for The system at the right has 8 mm diameter pins at the B and D their allowable shear stress is 100 Mpa , What is the allowable force P that can be safely held the system? Solution A = pi*d^2/4 = 3.14*8^2*10^-6/4 = 5.024*10^-5 m^2 stress = F/A ==> F = stress*A = 100*10^6*5.024*10^-5 = 5024 N.