • 19. Simplify 2 1 7 21 7 1 7 1 7 1 7 7 7 21 7 1 7 6 3 Jeff Bivin -- LZHS
  • 20. Simplify 3 2 3 2 3 3 2 3 2 3 4 2 3 2 3 3 2 3 3 2 3 3 1 Jeff Bivin -- LZHS
  • 21. Simplify 3 2 3 2 3 2 3 1 1 2 2 2 4 3 3 2 2 3 2 2 3 2 3 2 2 Jeff Bivin -- LZHS
  • 22. Simplify 5 5 4 5 4 5 5 2 2 3 2 3 162 5 3 3 5 4 3 5 5 3 3 Jeff Bivin -- LZHS
  • 23. Try this Questions!!! 1 1 2 2 2 4 1 3 ... 4 12 5 6 a b 30 9 5 6 a b ......? Jeff Bivin -- LZHS
  • 24. Exponential Equations Properties B C a a B C 3x 27 3x 33 x 3 1 1 1 1 1 2x 1 2 52 x 5 2 2x x 52 x 5 5 5 5 2 4 5 1 3 36 x 3 27 x 1 Jeff Bivin -- LZHS
  • 25. Try this Questions!!! x 2 1 5 125 x 2 4x 2 3 16 x 5 x 4 1 5 32 2x x 273 x 7 2 1 x 3 2 0, 09 x 2 1 0,33 x 1 Jeff Bivin -- LZHS