A multinomial experiment was conducted with 4 cells and 400 trials. The results are shown in a table. This data needs to be tested to evaluate if it provides evidence against the null hypothesis that the probabilities of each cell are p1=0.2, p2=0.4, p3=0.1, and p4=0.3. The chi-square statistic needs to be calculated and compared to the critical value at an alpha of 0.05 to determine if the null hypothesis can be rejected.

1. A mulinomial experinent with k=4 cels and n=400 produoed the dirt shown in the one wry table
to the right. do these data provide sufflichent evidence to coritradid the mul thpothesis that
p1=0.2. p2=0.4. D3=0.1, and P4=0.3 ? Test, using a =0.05 Choose the corect null and whemative
hypotheses beiow A. H2:P1=022,p2=0.4,P2=0,14 and p4=0.3H1+P1=02,P2=0A1P3=0.1, and
P4=03 11. H0:D1=62.p2=0.4,p3=0.1, and p4=0.3 H.: N leat one of the proportiane diflers trom is
hypoltesized vulue C. H0:p1=0.2,p2=0.A1p3=0.1, and p4=0.3H3p1=0.25,p2=0.25,p3=0.25, and
p4=6.25 0. H0,P4=0.2,p2=0.4,py=0.1, and P4=0.3H4p4=0.p1p2=0.6,p2=0.9,andp4=0.7 Find the
value of the ohlsquare statote x2= (Round to tevee decimal places as needed.)