Solve for xlog 4 x 3 - log 2 xSolutionTo solve for x. log .pdf
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Solve the following for x x^(-43) - 1 = 15.SolutionWe have .pdfSolve the following for x x^(-43) - 1 = 15.SolutionWe have .pdf
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Solve for xlog 4 x 3 - log 2 xSolutionTo solve for x. log .pdf

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Solve for x log 4 x > 3 - log 2 x Solution To solve for x. log 4x > 3- log2x. Log ab = loga +logb; log a/b = loga-logb; log a^m = m loga. So the given equation becomes: log4+logx > 3- (log2+logx) log4 +logx > 3 -log2 -logx. logx+logx > 3 -log2 - log4 2logx > 3 - (log2+log4) = 3 -log4 = log10^3 - log4 2logx> log(10^3/8) logx^2> log(10^3/8) . Take antilog. x^2> 10^3/8 x> sqrt(10^3/8) = sqrt(125) x > 5sqrt5..

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Solve for xlog 4 x 3 - log 2 xSolutionTo solve for x. log .pdf

  1. Solve for x log 4 x > 3 - log 2 x Solution To solve for x. log 4x > 3- log2x. Log ab = loga +logb; log a/b = loga-logb; log a^m = m loga. So the given equation becomes: log4+logx > 3- (log2+logx) log4 +logx > 3 -log2 -logx. logx+logx > 3 -log2 - log4 2logx > 3 - (log2+log4) = 3 -log4 = log10^3 - log4 2logx> log(10^3/8) logx^2> log(10^3/8) . Take antilog. x^2> 10^3/8 x> sqrt(10^3/8) = sqrt(125) x > 5sqrt5.