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1. Vedic Mathematics
Cultural Computing Initiatives
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The answer is divided into partsThe answer is divided into parts
Number of parts in the answer=Number of parts in the answer= (No. of digits in multiplicand +(No. of digits in multiplicand +
No. of digits in multiplier)-1No. of digits in multiplier)-1
Each part is product or sum of product of digits in multiplicandEach part is product or sum of product of digits in multiplicand
& multiplier.& multiplier.
In the answer each part should contain only one digit. The extraIn the answer each part should contain only one digit. The extra
digits are added to the immediate left.digits are added to the immediate left.

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Answer is divided into 3 partsAnswer is divided into 3 parts (2+2)-1=3(2+2)-1=3
The pattern for each part is given below :The pattern for each part is given below :
• •
• •
• •
• • • •
• •
RPRPLPLP MPMP
RP represents Units placeRP represents Units place
MP represents Tens placeMP represents Tens place
LP represents Hundreds placeLP represents Hundreds place
Here,Here,
Each dot (Each dot (••) represent single digit in the number & line jointly) represent single digit in the number & line jointly
represents the no’s to be multiplicationrepresents the no’s to be multiplication

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2 3
1 2
RP
6
RP =RP =
X
3x2 =3x2 = 66

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2 3
1 2
RPMP
7
MP :MP :
X
(3x1)(3x1) = 4+3=7= 4+3=7++(2x2)(2x2)

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2 3
1 2
LP RPMP
2
2x12x1
X
=2=2LP :LP :

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2 3
1 2
LP RPMP
2
LP :LP :
Ans:Ans: 276276
X
7 6
RP : 3x2=6RP : 3x2=6
MP :MP : (3x1)(3x1) = 4+3=7= 4+3=7++(2x2)(2x2)
=2=22x12x1

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3 2
4 1
21112
RP : 1x2=2RP : 1x2=2
MP : (3x1) + (4x2) =3+8=11MP : (3x1) + (4x2) =3+8=11
LP : (3x4)=12LP : (3x4)=12
Ans:Ans: 13121312
Note:Note: RP & MPRP & MP should have only one digit so extra digit is carried & added toshould have only one digit so extra digit is carried & added to LPLP
1
X

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4 3
3 5
152912
RP : 3x5= 1515
MP : (3x3) + (4x5) =9+20=29MP : (3x3) + (4x5) =9+20=29
LP : (3x4)=12LP : (3x4)=12
Ans:Ans: 15051505
Note:Note: RP & MPRP & MP should have only one digit so extra digit is carried & added toshould have only one digit so extra digit is carried & added to LPLP
12
X

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2 3
4 5
15228
RP : 3x5= 1515
MP : (2x5) + (3x4) =10+12=22MP : (2x5) + (3x4) =10+12=22
LP : (2x4)=8LP : (2x4)=8
Ans:Ans: 10351035
Note:Note: RP & MPRP & MP should have only one digit so extra digit is carried & added toshould have only one digit so extra digit is carried & added to LPLP
12
X

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3 4
4 4
162412
RP : 4x4= 1616
MP : (3x4) + (4x3) =12+12=24MP : (3x4) + (4x3) =12+12=24
LP : (3x4)=12LP : (3x4)=12
Ans:Ans: 14561456
Note:Note: RP & MPRP & MP should have only one digit so extra digit is carried & added toshould have only one digit so extra digit is carried & added to LPLP
12
X

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2
372
RP : 1 x 3= 3
MP : (2x3)+(1x1) = 6 + 1= 7MP : (2x3)+(1x1) = 6 + 1= 7
LP : (2x1)=2LP : (2x1)=2
Ans:Ans:
X
19 = 2 1
1
31
Convert Vinculum to Normal
& 7 = 1 3
11 3333

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4
12120
RP : 3 x 4= 12
MP : (4x4)+(3x5) =16+15=1MP : (4x4)+(3x5) =16+15=1
LP : (4x5)=20LP : (4x5)=20
Ans:Ans: 19981998
X
37 = 4 3
3
45
Convert Vinculum to Normal
= 2002

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4
2512
RP : 1 x 2= 2
MP : (4x2)+(1x3) = 8+3= 5MP : (4x2)+(1x3) = 8+3= 5
LP : (4x3)=12LP : (4x3)=12
Ans:Ans: 11481148
X
28 = 3 2
1
23
Convert Vinculum to Normal

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5
42420
RP : 1 x 4= 4
MP : (5x4)+(1x4) = 20+4= 2 4MP : (5x4)+(1x4) = 20+4= 2 4
LP : (5x4)=20LP : (5x4)=20
Ans:Ans: 17641764
X
49 = 5 1
1
44
Convert Vinculum to Normal
36 = 4 4
-2
=1 8 4 4

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4
62220
RP : 2 x 3= 6
MP : (4x3)+(2x5) = 12+10= 2 2MP : (4x3)+(2x5) = 12+10= 2 2
LP : (4x5)=20LP : (4x5)=20
Ans:Ans: 17861786
X
38 = 4 2
2
35
Convert Vinculum to Normal
47 = 5 3
-2
=1 8 2 6

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5
8215
RP : 4 x 2= 8
MP : (5x2)+(4x3) = 10+12= 2MP : (5x2)+(4x3) = 10+12= 2
LP : (5x3)= 15LP : (5x3)= 15
Ans:Ans: 14721472
X
46 = 5 4
4
23
Convert Vinculum to Normal
=1 5 2 8