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a. I release the ball at the 2 m mark. How much PE, KE, and total en.pdf

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24. Mar 2023••
a. I release the ball at the 2 m mark. How much PE, KE, and total en.pdf
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a. I release the ball at the 2 m mark. How much PE, KE, and total en.pdf

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a. I release the ball at the 2 m mark. How much PE, KE, and total energy does it have there? b. Where is the total energy line, how many joules? Where does the object stop? c. How much kinetic energy does the object have as it passes 10 m? d. How much potential energy does the object have as it 13 m? e. At what point does the object have the most kinetic energy? Solution a) PE = 5J KE = 0 TE = 5J b) 5J is total energy line and ball stops at 17m c) KE = TE - PE at 10 m PE = 1J KE = 4J d) at 13m PE = 2J e) max kinetic energy means min potential energy at 11 m.

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a. I release the ball at the 2 m mark. How much PE, KE, and total en.pdf

  1. a. I release the ball at the 2 m mark. How much PE, KE, and total energy does it have there? b. Where is the total energy line, how many joules? Where does the object stop? c. How much kinetic energy does the object have as it passes 10 m? d. How much potential energy does the object have as it 13 m? e. At what point does the object have the most kinetic energy? Solution a) PE = 5J KE = 0 TE = 5J b) 5J is total energy line and ball stops at 17m c) KE = TE - PE at 10 m PE = 1J KE = 4J d) at 13m PE = 2J e) max kinetic energy means min potential energy at 11 m
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