d) 0.3333 show work thanks Solution A pair of fair dice is cast. What is the probabiliy that one of the numbers falling uppermost is a 5, given that the two numbers falling uppermost are different? possilbe conditions are: 5,1 and 5,2 and 5,3 and 5,4 and 5,6 1,5 and 2,5 and 3,5 and 4,5 and 6,5 total outcomes are (1,2)(..................(1,6) (2,1) (2,3)(2,4).......(2,6) (3,1)(3,2)(3,4).....(3,6) (4,1)(4,2)......(4,6) (5,1)........(5,6) (6,1)( 6,5) = 5 + 5 + 5 + 5 + 5 + 5 = 30 probabity = 10/30 = 0.33333333333333 d) 0.3333.

1. d) 0.3333
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Solution
A pair of fair dice is cast. What is the probabiliy that one of the numbers falling uppermost is a 5,
given that the two numbers falling uppermost are different?
possilbe conditions are:
5,1 and 5,2 and 5,3 and 5,4 and 5,6
1,5 and 2,5 and 3,5 and 4,5 and 6,5
total outcomes are
(1,2)(..................(1,6)
(2,1) (2,3)(2,4).......(2,6)
(3,1)(3,2)(3,4).....(3,6)
(4,1)(4,2)......(4,6)
(5,1)........(5,6)
(6,1)( 6,5)
= 5 + 5 + 5 + 5 + 5 + 5 = 30
probabity = 10/30 = 0.33333333333333
d) 0.3333