A) Formation of carbocation B) Unimolecular step ?C) Formation of alkyloxonium ion Section 4.11 Orange 8\' 8t RC 8.8 d\' R*, H2O, Ch imolecular ROH, HCI bimolecular bimolecular RCI, H2O Reaction Coordinate For question orange, input the step number that corresponds to the description. Input either 1, 2 or 3. Click pause now. Solution Formation of carbocation : step 2 From the graph of the reaction, formation of carbocation occurs as the product of step 2 (Pink Step). At the end of step 2, we can see the products as R + (carbocation), H 2 O (water), Cl - (chloride ion) Unimolecular Step : step 2 It can be clearly seen from the graph that 2 nd step (pink step) is the unimolecular step Formation of alkyloxonium ion : step 1 From the graph of the reaction, formation of alkyloxonium ion occurs as the product of step 1 (blue step). At the end of step 1, we can see the products as ROH 2 + (alkyloxonium ion) & Cl - (chloride ion) .