Give a reason why Sin2 ?+Cos2 ? =1 I have been able to prove the above but the reason I gave when I wrote Sin2 ?+Cos2 ? =1 Solution To prove that sin^2 theta +cos^2theta =1 Proof: Let theta = A, for A for the sake of typing friendliness. The geometrical definition of the sine of A is the ratio of the length opposite side of the angle A , to hypotenus of a right angled triangle whose angles are A, right angle and right angle -A . In the same right angled triangle cosine of A (or cos A) is the ratio adjascent side to the angle A to the hypotenus. So if ABC is a tringle with a right angle at B, then sineA = BC/AC and cosineA = AB/AC, by definition. Proof: Since the triangle is right angled, the Pythagorus theorem holds . Therefore, BC^2+AB^2=AC^2. Dividing both sides of the equatiob by AC^2, we get: BC^2+AB^2 = AC^2/AC^2 or sine ^2A+cosine^2A = 1 or (sineA)^2+(cosineA)^2 =1.This is a trigonometric identity. And and identity. So it holds for all values of A.So your doubt must be cleared as now it stands proved that (sineA)^2+(cosineA)^2 =1 is an identity..