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From your knowledge of the relationships among the various cost func.pdf
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FormulasSolutionHere are the answers 1. d = 7-2 = 5 .pdf
2. Apr 2023•0 gefällt mir•3 Aufrufe
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Formulas: Solution Here are the answers: 1. d = 7-2 = 5 2. a31 = -3+4(30) = 117 3. r = -1/2 4. a12 = 12(12-6) = 72 5. a4 = 1000(1/1000) = 1 6. since r =-3, so next term = 54 7. ar^6/a = r^6 = 11.4 => 0.2 8. -15 9. a(1/3)^4 = 1/108 => a = 3/4 10. r = -18/12 = -1.5 11. {Sum(n = 0to 4) }3*(4)^n 12. {Sum(n = 1to 6) }{7+(n-1)5) 13. S9 = 9/2 {2*4+8*8} = 324 14. S8 = 3(2^8-1)/1 = 765 15. S5 = 4(5)(5+1)/2 -3*5 = 45 { Using Sn = n(n+1)/2 for 1st n natural numberS) 16 S5 = 5(1*(3^5-1)/2= 605 17. S = 5*5 + 1/6(2+3+4+5+6) = 25+20/6 = 28.3 18. a200 = 1+199*4 = 797 19. 101 = 3 + (n-1)2 => n=50 , So, Sum = 50/2 (3+101) = 2600 20. Its a GP series with r = -1/3 , Sum = a/(1-r ) = 3/(1+1/3) = 4.5 ,.. Clearly it is convergent. Cheers !! gud luck!.
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FormulasSolutionHere are the answers 1. d = 7-2 = 5 .pdf
- Formulas: Solution Here are the answers: 1. d = 7-2 = 5 2. a31 = -3+4(30) = 117 3. r = -1/2 4. a12 = 12(12-6) = 72 5. a4 = 1000(1/1000) = 1 6. since r =-3, so next term = 54 7. ar^6/a = r^6 = 11.4 => 0.2 8. -15 9. a(1/3)^4 = 1/108 => a = 3/4 10. r = -18/12 = -1.5 11. {Sum(n = 0to 4) }3*(4)^n 12. {Sum(n = 1to 6) }{7+(n-1)5) 13. S9 = 9/2 {2*4+8*8} = 324 14. S8 = 3(2^8-1)/1 = 765 15. S5 = 4(5)(5+1)/2 -3*5 = 45 { Using Sn = n(n+1)/2 for 1st n natural numberS)
- 16 S5 = 5(1*(3^5-1)/2= 605 17. S = 5*5 + 1/6(2+3+4+5+6) = 25+20/6 = 28.3 18. a200 = 1+199*4 = 797 19. 101 = 3 + (n-1)2 => n=50 , So, Sum = 50/2 (3+101) = 2600 20. Its a GP series with r = -1/3 , Sum = a/(1-r ) = 3/(1+1/3) = 4.5 ,.. Clearly it is convergent. Cheers !! gud luck!
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