1. A) Formation of carbocation
B) Unimolecular step
?C) Formation of alkyloxonium ion
Section 4.11 Orange 8' 8t RC 8.8 d' R*, H2O, Ch imolecular ROH, HCI bimolecular
bimolecular RCI, H2O Reaction Coordinate For question orange, input the step number that
corresponds to the description. Input either 1, 2 or 3. Click pause now.
Solution
Formation of carbocation : step 2
From the graph of the reaction, formation of carbocation occurs as the product of step 2 (Pink
Step). At the end of step 2, we can see the products as R +
(carbocation), H 2 O (water), Cl -
(chloride ion)
Unimolecular Step : step 2
It can be clearly seen from the graph that 2 nd
step (pink step) is the unimolecular step
Formation of alkyloxonium ion : step 1
From the graph of the reaction, formation of alkyloxonium ion occurs as the product of step 1
(blue step). At the end of step 1, we can see the products as ROH 2
+
(alkyloxonium ion) & Cl -
(chloride ion)