Part A Imagine that you have a 5.50 L gas tank and a 2.00 L gas tank. You need to fill one tank with oxygen and the other with acetylene to use in conjunction with your welding torch. If you fil the larger tan k with oxygen to a pressure of 125 atm, to what pressure should you fill the acetylene tank to ensure that you run out of each gas at the same time? Assume ideal behavior for all gases Express your answer with the appropriate units. View Available Hint(s) atm Submit Previous Answers Incorrect Try Again Next> Provide Feedback Solution Acetylene torches are used for welding. These torches use a mixture of acetylene gas, C2H2, and oxygen gas, O2 to produce the following combustion reaction: 2C2H2{(g)} + 5O2{(g)} = 4CO2{(g)} + 2H2O{(g)} Now applying Ideal gas law PV = nRT n1 = P1V1/ R1T1 = n2 = P2V2/R2T2 n1O2 = (125atm * 5.50L) /RT The ratio between O2 to Acetylene is 2/5 nC2H2= (P2 * 2.0 L) / RT nO2 =(125atm * 5.50L) (2/5)/ RT = P2 * (2.0L) / RT Solve for P2 ( (RT cancels out) P2 = (125atm * 5.50L) (2/5) / (2.0L) P2 = 137.5atm .

1. Part A Imagine that you have a 5.50 L gas tank and a 2.00 L gas tank. You need to fill one tank
with oxygen and the other with acetylene to use in conjunction with your welding torch. If you
fil the larger tan k with oxygen to a pressure of 125 atm, to what pressure should you fill the
acetylene tank to ensure that you run out of each gas at the same time? Assume ideal behavior
for all gases Express your answer with the appropriate units. View Available Hint(s) atm Submit
Previous Answers Incorrect Try Again Next> Provide Feedback
Solution
Acetylene torches are used for welding. These torches use a mixture of acetylene gas, C2H2, and
oxygen gas, O2 to produce the following combustion reaction:
2C2H2{(g)} + 5O2{(g)} = 4CO2{(g)} + 2H2O{(g)}
Now applying Ideal gas law PV = nRT
n1 = P1V1/ R1T1 = n2 = P2V2/R2T2
n1O2 = (125atm * 5.50L) /RT
The ratio between O2 to Acetylene is 2/5
nC2H2= (P2 * 2.0 L) / RT
nO2 =(125atm * 5.50L) (2/5)/ RT = P2 * (2.0L) / RT
Solve for P2 ( (RT cancels out)
P2 = (125atm * 5.50L) (2/5) / (2.0L)
P2 = 137.5atm