The base of a solid is the disk bounded by the circle x2+y2=r2. Find the volume of the solid given that the cross sections are perpendicular to the x-axis are equilateral triangles Solution The solid becomes a cone ... and it\'s volume = 1/3 * pi * r^2 * h since the crossection is equilateral triangle, h= sqrt(3)/2 * (2r) =sqrt(3) *r.

1. The base of a solid is the disk bounded by the circle x2+y2=r2. Find the volume of the solid
given that the cross sections are perpendicular to the x-axis are equilateral triangles
Solution
The solid becomes a cone ... and it's volume = 1/3 * pi * r^2 * h since the
crossection is equilateral triangle, h= sqrt(3)/2 * (2r) =sqrt(3) *r