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12834316.ppt
1.
1 Slide © 2018 Cengage
Learning. All Rights Reserved. Probability is a numerical measure of the likelihood that an event will occur. Probability values are always assigned on a scale from 0 to 1. A probability near zero indicates an event is quite unlikely to occur. A probability near one indicates an event is almost certain to occur. Chapter 4 - Introduction to Probability
2.
2 Slide © 2018 Cengage
Learning. All Rights Reserved. Probability as a Numerical Measure of the Likelihood of Occurrence 0 1 .5 Increasing Likelihood of Occurrence Probability: The event is very unlikely to occur. The occurrence of the event is just as likely as it is unlikely. The event is almost certain to occur.
3.
3 Slide © 2018 Cengage
Learning. All Rights Reserved. Statistical Experiments In statistics, the notion of an experiment differs somewhat from that of an experiment in the physical sciences. In statistical experiments, probability determines outcomes. Even though the experiment is repeated in exactly the same way, an entirely different outcome may occur. For this reason, statistical experiments are some- times called random experiments.
4.
4 Slide © 2018 Cengage
Learning. All Rights Reserved. An Experiment and Its Sample Space An experiment is any process that generates well- defined outcomes. The sample space for an experiment is the set of all experimental outcomes. An experimental outcome is also called a sample point.
5.
5 Slide © 2018 Cengage
Learning. All Rights Reserved. An event is a collection of sample points. The probability of any event is equal to the sum of the probabilities of the sample points in the event. If we can identify all the sample points of an experiment and assign a probability to each, we can compute the probability of an event. Events and Their Probabilities
6.
6 Slide © 2018 Cengage
Learning. All Rights Reserved. An Experiment and Its Sample Space Experiment Toss a coin Inspection of a part Conduct a sales call Roll a die Play a football game Experiment Outcomes Head, tail Defective, non-defective Purchase, no purchase 1, 2, 3, 4, 5, 6 Win, lose, tie
7.
7 Slide © 2018 Cengage
Learning. All Rights Reserved. An Experiment and Its Sample Space Example: Kentucky Power and Light Company (KP&L) KP&L has designed a project to increase the generating capacity of one of its plants. The project is divided into two sequential stages : Stage 1 – Design; Stage 2 – Construction. The possible completion times of these stages are as follows: Possible completion time in months Design Stage Construction Stage 2 6 3 7 4 8
8.
8 Slide © 2018 Cengage
Learning. All Rights Reserved. A Counting Rule for Multiple-Step Experiments If an experiment consists of a sequence of k steps in which there are n1 possible results for the first step, n2 possible results for the second step, and so on, then the total number of experimental outcomes is given by (n1)(n2) . . . (nk). A helpful graphical representation of a multiple-step experiment is a tree diagram.
9.
9 Slide © 2018 Cengage
Learning. All Rights Reserved. A Counting Rule for Multiple-Step Experiments Example: Kentucky Power and Light Company (KP&L) (KP&L) expansion project can be viewed as a two-step experiment. It involves two stages each of which have three possible completion times. Design stage n1 = 3 Construction stage n2 = 3 Total Number of Experimental Outcomes: n1n2 = (3)(3) = 9
10.
10 Slide © 2018 Cengage
Learning. All Rights Reserved. Tree Diagram Example: Kentucky Power and Light Company (KP&L)
11.
11 Slide © 2018 Cengage
Learning. All Rights Reserved. Counting Rule for Combinations
12.
12 Slide © 2018 Cengage
Learning. All Rights Reserved. Counting Rule for Permutations
13.
13 Slide © 2018 Cengage
Learning. All Rights Reserved. Assigning Probabilities Basic Requirements for Assigning Probabilities 1. The probability assigned to each experimental outcome must be between 0 and 1, inclusively. 0 < P(Ei) < 1 for all i where: Ei is the ith experimental outcome P(Ei) is its probability 2. The sum of the probabilities for all experimental outcomes must equal 1. P(E1) + P(E2) + . . . + P(En) = 1 where: n is the number of experimental outcomes
14.
