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Chapter 3   Stoichiometry: Calculations with Chemical Formulas and Equations John D. Bookstaver St. Charles Community College Cottleville, MO Lecture Presentation
Law of Conservation of Mass ,[object Object],[object Object]
Chemical Equations ,[object Object]
Anatomy of a Chemical Equation ,[object Object]
Anatomy of a Chemical Equation ,[object Object],Reactants  appear on the left side of the equation.
Anatomy of a Chemical Equation ,[object Object],Products  appear on the right side of the equation.
Anatomy of a Chemical Equation ,[object Object],The  states  of the reactants and products are written in parentheses to the right of each compound.
Anatomy of a Chemical Equation ,[object Object],Coefficients  are inserted to balance the equation.
Subscripts and Coefficients Give Different Information ,[object Object],[object Object]
Reaction Types
Combination Reactions ,[object Object],[object Object],[object Object],[object Object],[object Object]
[object Object],Decomposition Reactions ,[object Object],[object Object],[object Object],[object Object]
Combustion Reactions ,[object Object],[object Object],[object Object],[object Object],[object Object]
Formula Weights
Formula Weight (FW) ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Molecular Weight (MW) ,[object Object],[object Object],C:  2(12.011 amu) 30.070 amu + H:  6(1.00794 amu)
Percent Composition ,[object Object],% Element = (number of atoms)(atomic weight) (FW of the compound) x 100
Percent Composition ,[object Object],%C = (2)(12.011 amu) (30.070 amu) 24.022 amu 30.070 amu = x 100 = 79.887%
Moles
Avogadro’s Number ,[object Object],[object Object]
Molar Mass ,[object Object],[object Object],[object Object]
Using Moles ,[object Object]
Mole Relationships ,[object Object],[object Object]
Finding Empirical Formulas
Calculating Empirical Formulas ,[object Object]
Calculating Empirical Formulas The compound  para -aminobenzoic acid (you may have seen it listed as PABA on your bottle of sunscreen) is composed of carbon (61.31%), hydrogen (5.14%), nitrogen (10.21%), and oxygen (23.33%).  Find the empirical formula of PABA.
Calculating Empirical Formulas Assuming 100.00 g of  para -aminobenzoic acid, C: 61.31 g x  = 5.105 mol C H:   5.14 g x = 5.09 mol H N: 10.21 g x = 0.7288 mol N O: 23.33 g x  = 1.456 mol O 1 mol 12.01 g 1 mol 14.01 g 1 mol 1.01 g 1 mol 16.00 g
Calculating Empirical Formulas Calculate the mole ratio by dividing by the smallest number of moles: C: = 7.005    7 H: = 6.984    7 N: = 1.000 O: = 2.001    2 5.105 mol 0.7288 mol 5.09  mol 0.7288 mol 0.7288 mol 0.7288 mol 1.458 mol 0.7288 mol
Calculating Empirical Formulas These are the subscripts for the empirical formula: C 7 H 7 NO 2
Combustion Analysis ,[object Object],[object Object],[object Object],[object Object]
Stoichiometric Calculations ,[object Object]
Stoichiometric Calculations ,[object Object]
Stoichiometric Calculations ,[object Object],[object Object],[object Object],[object Object],C 6 H 12 O 6  + 6 O 2     6 CO 2  + 6 H 2 O
Limiting Reactants
Limiting Reactants ,[object Object],[object Object]
Limiting Reactants ,[object Object]
Theoretical Yield ,[object Object],[object Object],[object Object]
Percent Yield ,[object Object],Percent yield = x 100 actual yield theoretical yield

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Blb12 ch03 lecture

  • 1. Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations John D. Bookstaver St. Charles Community College Cottleville, MO Lecture Presentation
  • 2.
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  • 19. Moles
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  • 26. Calculating Empirical Formulas The compound para -aminobenzoic acid (you may have seen it listed as PABA on your bottle of sunscreen) is composed of carbon (61.31%), hydrogen (5.14%), nitrogen (10.21%), and oxygen (23.33%). Find the empirical formula of PABA.
  • 27. Calculating Empirical Formulas Assuming 100.00 g of para -aminobenzoic acid, C: 61.31 g x = 5.105 mol C H: 5.14 g x = 5.09 mol H N: 10.21 g x = 0.7288 mol N O: 23.33 g x = 1.456 mol O 1 mol 12.01 g 1 mol 14.01 g 1 mol 1.01 g 1 mol 16.00 g
  • 28. Calculating Empirical Formulas Calculate the mole ratio by dividing by the smallest number of moles: C: = 7.005  7 H: = 6.984  7 N: = 1.000 O: = 2.001  2 5.105 mol 0.7288 mol 5.09 mol 0.7288 mol 0.7288 mol 0.7288 mol 1.458 mol 0.7288 mol
  • 29. Calculating Empirical Formulas These are the subscripts for the empirical formula: C 7 H 7 NO 2
  • 30.
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