C1 The function FZ+Z+is defined recursively as follows F.pdf

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C.1. The function F:Z+Z+is defined recursively as follows: F(1)=1,F(2)=2, and F(n)=F(2n)+F(2n)1 for n3. (i) Calculate the value of F(9). (ii) Use strong induction to prove that F(n)n for every positive integer n. (Suggestion: Recall the inequalities for floor and ceiling functions in Table 1 in Section 2.3.).

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Can someone please help with this :) Now that you have completed the Punnete squaies you can ule this information to pecdict the Probability of specific outcomes in the F2, 2. Each of the four boxes represents a one in four (or 25% ) chance or probabilicy of a genorype. What is the genotypic ratio for this cross? 3. For each of the above genotypes, give the phenorype that would be expressod in the F2 generation. 4. What is the phenotypic ratio for this cross? SECTION 5: DIHYBRID CROSSES UP to this point, you have considered genetic crosses that involved a single trait controlled by 2 single gene (monohybrid cross). Mendel also made crosses that involved two genes, each located on a different pair of homologous chromosomes. This type of cross is called a dihybrid cross and illustrates Mendel's Law of Independent Assortment. Mendel demonstrated that when two traits are determined by genes located on two different chromosomes, each pair of alleles segregates independently of one another during gamete formation. The different possible allele combinations that result from meiosis are illustrated in Figure 8-3. Two equallv probable arranaements of chromosomes at metaphase l:Step 9: Phenotypic ratio of F2 Tongue roller, Taster Tongue roller, Non-taster Non-roller, Taster Non-roller, Non-taster.

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Can someone please help me complete the "add_song" function below. Thank you! // Each song has this information: song's id, song's name, singer's name, genre of the song, and its published year. // The struct 'musicRepository' holds information of one song. Genre is enum type. // An array of structs called 'list' is made to hold the list of songs. // You should not modify any of the given code, the return types, or the parameters, you will risk of getting compilation error. // You are not allowed to modify main (). // You can use string library functions. #include <stdio.h> #include <stdlib.h> #include <string.h> #pragma warning(disable : 4996) // for Visual Studio Only #define MAX_SONGS 20 #define MAX_SONG_NAME_LENGTH 40 #define MAX_SINGER_NAME_LENGTH 40 typedef enum { unclassified = 0, Pop, Rock, Reggae, Country, Blues, Balad, } genreType; // enum type struct musicRepository { // struct for song details unsigned int ID; char songName[MAX_SONG_NAME_LENGTH]; char singerName[MAX_SINGER_NAME_LENGTH]; genreType genre; unsigned int year; }; struct musicRepository list[MAX_SONGS]; // declare the list of songs int numSongs = 0; // the number of songs currently stored in the list (initialized to 0) // This function takes in an array of musicRepository structures and the size of the array as parameters. It then loops through each index of the array and sets the values of id, year, genre, name, and singer to their respective initial values. // NOTE that strcpy is used to copy an empty string to name and singer, rather than setting them equal to "". This is because arrays in C are not assignable, so the strcpy function must be used to copy the empty string into the array. void initializeRepository(struct musicRepository repo[], int size) { for (int i = 0; i < size; i++) { repo[i].ID = 0; repo[i].year = 0; repo[i].genre = 0; strcpy(repo[i].songName, ""); strcpy(repo[i].singerName, ""); } } // This function takes in the musicRepository array and iterates through each element. If the ID of the song is not 0, it prints the details of the song. void printRepository(struct musicRepository repo[], int numSongs) { printf("n--- Song Repository ---n"); for (int i = 0; i < numSongs; i++) { if (repo[i].ID != 0) { printf("ID: %dn", repo[i].ID); printf("Name: %sn", repo[i].songName); printf("Singer: %sn", repo[i].singerName); if (repo[i].genre == 0) printf("Genre: unclassifiedn"); else if (repo[i].genre == 1) printf("Genre: Popn"); else if (repo[i].genre == 2) printf("Genre: Rockn"); else if (repo[i].genre == 3) printf("Genre: Reggaen"); else if (repo[i].genre == 4) printf("Genre: Countryn"); else if (repo[i].genre == 5) printf("Genre: Bluesn"); else if (repo[i].genre == 6) printf("Genre: Baladn"); printf("Year: %dn", repo[i].year); printf("n"); } } } // Problem 2 // struct to hold information about a song struct Song { int id; char name[MAX_SONG_NAME_LENGTH]; char singer[MAX_SINGER_NAME_LENGTH]; genreType genre; int year; struct Song* next; }; // Function declarati.

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can someone please assist me with analysis of this case atudy VAKRANGEE: ANATOMY OF STOCK VALUATION 1 Poga Gupti and Zahid Jamar wrote this case solby to provide matorial for chas discussion. The authors do not intond to iflustrate either oflective or innflloctive handing of a managonial sihution. The authors may have disguised certain names and other idantifying information to protect confidentilith. This publication may not be transmitted, pholocopied, digitinod, or othorwise reproduced in any form or by any moans without the pormissian of the copynight holder. Reproduction of this material is not covered under autherization by any reproduction rights organization. To arder copies or nequest pemission to reproduce materials, contact Ney Pubbishing. Avey Business School, Westem Cogyright 92020, Ney Business School Foundation Vorsion: 20200703 On April 20, 2018, Priyankar Khandelwal was furious as he watched the stock value from his fund seemingly evaporate right in front of his eyes. Khandelwal, the fund manager at Principal First, had been managing the mid-sized information technology (IT) fund for the previous five years. Khandelwal asked his assistant to put in a sell order to cover his long position 2 in Vakrangee Limited (Vakrangee) at a substantial loss. He had bought the stock in the beginning of October 2017. The stock hit a high in Jamuary 2018 but had subsequently been sliding (see Exhibit 1). In his fund, Khandelwal had allocated a substantial amount to Vakrangee in the initial investment. Based on the current market price of the stock, there was a net loss of 169 million 3 and a loss of 592 million unrealized from the top for the fund. 4 This loss caused the net asset value of the fund to fall by 35 per cent year to date, because Khandelwal had not hedged his position. Khandelwal's clients were irate, and more than 25 per cent of his firm's investors had withdrawn their money from the fund. Principal First had also reprimanded him and put him on notice. Khandelwal wondered where he went wrong in his analysis of Vakrangee. He had done the valuation exercise himself, checked and cross-checked his assumptions, looked at industry and credit reports, and had found it to be a good stock with good future prospects. What had he missed? What could he have done better? PRINCIPAL FIRST Principal First was a Mumbai-based boutique investment management and investment advisory firm. The investment objective of the firm was to deliver notable risk-adjusted retums consistently while ensuring capital preservation. The firm was founded in 2005 and had been an carly investor in the Indian alternative 'This case was awarded an honourable mention in the the ISB-lvey Global Case Compettion 2018. The prize was sponsored by ISB. 2 A long position was the buying of a stock, commodity, or currency with the expectation that it (would] rise in value; "Long Position (Long)," Investopedia, March 20, 2020, accessed April 6, 2010, www. investopedia.com/terms/Vi.

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