14 Slide © 2018 Cengage
Learning. All Rights Reserved. Assigning Probabilities Classical Method Relative Frequency Method Subjective Method Assigning probabilities based on the assumption of equally likely outcomes Assigning probabilities based on experimentation or historical data Assigning probabilities based on judgment
15.
15 Slide © 2018 Cengage
Learning. All Rights Reserved. Classical Method If an experiment has n possible outcomes, the classical method would assign a probability of 1/n to each outcome. Experiment: Rolling a die Sample Space: S = {1, 2, 3, 4, 5, 6} Probabilities: Each sample point has a 1/6 chance of occurring Example: Rolling a Die
16.
16 Slide © 2018 Cengage
Learning. All Rights Reserved. Relative Frequency Method • Lucas Tool Rental would like to assign probabilities to the number of car polishers it rents each day and office records show the following frequencies of daily rentals for the last 40 days. • Each probability assignment is given by dividing the frequency (number of days) by the total frequency (total number of days). 4/40 Probability Number of Polishers Rented Number of Days 0 1 2 3 4 4 6 18 10 2 40 .10 .15 .45 .25 .05 1.00 Example: Lucas Tool Rental
17.
17 Slide © 2018 Cengage
Learning. All Rights Reserved. Subjective Method When economic conditions or a company’s circumstances change rapidly it might be inappropriate to assign probabilities based solely on historical data. We can use any data available as well as our experience and intuition, but ultimately a probability value should express our degree of belief that the experimental outcome will occur. The best probability estimates often are obtained by combining the estimates from the classical or relative frequency approach with the subjective estimate.
18.
18 Slide © 2018 Cengage
Learning. All Rights Reserved. Some Basic Relationships of Probability There are some basic probability relationships that can be used to compute the probability of an event without knowledge of all the sample point probabilities. Complement of an Event Intersection of Two Events Mutually Exclusive Events Union of Two Events
19.
19 Slide © 2018 Cengage
Learning. All Rights Reserved. The complement of A is denoted by Ac . The complement of event A is defined to be the event consisting of all sample points that are not in A. Complement of an Event Event A Ac Sample Space S Venn Diagram
20.
20 Slide © 2018 Cengage
Learning. All Rights Reserved. The union of events A and B is denoted by A B The union of events A and B is the event containing all sample points that are in A or B or both. Union of Two Events Sample Space S Event A Event B
21.
21 Slide © 2018 Cengage
Learning. All Rights Reserved. The intersection of events A and B is denoted by A The intersection of events A and B is the set of all sample points that are in both A and B. Sample Space S Event A Event B Intersection of Two Events Intersection of A and B
22.
22 Slide © 2018 Cengage
Learning. All Rights Reserved. Bradley has invested in two stocks, Markley Oil and Collins Mining. Bradley has determined that the possible outcomes of these investments three months from now are as follows. Investment Gain or Loss in 3 Months (in $000) Markley Oil Collins Mining 10 5 0 -20 8 -2 Example: Bradley Investments An Experiment and Its Sample Space
23.
23 Slide © 2018 Cengage
Learning. All Rights Reserved. Tree Diagram Gain 5 Gain 8 Gain 8 Gain 10 Gain 8 Gain 8 Lose 20 Lose 2 Lose 2 Lose 2 Lose 2 Even Markley Oil (Stage 1) Collins Mining (Stage 2) Experimental Outcomes (10, 8) Gain $18,000 (10, -2) Gain $8,000 (5, 8) Gain $13,000 (5, -2) Gain $3,000 (0, 8) Gain $8,000 (0, -2) Lose $2,000 (-20, 8) Lose $12,000 (-20, -2) Lose $22,000 Example: Bradley Investments
24.
24 Slide © 2018 Cengage
Learning. All Rights Reserved. Subjective Method An analyst made the following probability estimates. Exper. Outcome Net Gain or Loss Probability (10, 8) (10, -2) (5, 8) (5, -2) (0, 8) (0, -2) (-20, 8) (-20, -2) $18,000 Gain $8,000 Gain $13,000 Gain $3,000 Gain $8,000 Gain $2,000 Loss $12,000 Loss $22,000 Loss .20 .08 .16 .26 .10 .12 .02 .06 Example: Bradley Investments
25.
