7. •Power Factor (P.F)=
𝐴𝑐𝑡𝑖𝑣𝑒 𝑃𝑜𝑤𝑒𝑟 (𝑊)
𝐴𝑝𝑝𝑎𝑟𝑒𝑛𝑡 𝑃𝑜𝑤𝑒𝑟 (𝑉𝐴)
•VA = √(𝑊2
+ 𝑉𝐴𝑅2
)
•When VAR ↑, P.F ↓
•Large Motor Produce high VAR and result with
LOWER P.F
•When P.F < 0.85 Utility Supply will give Penalty
because they need to supply more reactive power
(VAR) → Higher Utility Bill
8. SO HOW TO IMPROVE POWER FACTOR TO
PREVENT PENALTY FROM UTILITY SUPPLIER ?????
10. • P.F = 0.8
• We want to improve into 0.85 so there will be no penalty from utility
bill
ACTIVE POWER
REACTIVE POWER
(INDUCTIVE)
APPARENT POWER
POWER FACTOR ANGLE
POWER FACTOR : cos =kW / KVA
(kVAR)
(kVA)
(kW)
Reverse Engineering
P.F = 0.85
𝑃. 𝐹 =
𝑊
√(𝑊2 + 𝑉𝐴𝑅2)
With Watt Constant
0.85 =
8
√(82 + 𝑉𝐴𝑅2)
VAR = 4.95