2) The content of PC in the basic computer is 1B0 (all numbers are in hexadecimal) and the initial value of E is 1. The content of AC is 701B. The content of memory at address 1B0 is 7080 . The content of memory at address 080 is 15AC. The content of memory at address 5AC is 7BFF. The content of memory at address BFF is 0000. [15 points] (a) List the sequence of micro-operations for the instruction cycle (fetch, decode, execute) of this instruction. [15 points] (b) Show the contents of the registers (PC, AR, DR, AC, IR, E, I, SC) after the positive transition of each clock pulse for each timing signal: [15 points] (c) If any memory location(s) contents change because of the execution of the above instruction, list them: [5 points].