25 Slide © 2018 Cengage
Learning. All Rights Reserved. Events and Their Probabilities Event M = Markley Oil Profitable M = {(10, 8), (10, -2), (5, 8), (5, -2)} P(M) = P(10, 8) + P(10, -2) + P(5, 8) + P(5, -2) = .20 + .08 + .16 + .26 = .70 Example: Bradley Investments Event C = Collins Mining Profitable C = {(10, 8), (5, 8), (0, 8), (-20, 8)} P(C) = P(10, 8) + P(5, 8) + P(0, 8) + P(-20, 8) = .20 + .16 + .10 + .02 = 0.48
26.
26 Slide © 2018 Cengage
Learning. All Rights Reserved. Union of Two Events Event M = Markley Oil Profitable Event C = Collins Mining Profitable M C = Markley Oil Profitable or Collins Mining Profitable (or both) M C = {(10, 8), (10, -2), (5, 8), (5, -2), (0, 8), (-20, 8)} P(M C) = P(10, 8) + P(10, -2) + P(5, 8) + P(5, -2) + P(0, 8) + P(-20, 8) = .20 + .08 + .16 + .26 + .10 + .02 = .82 Example: Bradley Investments
27.
27 Slide © 2018 Cengage
Learning. All Rights Reserved. Intersection of Two Events Event M = Markley Oil Profitable Event C = Collins Mining Profitable M C = Markley Oil Profitable and Collins Mining Profitable M C = {(10, 8), (5, 8)} P(M C) = P(10, 8) + P(5, 8) = .20 + .16 = .36 Example: Bradley Investments
28.
28 Slide © 2018 Cengage
Learning. All Rights Reserved. The addition law provides a way to compute the probability of event A, or B, or both A and B occurring. Addition Law The law is written as: P(A B) = P(A) + P(B) - P(A B
29.
29 Slide © 2018 Cengage
Learning. All Rights Reserved. Event M = Markley Oil Profitable Event C = Collins Mining Profitable M C = Markley Oil Profitable or Collins Mining Profitable We know: P(M) = .70, P(C) = .48, P(M C) = .36 Thus: P(M C) = P(M) + P(C) - P(M C) = .70 + .48 - .36 = .82 Addition Law (This result is the same as that obtained earlier using the definition of the probability of an event.) Example: Bradley Investments
30.
30 Slide © 2018 Cengage
Learning. All Rights Reserved. Events and Their Probabilities (Another Example) Example: Kentucky Power and Light Company (KP&L) We have completion results for 40 KP&L projects. Completion time in months Design Construction Sample Point Number of past projects with this completion time Probability 2 6 (2,6) 6 0.15 2 7 (2,7) 6 0.15 2 8 (2,8) 2 0.05 3 6 (2,6) 4 0.10 3 7 (2,7) 8 0.20 3 8 (2,8) 2 0.05 4 6 (2,6) 2 0.05 4 7 (2,7) 4 0.10 4 8 (2,8) 6 0.15
31.
31 Slide © 2018 Cengage
Learning. All Rights Reserved. Events and Their Probabilities Example: Kentucky Power and Light Company (KP&L) Event C = Project will take 10 months or less to complete C = { (2,6), (2,7), (2,8), (3,6) , (3,7), (4,6)} P (C )= { P(2,6) + P (2,7) + P (2,8) + P (3,6) +P (3,7) +P (4,6)} P(C) = 0.15 + 0.15 + 0.05 + 0.10 + 0.20 + 0.05 = 0.7
32.
32 Slide © 2018 Cengage
Learning. All Rights Reserved. Events and Their Probabilities Example: Kentucky Power and Light Company (KP&L) Event L = Project will take less than 10 months to complete C = { (2,6), (2,7), (3,6)} P (C )= { P(2,6) + P (2,7) + P (3,6)} P(C) = 0.15 + 0.15 + 0.10 = 0.4
33.
33 Slide © 2018 Cengage
Learning. All Rights Reserved. Mutually Exclusive Events Two events are said to be mutually exclusive if the events have no sample points in common. Two events are mutually exclusive if, when one event occurs, the other cannot occur. Sample Space S Event A Event B
34.
34 Slide © 2018 Cengage
Learning. All Rights Reserved. Mutually Exclusive Events If events A and B are mutually exclusive, P(A B = 0. The addition law for mutually exclusive events is: P(A B) = P(A) + P(B) There is no need to include “- P(A B”
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Learning. All Rights Reserved. The probability of an event given that another event has occurred is called a conditional probability. A conditional probability is computed as follows : The conditional probability of A given B is denoted by P(A|B). Conditional Probability ( ) ( | ) ( ) P A B P A B P B
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Learning. All Rights Reserved. Event M = Markley Oil Profitable Event C = Collins Mining Profitable We know: P(M C) = .36, P(M) = .70 Thus: Conditional Probability ( ) .36 ( | ) .5143 ( ) .70 P C M P C M P M = Collins Mining Profitable given Markley Oil Profitable ( | ) P C M Example: Bradley Investments
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Learning. All Rights Reserved. Conditional Probability – Another Example Example: Promotion status of police officers over the past two years Men Women Total Promoted 288 36 324 Not Promoted 672 204 876 Total 960 240 1200
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Learning. All Rights Reserved. Conditional Probability Example: Promotion status of police officers over the past two years Probability Table Men (M) Women (W) Total Promoted (A) 288/1200 = 0.24 0.03 0.27 Not Promoted (Ac ) 0.56 0.17 0.73 Total 0.80 0.20 1.00
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Learning. All Rights Reserved. Conditional Probability
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Learning. All Rights Reserved. Multiplication Law The multiplication law provides a way to compute the probability of the intersection of two events. The law is written as: P(A B) = P(A)P(B|A) or P(A B) = P(B)P(A|B)
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Learning. All Rights Reserved. Event M = Markley Oil Profitable Event C = Collins Mining Profitable We know: P(M) = .70, P(C|M) = .5143 Multiplication Law M C = Markley Oil Profitable and Collins Mining Profitable Thus: P(M C) = P(M)P(C|M) = (.70)(.5143) = .36 (This result is the same as that obtained earlier using the definition of the probability of an event.) Example: Bradley Investments
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Learning. All Rights Reserved. Joint Probability Table 1 Collins Mining Profitable (C) Not Profitable (Cc) Markley Oil Profitable (M) Not Profitable (Mc) Total .48 .52 Total .70 .30 1.00 .36 .34 .12 .18 Joint Probabilities (appear in the body of the table) Marginal Probabilities (appear in the margins of the table)
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Learning. All Rights Reserved. Joint Probability Table 2 (as we saw before
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Learning. All Rights Reserved. Independent Events If the probability of event A is not changed by the existence of event B, we would say that events A and B are independent. Two events A and B are independent if: P(A|B) = P(A) P(B|A) = P(B) or
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Learning. All Rights Reserved. The multiplication law also can be used as a test to see if two events are independent. The law is written as: P(A B) = P(A)P(B) Multiplication Law for Independent Events
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Learning. All Rights Reserved. Event M = Markley Oil Profitable Event C = Collins Mining Profitable We know: P(M C) = .36, P(M) = .70, P(C) = .48 But: P(M)P(C) = (.70)(.48) = .34, not .36 Are events M and C independent? Does P(M C) = P(M)P(C) ? Hence: M and C are not independent. Example: Bradley Investments Multiplication Law for Independent Events
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Learning. All Rights Reserved. Multiplication Law for Independent Events Example : Use of credit card for purchase of gasoline From past experience it is known 80% of customers use credit card for the purchase of gasoline. The service station manger wants to determine the probability that the next two customers purchasing gasoline will each use a credit card. Event A: First customer uses a credit card Event B: The second customer uses a credit card P(A B) = P(A)P(B) = (0.8) (0.8) = 0.64
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Learning. All Rights Reserved. Do not confuse the notion of mutually exclusive events with that of independent events. Two events with nonzero probabilities cannot be both mutually exclusive and independent. If one mutually exclusive event is known to occur, the other cannot occur.; thus, the probability of the other event occurring is reduced to zero (and they are therefore dependent). Mutual Exclusiveness and Independence Two events that are not mutually exclusive, might or might not be independent.
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